Termination w.r.t. Q of the given QTRS could be proven:

0 QTRS
↳1 DependencyPairsProof (⇔)
↳2 QDP
↳3 DependencyGraphProof (⇔)
↳4 AND
    ↳5 QDP
        ↳6 QDPOrderProof (⇔)
        ↳7 QDP
        ↳8 QDPOrderProof (⇔)
        ↳9 QDP
        ↳10 PisEmptyProof (⇔)
        ↳11 TRUE
    ↳12 QDP
        ↳13 QDPOrderProof (⇔)
        ↳14 QDP
        ↳15 QDPOrderProof (⇔)
        ↳16 QDP
        ↳17 PisEmptyProof (⇔)
        ↳18 TRUE
    ↳19 QDP
        ↳20 QDPOrderProof (⇔)
        ↳21 QDP
        ↳22 QDPOrderProof (⇔)
        ↳23 QDP
        ↳24 PisEmptyProof (⇔)
        ↳25 TRUE
    ↳26 QDP
        ↳27 QDPOrderProof (⇔)
        ↳28 QDP
        ↳29 QDPOrderProof (⇔)
        ↳30 QDP
        ↳31 QDPOrderProof (⇔)
        ↳32 QDP
        ↳33 QDPOrderProof (⇔)
        ↳34 QDP
        ↳35 PisEmptyProof (⇔)
        ↳36 TRUE
    ↳37 QDP
        ↳38 QDPOrderProof (⇔)
        ↳39 QDP
        ↳40 QDPOrderProof (⇔)
        ↳41 QDP
        ↳42 QDPOrderProof (⇔)
        ↳43 QDP
        ↳44 QDPOrderProof (⇔)
        ↳45 QDP
        ↳46 QDPOrderProof (⇔)
        ↳47 QDP
        ↳48 QDPOrderProof (⇔)
        ↳49 QDP
        ↳50 PisEmptyProof (⇔)
        ↳51 TRUE
    ↳52 QDP
        ↳53 QDPOrderProof (⇔)
        ↳54 QDP
        ↳55 QDPOrderProof (⇔)
        ↳56 QDP
        ↳57 DependencyGraphProof (⇔)
        ↳58 QDP
        ↳59 QDPOrderProof (⇔)
        ↳60 QDP
        ↳61 QDPOrderProof (⇔)
        ↳62 QDP
        ↳63 QDPOrderProof (⇔)
        ↳64 QDP
        ↳65 QDPOrderProof (⇔)
        ↳66 QDP
        ↳67 QDPOrderProof (⇔)
        ↳68 QDP
        ↳69 QDPOrderProof (⇔)
        ↳70 QDP
        ↳71 PisEmptyProof (⇔)
        ↳72 TRUE

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
ACTIVE(filter(cons(X, Y), 0, M)) → CONS(0, filter(Y, M, M))
ACTIVE(filter(cons(X, Y), 0, M)) → FILTER(Y, M, M)
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
ACTIVE(filter(cons(X, Y), s(N), M)) → CONS(X, filter(Y, N, M))
ACTIVE(filter(cons(X, Y), s(N), M)) → FILTER(Y, N, M)
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
ACTIVE(sieve(cons(0, Y))) → CONS(0, sieve(Y))
ACTIVE(sieve(cons(0, Y))) → SIEVE(Y)
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
ACTIVE(sieve(cons(s(N), Y))) → CONS(s(N), sieve(filter(Y, N, N)))
ACTIVE(sieve(cons(s(N), Y))) → SIEVE(filter(Y, N, N))
ACTIVE(sieve(cons(s(N), Y))) → FILTER(Y, N, N)
ACTIVE(nats(N)) → MARK(cons(N, nats(s(N))))
ACTIVE(nats(N)) → CONS(N, nats(s(N)))
ACTIVE(nats(N)) → NATS(s(N))
ACTIVE(nats(N)) → S(N)
ACTIVE(zprimes) → MARK(sieve(nats(s(s(0)))))
ACTIVE(zprimes) → SIEVE(nats(s(s(0))))
ACTIVE(zprimes) → NATS(s(s(0)))
ACTIVE(zprimes) → S(s(0))
ACTIVE(zprimes) → S(0)
MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
MARK(filter(X1, X2, X3)) → FILTER(mark(X1), mark(X2), mark(X3))
MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
MARK(cons(X1, X2)) → ACTIVE(cons(mark(X1), X2))
MARK(cons(X1, X2)) → CONS(mark(X1), X2)
MARK(cons(X1, X2)) → MARK(X1)
MARK(0) → ACTIVE(0)
MARK(s(X)) → ACTIVE(s(mark(X)))
MARK(s(X)) → S(mark(X))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
MARK(sieve(X)) → SIEVE(mark(X))
MARK(sieve(X)) → MARK(X)
MARK(nats(X)) → ACTIVE(nats(mark(X)))
MARK(nats(X)) → NATS(mark(X))
MARK(nats(X)) → MARK(X)
MARK(zprimes) → ACTIVE(zprimes)
FILTER(mark(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, mark(X2), X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, mark(X3)) → FILTER(X1, X2, X3)
FILTER(active(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, active(X3)) → FILTER(X1, X2, X3)
CONS(mark(X1), X2) → CONS(X1, X2)
CONS(X1, mark(X2)) → CONS(X1, X2)
CONS(active(X1), X2) → CONS(X1, X2)
CONS(X1, active(X2)) → CONS(X1, X2)
S(mark(X)) → S(X)
S(active(X)) → S(X)
SIEVE(mark(X)) → SIEVE(X)
SIEVE(active(X)) → SIEVE(X)
NATS(mark(X)) → NATS(X)
NATS(active(X)) → NATS(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 6 SCCs with 22 less nodes.

