(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f(f(y, z), f(x, f(a, x))) → f(f(f(a, z), f(x, a)), f(a, y))

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(f(y, z), f(x, f(a, x))) → F(f(f(a, z), f(x, a)), f(a, y))
F(f(y, z), f(x, f(a, x))) → F(f(a, z), f(x, a))
F(f(y, z), f(x, f(a, x))) → F(a, z)
F(f(y, z), f(x, f(a, x))) → F(x, a)
F(f(y, z), f(x, f(a, x))) → F(a, y)

The TRS R consists of the following rules:

f(f(y, z), f(x, f(a, x))) → f(f(f(a, z), f(x, a)), f(a, y))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 4 less nodes.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(f(y, z), f(x, f(a, x))) → F(f(f(a, z), f(x, a)), f(a, y))

The TRS R consists of the following rules:

f(f(y, z), f(x, f(a, x))) → f(f(f(a, z), f(x, a)), f(a, y))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(5) UsableRulesProof (EQUIVALENT transformation)

We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R.

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(f(y, z), f(x, f(a, x))) → F(f(f(a, z), f(x, a)), f(a, y))

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(7) Instantiation (EQUIVALENT transformation)

By instantiating [LPAR04] the rule F(f(y, z), f(x, f(a, x))) → F(f(f(a, z), f(x, a)), f(a, y)) we obtained the following new rules [LPAR04]:

F(f(f(a, z1), f(z2, a)), f(a, f(a, a))) → F(f(f(a, f(z2, a)), f(a, a)), f(a, f(a, z1)))

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(f(f(a, z1), f(z2, a)), f(a, f(a, a))) → F(f(f(a, f(z2, a)), f(a, a)), f(a, f(a, z1)))

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) Instantiation (EQUIVALENT transformation)

By instantiating [LPAR04] the rule F(f(f(a, z1), f(z2, a)), f(a, f(a, a))) → F(f(f(a, f(z2, a)), f(a, a)), f(a, f(a, z1))) we obtained the following new rules [LPAR04]:

F(f(f(a, f(z1, a)), f(a, a)), f(a, f(a, a))) → F(f(f(a, f(a, a)), f(a, a)), f(a, f(a, f(z1, a))))

(10) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(f(f(a, f(z1, a)), f(a, a)), f(a, f(a, a))) → F(f(f(a, f(a, a)), f(a, a)), f(a, f(a, f(z1, a))))

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(11) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node.

(12) TRUE