(0) Obligation:
Clauses:
suffix(Xs, Ys) :- app(X1, Xs, Ys).
app([], X, X).
app(.(X, Xs), Ys, .(X, Zs)) :- app(Xs, Ys, Zs).
Queries:
suffix(g,a).
(1) PrologToPiTRSProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
suffix_in: (b,f)
app_in: (f,b,f)
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x2,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x3,
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x1,
x2)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(2) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x2,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x3,
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x1,
x2)
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
SUFFIX_IN_GA(Xs, Ys) → U1_GA(Xs, Ys, app_in_aga(X1, Xs, Ys))
SUFFIX_IN_GA(Xs, Ys) → APP_IN_AGA(X1, Xs, Ys)
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → U2_AGA(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x2,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x3,
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x1,
x2)
SUFFIX_IN_GA(
x1,
x2) =
SUFFIX_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x1,
x3)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
U2_AGA(
x1,
x2,
x3,
x4,
x5) =
U2_AGA(
x3,
x5)
We have to consider all (P,R,Pi)-chains
(4) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
SUFFIX_IN_GA(Xs, Ys) → U1_GA(Xs, Ys, app_in_aga(X1, Xs, Ys))
SUFFIX_IN_GA(Xs, Ys) → APP_IN_AGA(X1, Xs, Ys)
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → U2_AGA(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x2,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x3,
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x1,
x2)
SUFFIX_IN_GA(
x1,
x2) =
SUFFIX_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x1,
x3)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
U2_AGA(
x1,
x2,
x3,
x4,
x5) =
U2_AGA(
x3,
x5)
We have to consider all (P,R,Pi)-chains
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 3 less nodes.
(6) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x2,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x3,
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x1,
x2)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
We have to consider all (P,R,Pi)-chains
(7) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(8) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
R is empty.
The argument filtering Pi contains the following mapping:
.(
x1,
x2) =
.(
x2)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
We have to consider all (P,R,Pi)-chains
(9) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(10) Obligation:
Q DP problem:
The TRS P consists of the following rules:
APP_IN_AGA(Ys) → APP_IN_AGA(Ys)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(11) NonTerminationProof (EQUIVALENT transformation)
We used the non-termination processor [FROCOS05] to show that the DP problem is infinite.
Found a loop by semiunifying a rule from P directly.
s =
APP_IN_AGA(
Ys) evaluates to t =
APP_IN_AGA(
Ys)
Thus s starts an infinite chain as s semiunifies with t with the following substitutions:
- Matcher: [ ]
- Semiunifier: [ ]
Rewriting sequenceThe DP semiunifies directly so there is only one rewrite step from APP_IN_AGA(Ys) to APP_IN_AGA(Ys).
(12) FALSE
(13) PrologToPiTRSProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
suffix_in: (b,f)
app_in: (f,b,f)
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x2)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(14) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x2)
(15) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
SUFFIX_IN_GA(Xs, Ys) → U1_GA(Xs, Ys, app_in_aga(X1, Xs, Ys))
SUFFIX_IN_GA(Xs, Ys) → APP_IN_AGA(X1, Xs, Ys)
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → U2_AGA(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x2)
SUFFIX_IN_GA(
x1,
x2) =
SUFFIX_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x3)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
U2_AGA(
x1,
x2,
x3,
x4,
x5) =
U2_AGA(
x5)
We have to consider all (P,R,Pi)-chains
(16) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
SUFFIX_IN_GA(Xs, Ys) → U1_GA(Xs, Ys, app_in_aga(X1, Xs, Ys))
SUFFIX_IN_GA(Xs, Ys) → APP_IN_AGA(X1, Xs, Ys)
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → U2_AGA(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x2)
SUFFIX_IN_GA(
x1,
x2) =
SUFFIX_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x3)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
U2_AGA(
x1,
x2,
x3,
x4,
x5) =
U2_AGA(
x5)
We have to consider all (P,R,Pi)-chains
(17) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 3 less nodes.
(18) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
The TRS R consists of the following rules:
suffix_in_ga(Xs, Ys) → U1_ga(Xs, Ys, app_in_aga(X1, Xs, Ys))
app_in_aga([], X, X) → app_out_aga([], X, X)
app_in_aga(.(X, Xs), Ys, .(X, Zs)) → U2_aga(X, Xs, Ys, Zs, app_in_aga(Xs, Ys, Zs))
U2_aga(X, Xs, Ys, Zs, app_out_aga(Xs, Ys, Zs)) → app_out_aga(.(X, Xs), Ys, .(X, Zs))
U1_ga(Xs, Ys, app_out_aga(X1, Xs, Ys)) → suffix_out_ga(Xs, Ys)
The argument filtering Pi contains the following mapping:
suffix_in_ga(
x1,
x2) =
suffix_in_ga(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
app_in_aga(
x1,
x2,
x3) =
app_in_aga(
x2)
app_out_aga(
x1,
x2,
x3) =
app_out_aga(
x1,
x3)
U2_aga(
x1,
x2,
x3,
x4,
x5) =
U2_aga(
x5)
.(
x1,
x2) =
.(
x2)
suffix_out_ga(
x1,
x2) =
suffix_out_ga(
x2)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
We have to consider all (P,R,Pi)-chains
(19) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(20) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
APP_IN_AGA(.(X, Xs), Ys, .(X, Zs)) → APP_IN_AGA(Xs, Ys, Zs)
R is empty.
The argument filtering Pi contains the following mapping:
.(
x1,
x2) =
.(
x2)
APP_IN_AGA(
x1,
x2,
x3) =
APP_IN_AGA(
x2)
We have to consider all (P,R,Pi)-chains
(21) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(22) Obligation:
Q DP problem:
The TRS P consists of the following rules:
APP_IN_AGA(Ys) → APP_IN_AGA(Ys)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(23) NonTerminationProof (EQUIVALENT transformation)
We used the non-termination processor [FROCOS05] to show that the DP problem is infinite.
Found a loop by semiunifying a rule from P directly.
s =
APP_IN_AGA(
Ys) evaluates to t =
APP_IN_AGA(
Ys)
Thus s starts an infinite chain as s semiunifies with t with the following substitutions:
- Matcher: [ ]
- Semiunifier: [ ]
Rewriting sequenceThe DP semiunifies directly so there is only one rewrite step from APP_IN_AGA(Ys) to APP_IN_AGA(Ys).
(24) FALSE