(0) Obligation:

Clauses:

p(X, Y).
map(.(X, Xs), .(Y, Ys)) :- ','(p(X, Y), map(Xs, Ys)).
map([], []).

Queries:

map(g,a).

(1) PrologToPrologProblemTransformerProof (SOUND transformation)

Built Prolog problem from termination graph.

(2) Obligation:

Clauses:

map1(.(T31, T8), .(T32, T33)) :- map1(T8, T33).
map1([], []).

Queries:

map1(g,a).

(3) PrologToPiTRSProof (SOUND transformation)

We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
map1_in: (b,f)
Transforming Prolog into the following Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:

map1_in_ga(.(T31, T8), .(T32, T33)) → U1_ga(T31, T8, T32, T33, map1_in_ga(T8, T33))
map1_in_ga([], []) → map1_out_ga([], [])
U1_ga(T31, T8, T32, T33, map1_out_ga(T8, T33)) → map1_out_ga(.(T31, T8), .(T32, T33))

The argument filtering Pi contains the following mapping:
map1_in_ga(x1, x2)  =  map1_in_ga(x1)
.(x1, x2)  =  .(x2)
U1_ga(x1, x2, x3, x4, x5)  =  U1_ga(x5)
[]  =  []
map1_out_ga(x1, x2)  =  map1_out_ga(x2)

Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog

(4) Obligation:

Pi-finite rewrite system:
The TRS R consists of the following rules:

map1_in_ga(.(T31, T8), .(T32, T33)) → U1_ga(T31, T8, T32, T33, map1_in_ga(T8, T33))
map1_in_ga([], []) → map1_out_ga([], [])
U1_ga(T31, T8, T32, T33, map1_out_ga(T8, T33)) → map1_out_ga(.(T31, T8), .(T32, T33))

The argument filtering Pi contains the following mapping:
map1_in_ga(x1, x2)  =  map1_in_ga(x1)
.(x1, x2)  =  .(x2)
U1_ga(x1, x2, x3, x4, x5)  =  U1_ga(x5)
[]  =  []
map1_out_ga(x1, x2)  =  map1_out_ga(x2)

(5) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:

MAP1_IN_GA(.(T31, T8), .(T32, T33)) → U1_GA(T31, T8, T32, T33, map1_in_ga(T8, T33))
MAP1_IN_GA(.(T31, T8), .(T32, T33)) → MAP1_IN_GA(T8, T33)

The TRS R consists of the following rules:

map1_in_ga(.(T31, T8), .(T32, T33)) → U1_ga(T31, T8, T32, T33, map1_in_ga(T8, T33))
map1_in_ga([], []) → map1_out_ga([], [])
U1_ga(T31, T8, T32, T33, map1_out_ga(T8, T33)) → map1_out_ga(.(T31, T8), .(T32, T33))

The argument filtering Pi contains the following mapping:
map1_in_ga(x1, x2)  =  map1_in_ga(x1)
.(x1, x2)  =  .(x2)
U1_ga(x1, x2, x3, x4, x5)  =  U1_ga(x5)
[]  =  []
map1_out_ga(x1, x2)  =  map1_out_ga(x2)
MAP1_IN_GA(x1, x2)  =  MAP1_IN_GA(x1)
U1_GA(x1, x2, x3, x4, x5)  =  U1_GA(x5)

We have to consider all (P,R,Pi)-chains

(6) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

MAP1_IN_GA(.(T31, T8), .(T32, T33)) → U1_GA(T31, T8, T32, T33, map1_in_ga(T8, T33))
MAP1_IN_GA(.(T31, T8), .(T32, T33)) → MAP1_IN_GA(T8, T33)

The TRS R consists of the following rules:

map1_in_ga(.(T31, T8), .(T32, T33)) → U1_ga(T31, T8, T32, T33, map1_in_ga(T8, T33))
map1_in_ga([], []) → map1_out_ga([], [])
U1_ga(T31, T8, T32, T33, map1_out_ga(T8, T33)) → map1_out_ga(.(T31, T8), .(T32, T33))

The argument filtering Pi contains the following mapping:
map1_in_ga(x1, x2)  =  map1_in_ga(x1)
.(x1, x2)  =  .(x2)
U1_ga(x1, x2, x3, x4, x5)  =  U1_ga(x5)
[]  =  []
map1_out_ga(x1, x2)  =  map1_out_ga(x2)
MAP1_IN_GA(x1, x2)  =  MAP1_IN_GA(x1)
U1_GA(x1, x2, x3, x4, x5)  =  U1_GA(x5)

We have to consider all (P,R,Pi)-chains

(7) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 1 less node.

(8) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

MAP1_IN_GA(.(T31, T8), .(T32, T33)) → MAP1_IN_GA(T8, T33)

The TRS R consists of the following rules:

map1_in_ga(.(T31, T8), .(T32, T33)) → U1_ga(T31, T8, T32, T33, map1_in_ga(T8, T33))
map1_in_ga([], []) → map1_out_ga([], [])
U1_ga(T31, T8, T32, T33, map1_out_ga(T8, T33)) → map1_out_ga(.(T31, T8), .(T32, T33))

The argument filtering Pi contains the following mapping:
map1_in_ga(x1, x2)  =  map1_in_ga(x1)
.(x1, x2)  =  .(x2)
U1_ga(x1, x2, x3, x4, x5)  =  U1_ga(x5)
[]  =  []
map1_out_ga(x1, x2)  =  map1_out_ga(x2)
MAP1_IN_GA(x1, x2)  =  MAP1_IN_GA(x1)

We have to consider all (P,R,Pi)-chains

(9) UsableRulesProof (EQUIVALENT transformation)

For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.

(10) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

MAP1_IN_GA(.(T31, T8), .(T32, T33)) → MAP1_IN_GA(T8, T33)

R is empty.
The argument filtering Pi contains the following mapping:
.(x1, x2)  =  .(x2)
MAP1_IN_GA(x1, x2)  =  MAP1_IN_GA(x1)

We have to consider all (P,R,Pi)-chains

(11) PiDPToQDPProof (SOUND transformation)

Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.

(12) Obligation:

Q DP problem:
The TRS P consists of the following rules:

MAP1_IN_GA(.(T8)) → MAP1_IN_GA(T8)

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.

(13) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • MAP1_IN_GA(.(T8)) → MAP1_IN_GA(T8)
    The graph contains the following edges 1 > 1

(14) YES