(4) Complex Obligation (AND)

(5) Obligation:

Q DP problem:
The TRS P consists of the following rules:

NATS(active(X)) → NATS(X)
NATS(mark(X)) → NATS(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(6) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


NATS(active(X)) → NATS(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
NATS(x0, x1)  =  NATS(x1)

Tags:
NATS has argument tags [0,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(NATS(x1)) = 1   
POL(active(x1)) = 1 + x1   
POL(mark(x1)) = x1   

The following usable rules [FROCOS05] were oriented: none

(7) Obligation:

Q DP problem:
The TRS P consists of the following rules:

NATS(mark(X)) → NATS(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(8) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


NATS(mark(X)) → NATS(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
NATS(x0, x1)  =  NATS(x1)

Tags:
NATS has argument tags [1,1] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(NATS(x1)) = 0   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(9) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(10) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(11) TRUE

(12) Obligation:

Q DP problem:
The TRS P consists of the following rules:

SIEVE(active(X)) → SIEVE(X)
SIEVE(mark(X)) → SIEVE(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(13) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


SIEVE(active(X)) → SIEVE(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
SIEVE(x0, x1)  =  SIEVE(x1)

Tags:
SIEVE has argument tags [0,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(SIEVE(x1)) = 1   
POL(active(x1)) = 1 + x1   
POL(mark(x1)) = x1   

The following usable rules [FROCOS05] were oriented: none

(14) Obligation:

Q DP problem:
The TRS P consists of the following rules:

SIEVE(mark(X)) → SIEVE(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(15) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


SIEVE(mark(X)) → SIEVE(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
SIEVE(x0, x1)  =  SIEVE(x1)

Tags:
SIEVE has argument tags [1,1] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(SIEVE(x1)) = 0   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(16) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(17) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(18) TRUE

(19) Obligation:

Q DP problem:
The TRS P consists of the following rules:

S(active(X)) → S(X)
S(mark(X)) → S(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(20) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


S(active(X)) → S(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
S(x0, x1)  =  S(x1)

Tags:
S has argument tags [0,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(S(x1)) = 1   
POL(active(x1)) = 1 + x1   
POL(mark(x1)) = x1   

The following usable rules [FROCOS05] were oriented: none

(21) Obligation:

Q DP problem:
The TRS P consists of the following rules:

S(mark(X)) → S(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(22) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


S(mark(X)) → S(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
S(x0, x1)  =  S(x1)

Tags:
S has argument tags [1,1] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(S(x1)) = 0   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(23) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(24) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(25) TRUE

(26) Obligation:

Q DP problem:
The TRS P consists of the following rules:

CONS(X1, mark(X2)) → CONS(X1, X2)
CONS(mark(X1), X2) → CONS(X1, X2)
CONS(active(X1), X2) → CONS(X1, X2)
CONS(X1, active(X2)) → CONS(X1, X2)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(27) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


CONS(mark(X1), X2) → CONS(X1, X2)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
CONS(x0, x1, x2)  =  CONS(x0, x1)

Tags:
CONS has argument tags [3,0,2] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(CONS(x1, x2)) = 0   
POL(active(x1)) = x1   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(28) Obligation:

