(0) Obligation:
Clauses:
less(0, Y) :- ','(!, =(Y, s(X2))).
less(X, Y) :- ','(p(X, X1), ','(p(Y, Y1), less(X1, Y1))).
p(0, 0).
p(s(X), X).
=(X, X).
Queries:
less(g,a).
(1) BuiltinConflictTransformerProof (SOUND transformation)
Renamed defined predicates conflicting with built-in predicates [PROLOG].
(2) Obligation:
Clauses:
less(0, Y) :- ','(!, user_defined_=(Y, s(X2))).
less(X, Y) :- ','(p(X, X1), ','(p(Y, Y1), less(X1, Y1))).
p(0, 0).
p(s(X), X).
user_defined_=(X, X).
Queries:
less(g,a).
(3) PrologToDTProblemTransformerProof (SOUND transformation)
Built DT problem from termination graph.
(4) Obligation:
Triples:
less18(s(T25)) :- less18(T25).
less1(s(T19), 0) :- less18(T19).
less1(s(T19), s(T29)) :- less1(T19, T29).
Clauses:
lessc18(s(T25)) :- lessc18(T25).
lessc1(0, s(T11)).
lessc1(s(T19), 0) :- lessc18(T19).
lessc1(s(T19), s(T29)) :- lessc1(T19, T29).
Afs:
less1(x1, x2) = less1(x1)
(5) TriplesToPiDPProof (SOUND transformation)
We use the technique of [LOPSTR]. With regard to the inferred argument filtering the predicates were used in the following modes:
less1_in: (b,f)
less18_in: (b)
Transforming
TRIPLES into the following
Term Rewriting System:
Pi DP problem:
The TRS P consists of the following rules:
LESS1_IN_GA(s(T19), 0) → U2_GA(T19, less18_in_g(T19))
LESS1_IN_GA(s(T19), 0) → LESS18_IN_G(T19)
LESS18_IN_G(s(T25)) → U1_G(T25, less18_in_g(T25))
LESS18_IN_G(s(T25)) → LESS18_IN_G(T25)
LESS1_IN_GA(s(T19), s(T29)) → U3_GA(T19, T29, less1_in_ga(T19, T29))
LESS1_IN_GA(s(T19), s(T29)) → LESS1_IN_GA(T19, T29)
R is empty.
The argument filtering Pi contains the following mapping:
less1_in_ga(
x1,
x2) =
less1_in_ga(
x1)
s(
x1) =
s(
x1)
less18_in_g(
x1) =
less18_in_g(
x1)
0 =
0
LESS1_IN_GA(
x1,
x2) =
LESS1_IN_GA(
x1)
U2_GA(
x1,
x2) =
U2_GA(
x1,
x2)
LESS18_IN_G(
x1) =
LESS18_IN_G(
x1)
U1_G(
x1,
x2) =
U1_G(
x1,
x2)
U3_GA(
x1,
x2,
x3) =
U3_GA(
x1,
x3)
We have to consider all (P,R,Pi)-chains
Infinitary Constructor Rewriting Termination of PiDP implies Termination of TRIPLES
(6) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS1_IN_GA(s(T19), 0) → U2_GA(T19, less18_in_g(T19))
LESS1_IN_GA(s(T19), 0) → LESS18_IN_G(T19)
LESS18_IN_G(s(T25)) → U1_G(T25, less18_in_g(T25))
LESS18_IN_G(s(T25)) → LESS18_IN_G(T25)
LESS1_IN_GA(s(T19), s(T29)) → U3_GA(T19, T29, less1_in_ga(T19, T29))
LESS1_IN_GA(s(T19), s(T29)) → LESS1_IN_GA(T19, T29)
R is empty.
The argument filtering Pi contains the following mapping:
less1_in_ga(
x1,
x2) =
less1_in_ga(
x1)
s(
x1) =
s(
x1)
less18_in_g(
x1) =
less18_in_g(
x1)
0 =
0
LESS1_IN_GA(
x1,
x2) =
LESS1_IN_GA(
x1)
U2_GA(
x1,
x2) =
U2_GA(
x1,
x2)
LESS18_IN_G(
x1) =
LESS18_IN_G(
x1)
U1_G(
x1,
x2) =
U1_G(
x1,
x2)
U3_GA(
x1,
x2,
x3) =
U3_GA(
x1,
x3)
We have to consider all (P,R,Pi)-chains
(7) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 2 SCCs with 4 less nodes.
(8) Complex Obligation (AND)
(9) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS18_IN_G(s(T25)) → LESS18_IN_G(T25)
R is empty.
Pi is empty.
We have to consider all (P,R,Pi)-chains
(10) PiDPToQDPProof (EQUIVALENT transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(11) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LESS18_IN_G(s(T25)) → LESS18_IN_G(T25)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(12) QDPSizeChangeProof (EQUIVALENT transformation)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.
From the DPs we obtained the following set of size-change graphs:
- LESS18_IN_G(s(T25)) → LESS18_IN_G(T25)
The graph contains the following edges 1 > 1
(13) YES
(14) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
LESS1_IN_GA(s(T19), s(T29)) → LESS1_IN_GA(T19, T29)
R is empty.
The argument filtering Pi contains the following mapping:
s(
x1) =
s(
x1)
LESS1_IN_GA(
x1,
x2) =
LESS1_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(15) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(16) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LESS1_IN_GA(s(T19)) → LESS1_IN_GA(T19)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(17) QDPSizeChangeProof (EQUIVALENT transformation)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.
From the DPs we obtained the following set of size-change graphs:
- LESS1_IN_GA(s(T19)) → LESS1_IN_GA(T19)
The graph contains the following edges 1 > 1
(18) YES