(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
Q is empty.
(1) AAECC Innermost (EQUIVALENT transformation)
We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is
double(0) → 0
double(s(x)) → s(s(double(x)))
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
The TRS R 2 is
a → b
a → c
The signature Sigma is {
c,
a,
b}
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
(4) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LE(s(x), s(y)) → LE(x, y)
DOUBLE(s(x)) → DOUBLE(x)
LOG(s(x)) → LOOP(s(x), s(0), 0)
LOOP(x, s(y), z) → IF(le(x, s(y)), x, s(y), z)
LOOP(x, s(y), z) → LE(x, s(y))
IF(false, x, y, z) → LOOP(x, double(y), s(z))
IF(false, x, y, z) → DOUBLE(y)
MAPLOG(xs) → MAPITER(xs, nil)
MAPITER(xs, ys) → IFMAP(isempty(xs), xs, ys)
MAPITER(xs, ys) → ISEMPTY(xs)
IFMAP(false, xs, ys) → MAPITER(droplast(xs), cons(log(last(xs)), ys))
IFMAP(false, xs, ys) → DROPLAST(xs)
IFMAP(false, xs, ys) → LOG(last(xs))
IFMAP(false, xs, ys) → LAST(xs)
LAST(cons(x, cons(y, xs))) → LAST(cons(y, xs))
DROPLAST(cons(x, cons(y, xs))) → DROPLAST(cons(y, xs))
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
We have to consider all minimal (P,Q,R)-chains.
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 6 SCCs with 8 less nodes.
(6) Complex Obligation (AND)
(7) Obligation:
Q DP problem:
The TRS P consists of the following rules:
DROPLAST(cons(x, cons(y, xs))) → DROPLAST(cons(y, xs))
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
We have to consider all minimal (P,Q,R)-chains.
(8) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LAST(cons(x, cons(y, xs))) → LAST(cons(y, xs))
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
We have to consider all minimal (P,Q,R)-chains.
(9) Obligation:
Q DP problem:
The TRS P consists of the following rules:
DOUBLE(s(x)) → DOUBLE(x)
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
We have to consider all minimal (P,Q,R)-chains.
(10) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LE(s(x), s(y)) → LE(x, y)
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
We have to consider all minimal (P,Q,R)-chains.
(11) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LOOP(x, s(y), z) → IF(le(x, s(y)), x, s(y), z)
IF(false, x, y, z) → LOOP(x, double(y), s(z))
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
We have to consider all minimal (P,Q,R)-chains.
(12) Obligation:
Q DP problem:
The TRS P consists of the following rules:
IFMAP(false, xs, ys) → MAPITER(droplast(xs), cons(log(last(xs)), ys))
MAPITER(xs, ys) → IFMAP(isempty(xs), xs, ys)
The TRS R consists of the following rules:
le(s(x), 0) → false
le(0, y) → true
le(s(x), s(y)) → le(x, y)
double(0) → 0
double(s(x)) → s(s(double(x)))
log(0) → logError
log(s(x)) → loop(s(x), s(0), 0)
loop(x, s(y), z) → if(le(x, s(y)), x, s(y), z)
if(true, x, y, z) → z
if(false, x, y, z) → loop(x, double(y), s(z))
maplog(xs) → mapIter(xs, nil)
mapIter(xs, ys) → ifmap(isempty(xs), xs, ys)
ifmap(true, xs, ys) → ys
ifmap(false, xs, ys) → mapIter(droplast(xs), cons(log(last(xs)), ys))
isempty(nil) → true
isempty(cons(x, xs)) → false
last(nil) → error
last(cons(x, nil)) → x
last(cons(x, cons(y, xs))) → last(cons(y, xs))
droplast(nil) → nil
droplast(cons(x, nil)) → nil
droplast(cons(x, cons(y, xs))) → cons(x, droplast(cons(y, xs)))
a → b
a → c
The set Q consists of the following terms:
le(s(x0), 0)
le(0, x0)
le(s(x0), s(x1))
double(0)
double(s(x0))
log(0)
log(s(x0))
loop(x0, s(x1), x2)
if(true, x0, x1, x2)
if(false, x0, x1, x2)
maplog(x0)
mapIter(x0, x1)
ifmap(true, x0, x1)
ifmap(false, x0, x1)
isempty(nil)
isempty(cons(x0, x1))
last(nil)
last(cons(x0, nil))
last(cons(x0, cons(x1, x2)))
droplast(nil)
droplast(cons(x0, nil))
droplast(cons(x0, cons(x1, x2)))
a
We have to consider all minimal (P,Q,R)-chains.