Termination w.r.t. Q proof of /tmp/tmpQepp4o/aprove03.trs

Termination w.r.t. Q of the given QTRS could not be shown:

0 QTRS

↳1 AAECC Innermost (⇔)

↳2 QTRS

↳3 DependencyPairsProof (⇔)

↳4 QDP

↳5 DependencyGraphProof (⇔)

↳6 AND

  ↳7 QDP

    ↳8 QDPOrderProof (⇔)

    ↳9 QDP

    ↳10 PisEmptyProof (⇔)

    ↳11 TRUE

  ↳12 QDP

    ↳13 QDPOrderProof (⇔)

    ↳14 QDP

    ↳15 PisEmptyProof (⇔)

    ↳16 TRUE

  ↳17 QDP

    ↳18 QDPOrderProof (⇔)

    ↳19 QDP

    ↳20 PisEmptyProof (⇔)

    ↳21 TRUE

  ↳22 QDP

  ↳23 QDP

    ↳24 QDPOrderProof (⇔)

    ↳25 QDP

    ↳26 PisEmptyProof (⇔)

    ↳27 TRUE

  ↳28 QDP

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

Q is empty.

(1) AAECC Innermost (EQUIVALENT transformation)

We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is

ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
quicksort(x) → ifquick(isempty(x), x)

The TRS R 2 is

a → b
a → c

The signature Sigma is {a, b, c}

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

(3) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

AVERAGE(x, y) → IF(ge(x, y), x, y)
AVERAGE(x, y) → GE(x, y)
IF(true, x, y) → AVERITER(y, x, y)
IF(false, x, y) → AVERITER(x, y, x)
AVERITER(x, y, z) → IFITER(ge(x, y), x, y, z)
AVERITER(x, y, z) → GE(x, y)
IFITER(false, x, y, z) → AVERITER(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
IFITER(false, x, y, z) → PLUS(x, s(s(s(0))))
IFITER(false, x, y, z) → PLUS(y, s(0))
IFITER(false, x, y, z) → PLUS(z, s(0))
LOW(n, cons(m, x)) → IF_LOW(ge(m, n), n, cons(m, x))
LOW(n, cons(m, x)) → GE(m, n)
IF_LOW(false, n, cons(m, x)) → LOW(n, x)
IF_LOW(true, n, cons(m, x)) → LOW(n, x)
HIGH(n, cons(m, x)) → IF_HIGH(ge(m, n), n, cons(m, x))
HIGH(n, cons(m, x)) → GE(m, n)
IF_HIGH(false, n, cons(m, x)) → HIGH(n, x)
IF_HIGH(true, n, cons(m, x)) → AVERAGE(m, m)
IF_HIGH(true, n, cons(m, x)) → HIGH(n, x)
QUICKSORT(x) → IFQUICK(isempty(x), x)
QUICKSORT(x) → ISEMPTY(x)
IFQUICK(false, x) → APPEND(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
IFQUICK(false, x) → QUICKSORT(low(head(x), tail(x)))
IFQUICK(false, x) → LOW(head(x), tail(x))
IFQUICK(false, x) → HEAD(x)
IFQUICK(false, x) → TAIL(x)
IFQUICK(false, x) → QUICKSORT(high(head(x), tail(x)))
IFQUICK(false, x) → HIGH(head(x), tail(x))
PLUS(s(x), y) → PLUS(x, y)
GE(s(x), s(y)) → GE(x, y)

The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(5) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 6 SCCs with 17 less nodes.

(6) Complex Obligation (AND)

(7) Obligation:

Q DP problem:
The TRS P consists of the following rules:

GE(s(x), s(y)) → GE(x, y)

The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(8) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

GE(s(x), s(y)) → GE(x, y)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
GE(x1, x2) = GE(x2)
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

s₁ > GE₁

Status:

GE₁: [1]
s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(9) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(10) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(11) TRUE

(12) Obligation:

Q DP problem:
The TRS P consists of the following rules:

PLUS(s(x), y) → PLUS(x, y)

The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(13) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

PLUS(s(x), y) → PLUS(x, y)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
PLUS(x1, x2) = x1
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

trivial

Status:

s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(14) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(15) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(16) TRUE

(17) Obligation:

Q DP problem:
The TRS P consists of the following rules:

IF_LOW(false, n, cons(m, x)) → LOW(n, x)
LOW(n, cons(m, x)) → IF_LOW(ge(m, n), n, cons(m, x))
IF_LOW(true, n, cons(m, x)) → LOW(n, x)

The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(18) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

