Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(y, f2(x, y)) -> f2(f2(a, y), f2(a, x))
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(y, f2(x, y)) -> f2(f2(a, y), f2(a, x))
Q is empty.
Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F2(y, f2(x, y)) -> F2(f2(a, y), f2(a, x))
F2(y, f2(x, y)) -> F2(a, x)
F2(y, f2(x, y)) -> F2(a, y)
The TRS R consists of the following rules:
f2(y, f2(x, y)) -> f2(f2(a, y), f2(a, x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F2(y, f2(x, y)) -> F2(f2(a, y), f2(a, x))
F2(y, f2(x, y)) -> F2(a, x)
F2(y, f2(x, y)) -> F2(a, y)
The TRS R consists of the following rules:
f2(y, f2(x, y)) -> f2(f2(a, y), f2(a, x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.