Q DP problem:
The TRS P consists of the following rules:

CONS(X1, mark(X2)) → CONS(X1, X2)
CONS(active(X1), X2) → CONS(X1, X2)
CONS(X1, active(X2)) → CONS(X1, X2)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(29) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


CONS(X1, mark(X2)) → CONS(X1, X2)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
CONS(x0, x1, x2)  =  CONS(x2)

Tags:
CONS has argument tags [1,2,2] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(CONS(x1, x2)) = 1 + x1   
POL(active(x1)) = x1   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(30) Obligation:

Q DP problem:
The TRS P consists of the following rules:

CONS(active(X1), X2) → CONS(X1, X2)
CONS(X1, active(X2)) → CONS(X1, X2)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(31) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


CONS(active(X1), X2) → CONS(X1, X2)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
CONS(x0, x1, x2)  =  CONS(x0, x1)

Tags:
CONS has argument tags [0,1,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(CONS(x1, x2)) = 1   
POL(active(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(32) Obligation:

Q DP problem:
The TRS P consists of the following rules:

CONS(X1, active(X2)) → CONS(X1, X2)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(33) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


CONS(X1, active(X2)) → CONS(X1, X2)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
CONS(x0, x1, x2)  =  CONS(x0, x2)

Tags:
CONS has argument tags [3,2,1] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(CONS(x1, x2)) = 0   
POL(active(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(34) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(35) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(36) TRUE

(37) Obligation:

Q DP problem:
The TRS P consists of the following rules:

FILTER(X1, mark(X2), X3) → FILTER(X1, X2, X3)
FILTER(mark(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, mark(X3)) → FILTER(X1, X2, X3)
FILTER(active(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, active(X3)) → FILTER(X1, X2, X3)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(38) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


FILTER(X1, mark(X2), X3) → FILTER(X1, X2, X3)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
FILTER(x0, x1, x2, x3)  =  FILTER(x2)

Tags:
FILTER has argument tags [1,1,3,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(FILTER(x1, x2, x3)) = 1 + x3   
POL(active(x1)) = x1   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(39) Obligation:

Q DP problem:
The TRS P consists of the following rules:

FILTER(mark(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, mark(X3)) → FILTER(X1, X2, X3)
FILTER(active(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, active(X3)) → FILTER(X1, X2, X3)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(40) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


FILTER(mark(X1), X2, X3) → FILTER(X1, X2, X3)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
FILTER(x0, x1, x2, x3)  =  FILTER(x1)

Tags:
FILTER has argument tags [1,2,3,2] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(FILTER(x1, x2, x3)) = x2   
POL(active(x1)) = x1   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(41) Obligation:

Q DP problem:
The TRS P consists of the following rules:

FILTER(X1, X2, mark(X3)) → FILTER(X1, X2, X3)
FILTER(active(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, active(X3)) → FILTER(X1, X2, X3)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(42) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


FILTER(X1, X2, mark(X3)) → FILTER(X1, X2, X3)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
FILTER(x0, x1, x2, x3)  =  FILTER(x0, x2)

Tags:
FILTER has argument tags [1,3,2,2] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(FILTER(x1, x2, x3)) = x2 + x3   
POL(active(x1)) = x1   
POL(mark(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(43) Obligation:

Q DP problem:
The TRS P consists of the following rules:

FILTER(active(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)
FILTER(X1, X2, active(X3)) → FILTER(X1, X2, X3)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(44) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


FILTER(X1, X2, active(X3)) → FILTER(X1, X2, X3)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
FILTER(x0, x1, x2, x3)  =  FILTER(x3)

Tags:
FILTER has argument tags [1,2,3,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(FILTER(x1, x2, x3)) = 1   
POL(active(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(45) Obligation:

Q DP problem:
The TRS P consists of the following rules:

FILTER(active(X1), X2, X3) → FILTER(X1, X2, X3)
FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(46) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


FILTER(active(X1), X2, X3) → FILTER(X1, X2, X3)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
FILTER(x0, x1, x2, x3)  =  FILTER(x1)

Tags:
FILTER has argument tags [1,0,1,3] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(FILTER(x1, x2, x3)) = x3   
POL(active(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(47) Obligation:

Q DP problem:
The TRS P consists of the following rules:

FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(48) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


FILTER(X1, active(X2), X3) → FILTER(X1, X2, X3)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
FILTER(x0, x1, x2, x3)  =  FILTER(x0)

