(0) Obligation:
Clauses:
less(0, s(X1)).
less(s(X), s(Y)) :- less(X, Y).
Queries:
less(g,a).
(1) PrologToPiTRSProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
less_in: (b,f)
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(2) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → U1_GA(X, Y, less_in_ga(X, Y))
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x3)
We have to consider all (P,R,Pi)-chains
(4) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → U1_GA(X, Y, less_in_ga(X, Y))
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x3)
We have to consider all (P,R,Pi)-chains
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 1 less node.
(6) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(7) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(8) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
R is empty.
The argument filtering Pi contains the following mapping:
s(
x1) =
s(
x1)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(9) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(10) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X)) → LESS_IN_GA(X)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(11) QDPSizeChangeProof (EQUIVALENT transformation)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.
From the DPs we obtained the following set of size-change graphs:
- LESS_IN_GA(s(X)) → LESS_IN_GA(X)
The graph contains the following edges 1 > 1
(12) TRUE
(13) PrologToPiTRSProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
less_in: (b,f)
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga(
x1)
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(14) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga(
x1)
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
(15) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → U1_GA(X, Y, less_in_ga(X, Y))
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga(
x1)
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x1,
x3)
We have to consider all (P,R,Pi)-chains
(16) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → U1_GA(X, Y, less_in_ga(X, Y))
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga(
x1)
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x1,
x3)
We have to consider all (P,R,Pi)-chains
(17) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 1 less node.
(18) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
The TRS R consists of the following rules:
less_in_ga(0, s(X1)) → less_out_ga(0, s(X1))
less_in_ga(s(X), s(Y)) → U1_ga(X, Y, less_in_ga(X, Y))
U1_ga(X, Y, less_out_ga(X, Y)) → less_out_ga(s(X), s(Y))
The argument filtering Pi contains the following mapping:
less_in_ga(
x1,
x2) =
less_in_ga(
x1)
0 =
0
less_out_ga(
x1,
x2) =
less_out_ga(
x1)
s(
x1) =
s(
x1)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x1,
x3)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(19) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(20) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X), s(Y)) → LESS_IN_GA(X, Y)
R is empty.
The argument filtering Pi contains the following mapping:
s(
x1) =
s(
x1)
LESS_IN_GA(
x1,
x2) =
LESS_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(21) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(22) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LESS_IN_GA(s(X)) → LESS_IN_GA(X)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.