IF_LOW(false, n, cons(m, x)) → LOW(n, x)
LOW(n, cons(m, x)) → IF_LOW(ge(m, n), n, cons(m, x))
IF_LOW(true, n, cons(m, x)) → LOW(n, x)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
IF_LOW(x1, x2, x3) = x3
false = false
cons(x1, x2) = cons(x2)
LOW(x1, x2) = LOW(x2)
ge(x1, x2) = ge
true = true
0 = 0
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

cons₁ > [false, LOW₁, ge, true, s₁]
0 > [false, LOW₁, ge, true, s₁]

Status:

false: []
cons₁: [1]
LOW₁: [1]
ge: []
true: []
0: []
s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(19) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(20) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(21) TRUE

(22) Obligation:

Q DP problem:
The TRS P consists of the following rules:

IFITER(false, x, y, z) → AVERITER(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
AVERITER(x, y, z) → IFITER(ge(x, y), x, y, z)

The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(23) Obligation:

Q DP problem:
The TRS P consists of the following rules:

IF_HIGH(false, n, cons(m, x)) → HIGH(n, x)
HIGH(n, cons(m, x)) → IF_HIGH(ge(m, n), n, cons(m, x))
IF_HIGH(true, n, cons(m, x)) → HIGH(n, x)

The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(24) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

IF_HIGH(false, n, cons(m, x)) → HIGH(n, x)
HIGH(n, cons(m, x)) → IF_HIGH(ge(m, n), n, cons(m, x))
IF_HIGH(true, n, cons(m, x)) → HIGH(n, x)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
IF_HIGH(x1, x2, x3) = x3
false = false
cons(x1, x2) = cons(x2)
HIGH(x1, x2) = HIGH(x2)
ge(x1, x2) = ge
true = true
0 = 0
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

cons₁ > [false, HIGH₁, ge, true, s₁]
0 > [false, HIGH₁, ge, true, s₁]

Status:

false: []
cons₁: [1]
HIGH₁: [1]
ge: []
true: []
0: []
s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(25) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.

(26) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(27) TRUE

(28) Obligation:

Q DP problem:
The TRS P consists of the following rules:

IFQUICK(false, x) → QUICKSORT(low(head(x), tail(x)))
QUICKSORT(x) → IFQUICK(isempty(x), x)
IFQUICK(false, x) → QUICKSORT(high(head(x), tail(x)))

The TRS R consists of the following rules:

average(x, y) → if(ge(x, y), x, y)
if(true, x, y) → averIter(y, x, y)
if(false, x, y) → averIter(x, y, x)
averIter(x, y, z) → ifIter(ge(x, y), x, y, z)
ifIter(true, x, y, z) → z
ifIter(false, x, y, z) → averIter(plus(x, s(s(s(0)))), plus(y, s(0)), plus(z, s(0)))
append(nil, y) → y
append(cons(n, x), y) → cons(n, app(x, y))
low(n, nil) → nil
low(n, cons(m, x)) → if_low(ge(m, n), n, cons(m, x))
if_low(false, n, cons(m, x)) → cons(m, low(n, x))
if_low(true, n, cons(m, x)) → low(n, x)
high(n, nil) → nil
high(n, cons(m, x)) → if_high(ge(m, n), n, cons(m, x))
if_high(false, n, cons(m, x)) → high(n, x)
if_high(true, n, cons(m, x)) → cons(average(m, m), high(n, x))
quicksort(x) → ifquick(isempty(x), x)
ifquick(true, x) → nil
ifquick(false, x) → append(quicksort(low(head(x), tail(x))), cons(tail(x), quicksort(high(head(x), tail(x)))))
plus(0, y) → y
plus(s(x), y) → s(plus(x, y))
isempty(nil) → true
isempty(cons(n, x)) → false
head(nil) → error
head(cons(n, x)) → n
tail(nil) → nil
tail(cons(n, x)) → x
ge(x, 0) → true
ge(0, s(y)) → false
ge(s(x), s(y)) → ge(x, y)
a → b
a → c

The set Q consists of the following terms:

average(x0, x1)
if(true, x0, x1)
if(false, x0, x1)
averIter(x0, x1, x2)
ifIter(true, x0, x1, x2)
ifIter(false, x0, x1, x2)
append(nil, x0)
append(cons(x0, x1), x2)
low(x0, nil)
low(x0, cons(x1, x2))
if_low(false, x0, cons(x1, x2))
if_low(true, x0, cons(x1, x2))
high(x0, nil)
high(x0, cons(x1, x2))
if_high(false, x0, cons(x1, x2))
if_high(true, x0, cons(x1, x2))
quicksort(x0)
ifquick(true, x0)
ifquick(false, x0)
plus(0, x0)
plus(s(x0), x1)
isempty(nil)
isempty(cons(x0, x1))
head(nil)
head(cons(x0, x1))
tail(nil)
tail(cons(x0, x1))
ge(x0, 0)
ge(0, s(x0))
ge(s(x0), s(x1))
a

We have to consider all minimal (P,Q,R)-chains.