Tags:
FILTER has argument tags [3,3,1,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(FILTER(x1, x2, x3)) = x2 + x3   
POL(active(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(49) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(50) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(51) TRUE

(52) Obligation:

Q DP problem:
The TRS P consists of the following rules:

MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
MARK(cons(X1, X2)) → ACTIVE(cons(mark(X1), X2))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
MARK(cons(X1, X2)) → MARK(X1)
MARK(s(X)) → ACTIVE(s(mark(X)))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(sieve(X)) → MARK(X)
MARK(nats(X)) → ACTIVE(nats(mark(X)))
ACTIVE(nats(N)) → MARK(cons(N, nats(s(N))))
MARK(nats(X)) → MARK(X)
MARK(zprimes) → ACTIVE(zprimes)
ACTIVE(zprimes) → MARK(sieve(nats(s(s(0)))))

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(53) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


ACTIVE(nats(N)) → MARK(cons(N, nats(s(N))))
MARK(nats(X)) → MARK(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
MARK(x0, x1)  =  MARK(x1)
ACTIVE(x0, x1)  =  ACTIVE(x0, x1)

Tags:
MARK has argument tags [0,1] and root tag 0
ACTIVE has argument tags [1,1] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(0) = 0   
POL(ACTIVE(x1)) = 0   
POL(MARK(x1)) = 1   
POL(active(x1)) = x1   
POL(cons(x1, x2)) = x1   
POL(filter(x1, x2, x3)) = x1 + x2 + x3   
POL(mark(x1)) = x1   
POL(nats(x1)) = 1 + x1   
POL(s(x1)) = x1   
POL(sieve(x1)) = x1   
POL(zprimes) = 1   

The following usable rules [FROCOS05] were oriented: none

(54) Obligation:

Q DP problem:
The TRS P consists of the following rules:

MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
MARK(cons(X1, X2)) → ACTIVE(cons(mark(X1), X2))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
MARK(cons(X1, X2)) → MARK(X1)
MARK(s(X)) → ACTIVE(s(mark(X)))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(sieve(X)) → MARK(X)
MARK(nats(X)) → ACTIVE(nats(mark(X)))
MARK(zprimes) → ACTIVE(zprimes)
ACTIVE(zprimes) → MARK(sieve(nats(s(s(0)))))

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(55) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


ACTIVE(zprimes) → MARK(sieve(nats(s(s(0)))))
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
MARK(x0, x1)  =  MARK(x1)
ACTIVE(x0, x1)  =  ACTIVE(x0)

Tags:
MARK has argument tags [0,2] and root tag 0
ACTIVE has argument tags [2,1] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(0) = 0   
POL(ACTIVE(x1)) = x1   
POL(MARK(x1)) = x1   
POL(active(x1)) = x1   
POL(cons(x1, x2)) = x1   
POL(filter(x1, x2, x3)) = x1 + x2 + x3   
POL(mark(x1)) = x1   
POL(nats(x1)) = x1   
POL(s(x1)) = x1   
POL(sieve(x1)) = x1   
POL(zprimes) = 1   

The following usable rules [FROCOS05] were oriented:

mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
mark(s(X)) → active(s(mark(X)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
mark(sieve(X)) → active(sieve(mark(X)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
mark(nats(X)) → active(nats(mark(X)))
active(nats(N)) → mark(cons(N, nats(s(N))))
mark(zprimes) → active(zprimes)
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(0) → active(0)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(X1, mark(X2)) → cons(X1, X2)
cons(mark(X1), X2) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(active(X)) → s(X)
s(mark(X)) → s(X)
sieve(active(X)) → sieve(X)
sieve(mark(X)) → sieve(X)
nats(active(X)) → nats(X)
nats(mark(X)) → nats(X)

(56) Obligation:

Q DP problem:
The TRS P consists of the following rules:

MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
MARK(cons(X1, X2)) → ACTIVE(cons(mark(X1), X2))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
MARK(cons(X1, X2)) → MARK(X1)
MARK(s(X)) → ACTIVE(s(mark(X)))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(sieve(X)) → MARK(X)
MARK(nats(X)) → ACTIVE(nats(mark(X)))
MARK(zprimes) → ACTIVE(zprimes)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(57) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node.

