Termination w.r.t. Q of the given QTRS could be proven:

0 QTRS
↳1 DependencyPairsProof (⇔)
↳2 QDP
↳3 DependencyGraphProof (⇔)
↳4 AND
  ↳5 QDP
    ↳6 UsableRulesProof (⇔)
    ↳7 QDP
    ↳8 QDPSizeChangeProof (⇔)
    ↳9 TRUE
  ↳10 QDP
    ↳11 QDPOrderProof (⇔)
    ↳12 QDP
    ↳13 QDPOrderProof (⇔)
    ↳14 QDP
    ↳15 QDPOrderProof (⇔)
    ↳16 QDP
    ↳17 DependencyGraphProof (⇔)
    ↳18 QDP
    ↳19 QDPOrderProof (⇔)
    ↳20 QDP
    ↳21 QDPOrderProof (⇔)
    ↳22 QDP
    ↳23 QDPOrderProof (⇔)
    ↳24 QDP
    ↳25 QDPOrderProof (⇔)
    ↳26 QDP
    ↳27 DependencyGraphProof (⇔)
    ↳28 QDP
    ↳29 UsableRulesProof (⇔)
    ↳30 QDP
    ↳31 UsableRulesReductionPairsProof (⇔)
    ↳32 QDP
    ↳33 UsableRulesReductionPairsProof (⇔)
    ↳34 QDP
    ↳35 PisEmptyProof (⇔)
    ↳36 TRUE

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

INTERSECT'II'IN(Xs, cons(X0, Ys)) → U'1'1(intersect'ii'in(Xs, Ys))
INTERSECT'II'IN(Xs, cons(X0, Ys)) → INTERSECT'II'IN(Xs, Ys)
INTERSECT'II'IN(cons(X0, Xs), Ys) → U'2'1(intersect'ii'in(Xs, Ys))
INTERSECT'II'IN(cons(X0, Xs), Ys) → INTERSECT'II'IN(Xs, Ys)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → U'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → U'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → U'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → U'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → U'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → U'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(iff(A, B), Gs)), NF) → U'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
REDUCE'II'IN(sequent(Fs, cons(iff(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF)
REDUCE'II'IN(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → U'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
REDUCE'II'IN(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → REDUCE'II'IN(sequent(Fs, Gs), sequent(cons(p(V), Left), Right))
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → U'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → U'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, Gs)), NF)
U'12'1(reduce'ii'out, Fs, G2, Gs, NF) → U'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
U'12'1(reduce'ii'out, Fs, G2, Gs, NF) → REDUCE'II'IN(sequent(Fs, cons(G2, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → U'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)
REDUCE'II'IN(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → U'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
REDUCE'II'IN(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → REDUCE'II'IN(sequent(nil, Gs), sequent(Left, cons(p(V), Right)))
REDUCE'II'IN(sequent(nil, nil), sequent(F1, F2)) → U'15'1(intersect'ii'in(F1, F2))
REDUCE'II'IN(sequent(nil, nil), sequent(F1, F2)) → INTERSECT'II'IN(F1, F2)
TAUTOLOGY'I'IN(F) → U'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
TAUTOLOGY'I'IN(F) → REDUCE'II'IN(sequent(nil, cons(F, nil)), sequent(nil, nil))

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 18 less nodes.

(4) Complex Obligation (AND)

(5) Obligation:

Q DP problem:
The TRS P consists of the following rules:

INTERSECT'II'IN(cons(X0, Xs), Ys) → INTERSECT'II'IN(Xs, Ys)
INTERSECT'II'IN(Xs, cons(X0, Ys)) → INTERSECT'II'IN(Xs, Ys)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(6) UsableRulesProof (EQUIVALENT transformation)

We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R.

