(0) Obligation:
Clauses:
p(X, g(X)).
p(X, f(Y)) :- p(X, g(Y)).
Queries:
p(g,a).
(1) PrologToPrologProblemTransformerProof (SOUND transformation)
Built Prolog problem from termination graph.
(2) Obligation:
Clauses:
p1(T4, g(T4)).
p1(T14, f(T14)).
p1(T25, f(T25)).
Queries:
p1(g,a).
(3) PrologToPiTRSProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
p1_in_ga(T4, g(T4)) → p1_out_ga(T4, g(T4))
p1_in_ga(T14, f(T14)) → p1_out_ga(T14, f(T14))
The argument filtering Pi contains the following mapping:
p1_in_ga(
x1,
x2) =
p1_in_ga(
x1)
p1_out_ga(
x1,
x2) =
p1_out_ga(
x2)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(4) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
p1_in_ga(T4, g(T4)) → p1_out_ga(T4, g(T4))
p1_in_ga(T14, f(T14)) → p1_out_ga(T14, f(T14))
The argument filtering Pi contains the following mapping:
p1_in_ga(
x1,
x2) =
p1_in_ga(
x1)
p1_out_ga(
x1,
x2) =
p1_out_ga(
x2)
(5) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
P is empty.
The TRS R consists of the following rules:
p1_in_ga(T4, g(T4)) → p1_out_ga(T4, g(T4))
p1_in_ga(T14, f(T14)) → p1_out_ga(T14, f(T14))
The argument filtering Pi contains the following mapping:
p1_in_ga(
x1,
x2) =
p1_in_ga(
x1)
p1_out_ga(
x1,
x2) =
p1_out_ga(
x2)
We have to consider all (P,R,Pi)-chains
(6) Obligation:
Pi DP problem:
P is empty.
The TRS R consists of the following rules:
p1_in_ga(T4, g(T4)) → p1_out_ga(T4, g(T4))
p1_in_ga(T14, f(T14)) → p1_out_ga(T14, f(T14))
The argument filtering Pi contains the following mapping:
p1_in_ga(
x1,
x2) =
p1_in_ga(
x1)
p1_out_ga(
x1,
x2) =
p1_out_ga(
x2)
We have to consider all (P,R,Pi)-chains
(7) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,R,Pi) chain.
(8) YES