(58) Obligation:

Q DP problem:
The TRS P consists of the following rules:

ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
MARK(cons(X1, X2)) → ACTIVE(cons(mark(X1), X2))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
MARK(cons(X1, X2)) → MARK(X1)
MARK(s(X)) → ACTIVE(s(mark(X)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
MARK(sieve(X)) → MARK(X)
MARK(nats(X)) → ACTIVE(nats(mark(X)))

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(59) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


MARK(cons(X1, X2)) → MARK(X1)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
ACTIVE(x0, x1)  =  ACTIVE(x1)
MARK(x0, x1)  =  MARK(x1)

Tags:
ACTIVE has argument tags [0,2] and root tag 0
MARK has argument tags [0,2] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(0) = 0   
POL(ACTIVE(x1)) = 0   
POL(MARK(x1)) = 0   
POL(active(x1)) = x1   
POL(cons(x1, x2)) = 1 + x1   
POL(filter(x1, x2, x3)) = x1 + x2 + x3   
POL(mark(x1)) = x1   
POL(nats(x1)) = 1 + x1   
POL(s(x1)) = x1   
POL(sieve(x1)) = x1   
POL(zprimes) = 1   

The following usable rules [FROCOS05] were oriented: none

(60) Obligation:

Q DP problem:
The TRS P consists of the following rules:

ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
MARK(cons(X1, X2)) → ACTIVE(cons(mark(X1), X2))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
MARK(s(X)) → ACTIVE(s(mark(X)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
MARK(sieve(X)) → MARK(X)
MARK(nats(X)) → ACTIVE(nats(mark(X)))

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(61) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


MARK(cons(X1, X2)) → ACTIVE(cons(mark(X1), X2))
MARK(s(X)) → ACTIVE(s(mark(X)))
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
ACTIVE(x0, x1)  =  ACTIVE(x0, x1)
MARK(x0, x1)  =  MARK(x0)

Tags:
ACTIVE has argument tags [2,0] and root tag 1
MARK has argument tags [0,3] and root tag 1

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(0) = 0   
POL(ACTIVE(x1)) = 0   
POL(MARK(x1)) = 1   
POL(active(x1)) = 1 + x1   
POL(cons(x1, x2)) = 0   
POL(filter(x1, x2, x3)) = 1   
POL(mark(x1)) = 0   
POL(nats(x1)) = 1   
POL(s(x1)) = 0   
POL(sieve(x1)) = 1   
POL(zprimes) = 1   

The following usable rules [FROCOS05] were oriented: none

(62) Obligation:

Q DP problem:
The TRS P consists of the following rules:

ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
MARK(sieve(X)) → MARK(X)
MARK(nats(X)) → ACTIVE(nats(mark(X)))

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(63) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


MARK(filter(X1, X2, X3)) → MARK(X1)
MARK(filter(X1, X2, X3)) → MARK(X2)
MARK(filter(X1, X2, X3)) → MARK(X3)
MARK(sieve(X)) → MARK(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
ACTIVE(x0, x1)  =  ACTIVE(x0)
MARK(x0, x1)  =  MARK(x1)

Tags:
ACTIVE has argument tags [2,1] and root tag 0
MARK has argument tags [0,2] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(0) = 1   
POL(ACTIVE(x1)) = 1   
POL(MARK(x1)) = 0   
POL(active(x1)) = 0   
POL(cons(x1, x2)) = 1   
POL(filter(x1, x2, x3)) = 1 + x1 + x2 + x3   
POL(mark(x1)) = 1   
POL(nats(x1)) = 1 + x1   
POL(s(x1)) = x1   
POL(sieve(x1)) = 1 + x1   
POL(zprimes) = 0   

The following usable rules [FROCOS05] were oriented: none

(64) Obligation:

Q DP problem:
The TRS P consists of the following rules:

ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
MARK(nats(X)) → ACTIVE(nats(mark(X)))

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(65) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


ACTIVE(filter(cons(X, Y), 0, M)) → MARK(cons(0, filter(Y, M, M)))
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
ACTIVE(x0, x1)  =  ACTIVE(x0)
MARK(x0, x1)  =  MARK(x1)

Tags:
ACTIVE has argument tags [2,0] and root tag 1
MARK has argument tags [2,2] and root tag 1

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(0) = 1   
POL(ACTIVE(x1)) = x1   
POL(MARK(x1)) = 1   
POL(active(x1)) = x1   
POL(cons(x1, x2)) = 0   
POL(filter(x1, x2, x3)) = x2   
POL(mark(x1)) = x1   
POL(nats(x1)) = 1 + x1   
POL(s(x1)) = x1   
POL(sieve(x1)) = 0   
POL(zprimes) = 0   

