Termination w.r.t. Q of the given QTRS could be proven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f(X) → if(X, c, n__f(n__true))
if(true, X, Y) → X
if(false, X, Y) → activate(Y)
f(X) → n__f(X)
true → n__true
activate(n__f(X)) → f(activate(X))
activate(n__true) → true
activate(X) → X

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(X) → IF(X, c, n__f(n__true))
IF(false, X, Y) → ACTIVATE(Y)
ACTIVATE(n__f(X)) → F(activate(X))
ACTIVATE(n__f(X)) → ACTIVATE(X)
ACTIVATE(n__true) → TRUE

The TRS R consists of the following rules:

f(X) → if(X, c, n__f(n__true))
if(true, X, Y) → X
if(false, X, Y) → activate(Y)
f(X) → n__f(X)
true → n__true
activate(n__f(X)) → f(activate(X))
activate(n__true) → true
activate(X) → X

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

IF(false, X, Y) → ACTIVATE(Y)
ACTIVATE(n__f(X)) → F(activate(X))
F(X) → IF(X, c, n__f(n__true))
ACTIVATE(n__f(X)) → ACTIVATE(X)

The TRS R consists of the following rules:

f(X) → if(X, c, n__f(n__true))
if(true, X, Y) → X
if(false, X, Y) → activate(Y)
f(X) → n__f(X)
true → n__true
activate(n__f(X)) → f(activate(X))
activate(n__true) → true
activate(X) → X

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

ACTIVATE(n__f(X)) → ACTIVATE(X)

The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
IF(x0, x1, x2, x3)  =  IF(x1, x3)
ACTIVATE(x0, x1)  =  ACTIVATE(x0, x1)
F(x0, x1)  =  F(x0)

Tags:
IF has argument tags [4,3,0,1] and root tag 0
ACTIVATE has argument tags [0,1] and root tag 0
F has argument tags [1,0] and root tag 0

Comparison: MAX
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(ACTIVATE(x₁)) = 1   
POL(F(x₁)) = 1 + x₁   
POL(IF(x₁, x₂, x₃)) = 0   
POL(activate(x₁)) = x₁   
POL(c) = 0   
POL(f(x₁)) = 1 + x₁   
POL(false) = 1   
POL(if(x₁, x₂, x₃)) = x₂ + x₃   
POL(n__f(x₁)) = 1 + x₁   
POL(n__true) = 0   
POL(true) = 0   

The following usable rules [FROCOS05] were oriented:

if(false, X, Y) → activate(Y)
activate(n__f(X)) → f(activate(X))
f(X) → if(X, c, n__f(n__true))
activate(n__true) → true
activate(X) → X
f(X) → n__f(X)
if(true, X, Y) → X
true → n__true

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

IF(false, X, Y) → ACTIVATE(Y)
ACTIVATE(n__f(X)) → F(activate(X))
F(X) → IF(X, c, n__f(n__true))

The TRS R consists of the following rules:

f(X) → if(X, c, n__f(n__true))
if(true, X, Y) → X
if(false, X, Y) → activate(Y)
f(X) → n__f(X)
true → n__true
activate(n__f(X)) → f(activate(X))
activate(n__true) → true
activate(X) → X

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

IF(false, X, Y) → ACTIVATE(Y)
ACTIVATE(n__f(X)) → F(activate(X))
F(X) → IF(X, c, n__f(n__true))

The remaining pairs can at least be oriented weakly.
Used ordering: SCNP Order with the following components:
Level mapping:
Top level AFS:
IF(x0, x1, x2, x3)  =  IF(x0, x3)
ACTIVATE(x0, x1)  =  ACTIVATE(x0)
F(x0, x1)  =  F(x0, x1)

Tags:
IF has argument tags [0,7,5,7] and root tag 0
ACTIVATE has argument tags [4,0] and root tag 2
F has argument tags [7,4] and root tag 3

Comparison: DMS
Underlying order for the size change arcs and the rules of R:
Polynomial interpretation [POLO]:

POL(ACTIVATE(x₁)) = x₁   
POL(F(x₁)) = 0   
POL(IF(x₁, x₂, x₃)) = x₁ + x₃   
POL(activate(x₁)) = x₁   
POL(c) = 0   
POL(f(x₁)) = x₁   
POL(false) = 1   
POL(if(x₁, x₂, x₃)) = x₁ + x₂ + x₃   
POL(n__f(x₁)) = x₁   
POL(n__true) = 0   
POL(true) = 0   

The following usable rules [FROCOS05] were oriented: none

(8) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

f(X) → if(X, c, n__f(n__true))
if(true, X, Y) → X
if(false, X, Y) → activate(Y)
f(X) → n__f(X)
true → n__true
activate(n__f(X)) → f(activate(X))
activate(n__true) → true
activate(X) → X

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(10) TRUE