(7) Obligation:

Q DP problem:
The TRS P consists of the following rules:

INTERSECT'II'IN(cons(X0, Xs), Ys) → INTERSECT'II'IN(Xs, Ys)
INTERSECT'II'IN(Xs, cons(X0, Ys)) → INTERSECT'II'IN(Xs, Ys)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(8) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • INTERSECT'II'IN(cons(X0, Xs), Ys) → INTERSECT'II'IN(Xs, Ys)
    The graph contains the following edges 1 > 1, 2 >= 2

  • INTERSECT'II'IN(Xs, cons(X0, Ys)) → INTERSECT'II'IN(Xs, Ys)
    The graph contains the following edges 1 >= 1, 2 > 2

(9) TRUE

(10) Obligation:

Q DP problem:
The TRS P consists of the following rules:

REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → REDUCE'II'IN(sequent(Fs, Gs), sequent(cons(p(V), Left), Right))
REDUCE'II'IN(sequent(Fs, cons(iff(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → U'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
U'12'1(reduce'ii'out, Fs, G2, Gs, NF) → REDUCE'II'IN(sequent(Fs, cons(G2, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)
REDUCE'II'IN(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → REDUCE'II'IN(sequent(nil, Gs), sequent(Left, cons(p(V), Right)))

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(11) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


REDUCE'II'IN(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → REDUCE'II'IN(sequent(Fs, Gs), sequent(cons(p(V), Left), Right))
REDUCE'II'IN(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → REDUCE'II'IN(sequent(nil, Gs), sequent(Left, cons(p(V), Right)))
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO]:

POL(REDUCE'II'IN(x1, x2)) =
/0\
\0/
 +
/10\
\00/
·x1 +
/00\
\00/
·x2

POL(sequent(x1, x2)) =
/0\
\0/
 +
/01\
\00/
·x1 +
/01\
\00/
·x2

POL(cons(x1, x2)) =
/0\
\0/
 +
/00\
\11/
·x1 +
/00\
\01/
·x2

POL(x'2b(x1, x2)) =
/0\
\0/
 +
/00\
\11/
·x1 +
/10\
\01/
·x2

POL(U'6'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/11\
\00/
·x2 +
/01\
\00/
·x3 +
/01\
\00/
·x4 +
/00\
\00/
·x5

POL(reduce'ii'in(x1, x2)) =
/1\
\0/
 +
/00\
\00/
·x1 +
/01\
\01/
·x2

POL(reduce'ii'out) =
/0\
\1/

POL(if(x1, x2)) =
/0\
\0/
 +
/00\
\11/
·x1 +
/10\
\01/
·x2

POL(x'2d(x1)) =
/0\
\0/
 +
/00\
\11/
·x1

POL(iff(x1, x2)) =
/0\
\0/
 +
/11\
\11/
·x1 +
/11\
\11/
·x2

POL(x'2a(x1, x2)) =
/0\
\0/
 +
/11\
\00/
·x1 +
/10\
\01/
·x2

POL(p(x1)) =
/0\
\1/
 +
/00\
\00/
·x1

POL(U'12'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/01\
\00/
·x2 +
/11\
\00/
·x3 +
/01\
\00/
·x4 +
/00\
\00/
·x5

POL(nil) =
/0\
\1/

POL(u'9'1(x1)) =
/0\
\1/
 +
/00\
\01/
·x1

POL(u'10'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'11'1(x1)) =
/1\
\0/
 +
/11\
\00/
·x1

POL(u'12'1(x1, x2, x3, x4, x5)) =
/0\
\1/
 +
/00\
\01/
·x1 +
/11\
\01/
·x2 +
/00\
\11/
·x3 +
/11\
\01/
·x4 +
/10\
\01/
·x5

POL(u'12'2(x1)) =
/1\
\0/
 +
/10\
\00/
·x1

POL(u'13'1(x1)) =
/1\
\0/
 +
/11\
\00/
·x1

POL(u'14'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'15'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(intersect'ii'in(x1, x2)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/00\
\00/
·x2