The following usable rules [FROCOS05] were oriented:

filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(X1, mark(X2)) → cons(X1, X2)
cons(mark(X1), X2) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
mark(s(X)) → active(s(mark(X)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
mark(sieve(X)) → active(sieve(mark(X)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
mark(nats(X)) → active(nats(mark(X)))
active(nats(N)) → mark(cons(N, nats(s(N))))
mark(zprimes) → active(zprimes)
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(0) → active(0)
sieve(active(X)) → sieve(X)
sieve(mark(X)) → sieve(X)
s(active(X)) → s(X)
s(mark(X)) → s(X)
nats(active(X)) → nats(X)
nats(mark(X)) → nats(X)

(66) Obligation:

Q DP problem:
The TRS P consists of the following rules:

MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(s(X)) → MARK(X)
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
MARK(nats(X)) → ACTIVE(nats(mark(X)))

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(67) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


MARK(filter(X1, X2, X3)) → ACTIVE(filter(mark(X1), mark(X2), mark(X3)))
ACTIVE(filter(cons(X, Y), s(N), M)) → MARK(cons(X, filter(Y, N, M)))
ACTIVE(sieve(cons(0, Y))) → MARK(cons(0, sieve(Y)))
ACTIVE(sieve(cons(s(N), Y))) → MARK(cons(s(N), sieve(filter(Y, N, N))))
MARK(sieve(X)) → ACTIVE(sieve(mark(X)))
MARK(nats(X)) → ACTIVE(nats(mark(X)))
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
MARK(x0, x1)  =  MARK(x1)
ACTIVE(x0, x1)  =  ACTIVE(x0)

Tags:
MARK has argument tags [0,1] and root tag 1
ACTIVE has argument tags [1,2] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(0) = 0   
POL(ACTIVE(x1)) = 1   
POL(MARK(x1)) = 1   
POL(active(x1)) = 1   
POL(cons(x1, x2)) = 0   
POL(filter(x1, x2, x3)) = 1 + x1   
POL(mark(x1)) = 0   
POL(nats(x1)) = 1 + x1   
POL(s(x1)) = x1   
POL(sieve(x1)) = 1 + x1   
POL(zprimes) = 0   

The following usable rules [FROCOS05] were oriented: none

(68) Obligation:

Q DP problem:
The TRS P consists of the following rules:

MARK(s(X)) → MARK(X)

The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(69) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


MARK(s(X)) → MARK(X)
The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
MARK(x0, x1)  =  MARK(x1)

Tags:
MARK has argument tags [1,1] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(MARK(x1)) = 0   
POL(s(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(70) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

active(filter(cons(X, Y), 0, M)) → mark(cons(0, filter(Y, M, M)))
active(filter(cons(X, Y), s(N), M)) → mark(cons(X, filter(Y, N, M)))
active(sieve(cons(0, Y))) → mark(cons(0, sieve(Y)))
active(sieve(cons(s(N), Y))) → mark(cons(s(N), sieve(filter(Y, N, N))))
active(nats(N)) → mark(cons(N, nats(s(N))))
active(zprimes) → mark(sieve(nats(s(s(0)))))
mark(filter(X1, X2, X3)) → active(filter(mark(X1), mark(X2), mark(X3)))
mark(cons(X1, X2)) → active(cons(mark(X1), X2))
mark(0) → active(0)
mark(s(X)) → active(s(mark(X)))
mark(sieve(X)) → active(sieve(mark(X)))
mark(nats(X)) → active(nats(mark(X)))
mark(zprimes) → active(zprimes)
filter(mark(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, mark(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, mark(X3)) → filter(X1, X2, X3)
filter(active(X1), X2, X3) → filter(X1, X2, X3)
filter(X1, active(X2), X3) → filter(X1, X2, X3)
filter(X1, X2, active(X3)) → filter(X1, X2, X3)
cons(mark(X1), X2) → cons(X1, X2)
cons(X1, mark(X2)) → cons(X1, X2)
cons(active(X1), X2) → cons(X1, X2)
cons(X1, active(X2)) → cons(X1, X2)
s(mark(X)) → s(X)
s(active(X)) → s(X)
sieve(mark(X)) → sieve(X)
sieve(active(X)) → sieve(X)
nats(mark(X)) → nats(X)
nats(active(X)) → nats(X)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(71) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(72) TRUE