(0) Obligation:
Clauses:
num(0).
num(s(X)) :- num(X).
Queries:
num(g).
(1) PrologToDTProblemTransformerProof (SOUND transformation)
Built DT problem from termination graph.
(2) Obligation:
Triples:
num1(s(s(T6))) :- num1(T6).
Clauses:
numc1(0).
numc1(s(0)).
numc1(s(s(T6))) :- numc1(T6).
Afs:
num1(x1) = num1(x1)
(3) TriplesToPiDPProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
num1_in: (b)
Transforming
TRIPLES into the following
Term Rewriting System:
Pi DP problem:
The TRS P consists of the following rules:
NUM1_IN_G(s(s(T6))) → U1_G(T6, num1_in_g(T6))
NUM1_IN_G(s(s(T6))) → NUM1_IN_G(T6)
R is empty.
Pi is empty.
We have to consider all (P,R,Pi)-chains
Infinitary Constructor Rewriting Termination of PiDP implies Termination of TRIPLES
(4) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
NUM1_IN_G(s(s(T6))) → U1_G(T6, num1_in_g(T6))
NUM1_IN_G(s(s(T6))) → NUM1_IN_G(T6)
R is empty.
Pi is empty.
We have to consider all (P,R,Pi)-chains
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 1 less node.
(6) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
NUM1_IN_G(s(s(T6))) → NUM1_IN_G(T6)
R is empty.
Pi is empty.
We have to consider all (P,R,Pi)-chains
(7) PiDPToQDPProof (EQUIVALENT transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(8) Obligation:
Q DP problem:
The TRS P consists of the following rules:
NUM1_IN_G(s(s(T6))) → NUM1_IN_G(T6)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(9) QDPSizeChangeProof (EQUIVALENT transformation)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.
From the DPs we obtained the following set of size-change graphs:
- NUM1_IN_G(s(s(T6))) → NUM1_IN_G(T6)
The graph contains the following edges 1 > 1
(10) YES