POL(intersect'ii'out) =
/1\
\1/

POL(u'1'1(x1)) =
/0\
\0/
 +
/00\
\11/
·x1

POL(u'3'1(x1)) =
/0\
\1/
 +
/00\
\11/
·x1

POL(u'2'1(x1)) =
/0\
\0/
 +
/00\
\11/
·x1

POL(u'5'1(x1)) =
/0\
\0/
 +
/00\
\10/
·x1

POL(u'4'1(x1)) =
/0\
\0/
 +
/10\
\00/
·x1

POL(u'7'1(x1)) =
/0\
\0/
 +
/00\
\10/
·x1

POL(u'6'2(x1)) =
/1\
\1/
 +
/11\
\11/
·x1

POL(u'6'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\10/
·x1 +
/11\
\00/
·x2 +
/01\
\10/
·x3 +
/01\
\11/
·x4 +
/00\
\01/
·x5

POL(u'8'1(x1)) =
/1\
\1/
 +
/10\
\11/
·x1

The following usable rules [FROCOS05] were oriented: none

(12) Obligation:

Q DP problem:
The TRS P consists of the following rules:

REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(iff(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → U'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
U'12'1(reduce'ii'out, Fs, G2, Gs, NF) → REDUCE'II'IN(sequent(Fs, cons(G2, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(13) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


REDUCE'II'IN(sequent(Fs, cons(iff(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF)
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO]:

POL(REDUCE'II'IN(x1, x2)) =
/0\
\0/
 +
/10\
\00/
·x1 +
/00\
\00/
·x2

POL(sequent(x1, x2)) =
/0\
\0/
 +
/01\
\11/
·x1 +
/10\
\11/
·x2

POL(cons(x1, x2)) =
/0\
\0/
 +
/01\
\10/
·x1 +
/10\
\01/
·x2

POL(x'2b(x1, x2)) =
/0\
\0/
 +
/10\
\01/
·x1 +
/10\
\01/
·x2

POL(U'6'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/10\
\00/
·x2 +
/01\
\00/
·x3 +
/10\
\00/
·x4 +
/00\
\00/
·x5

POL(reduce'ii'in(x1, x2)) =
/0\
\1/
 +
/00\
\01/
·x1 +
/10\
\00/
·x2

POL(reduce'ii'out) =
/0\
\0/

POL(if(x1, x2)) =
/0\
\0/
 +
/10\
\01/
·x1 +
/01\
\10/
·x2

POL(x'2d(x1)) =
/0\
\0/
 +
/01\
\10/
·x1

POL(iff(x1, x2)) =
/0\
\1/
 +
/11\
\11/
·x1 +
/11\
\11/
·x2

POL(x'2a(x1, x2)) =
/0\
\0/
 +
/10\
\01/
·x1 +
/10\
\01/
·x2

POL(U'12'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/01\
\00/
·x2 +
/01\
\00/
·x3 +
/10\
\00/
·x4 +
/00\
\00/
·x5

POL(u'9'1(x1)) =
/0\
\0/
 +
/10\
\00/
·x1

POL(p(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'10'1(x1)) =
/1\
\1/
 +
/01\
\01/
·x1

POL(u'11'1(x1)) =
/1\
\0/
 +
/01\
\10/
·x1

POL(u'12'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\11/
·x1 +
/00\
\00/
·x2 +
/11\
\00/
·x3 +
/00\
\00/
·x4 +
/00\
\00/
·x5

POL(u'12'2(x1)) =
/0\
\0/
 +
/11\
\01/
·x1

POL(u'13'1(x1)) =
/0\
\1/
 +
/01\
\01/
·x1

POL(nil) =
/0\
\0/

POL(u'14'1(x1)) =
/1\
\1/
 +
/00\
\01/
·x1

POL(u'15'1(x1)) =
/0\
\0/
 +
/11\
\11/
·x1

POL(intersect'ii'in(x1, x2)) =
/0\
\0/
 +
/01\
\11/
·x1 +
/01\
\11/
·x2

POL(intersect'ii'out) =
/0\
\0/

POL(u'1'1(x1)) =
/1\
\0/
 +
/01\
\00/
·x1

POL(u'3'1(x1)) =
/0\
\0/
 +
/01\
\10/
·x1

POL(u'2'1(x1)) =
/1\
\0/
 +
/00\
\00/
·x1

POL(u'5'1(x1)) =
/0\
\0/
 +
/00\
\11/
·x1

POL(u'4'1(x1)) =
/1\
\0/
 +
/01\
\10/
·x1

POL(u'7'1(x1)) =
/0\
\0/
 +
/01\
\00/
·x1

POL(u'6'2(x1)) =
/1\
\0/
 +
/01\
\01/
·x1

POL(u'6'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/01\
\01/
·x1 +
/00\
\01/
·x2 +
/00\
\01/
·x3 +
/00\
\00/
·x4 +
/00\
\00/
·x5

POL(u'8'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

The following usable rules [FROCOS05] were oriented: none

(14) Obligation:

Q DP problem:
The TRS P consists of the following rules:

REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → U'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
U'12'1(reduce'ii'out, Fs, G2, Gs, NF) → REDUCE'II'IN(sequent(Fs, cons(G2, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(15) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


U'12'1(reduce'ii'out, Fs, G2, Gs, NF) → REDUCE'II'IN(sequent(Fs, cons(G2, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, Gs)), NF)
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO]:

POL(REDUCE'II'IN(x1, x2)) =
/0\
\0/
 +
/10\
\00/
·x1 +
/00\
\00/
·x2

POL(sequent(x1, x2)) =
/0\
\0/
 +
/10\
\00/
·x1 +
/01\
\10/
·x2

POL(cons(x1, x2)) =
/0\
\0/
 +
/01\
\10/
·x1 +
/10\
\01/
·x2

POL(x'2b(x1, x2)) =
/0\
\0/
 +
/10\
\01/
·x1 +
/10\
\01/
·x2

POL(U'6'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/01\
\00/
·x2 +
/10\
\00/
·x3 +
/01\
\00/
·x4 +
/00\
\00/
·x5

POL(reduce'ii'in(x1, x2)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/00\
\01/
·x2

POL(reduce'ii'out) =
/0\
\1/

POL(if(x1, x2)) =
/0\
\0/
 +
/10\
\01/
·x1 +
/01\
\10/
·x2

POL(x'2d(x1)) =
/0\
\0/
 +
/01\
\10/
·x1

POL(iff(x1, x2)) =
/0\
\0/
 +
/00\
\11/
·x1 +
/00\
\11/
·x2

POL(x'2a(x1, x2)) =
/1\
\0/
 +
/10\
\01/
·x1 +
/10\
\01/
·x2

POL(U'12'1(x1, x2, x3, x4, x5)) =
/1\
\0/
 +
/00\
\00/
·x1 +
/10\
\00/
·x2 +
/10\
\00/
·x3 +
/01\
\00/
·x4 +
/00\
\00/
·x5

POL(u'9'1(x1)) =
/1\
\0/
 +
/01\
\00/
·x1

POL(p(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'10'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'11'1(x1)) =
/1\
\0/
 +
/01\
\00/
·x1

POL(u'12'1(x1, x2, x3, x4, x5)) =
/0\
\1/
 +
/00\
\00/
·x1 +
/11\
\11/
·x2 +
/11\
\11/
·x3 +
/01\
\11/
·x4 +
/11\
\10/
·x5

POL(u'12'2(x1)) =
/1\
\0/
 +
/00\
\00/
·x1

POL(u'13'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(nil) =
/0\
\0/

POL(u'14'1(x1)) =
/1\
\0/
 +
/01\
\00/
·x1

POL(u'15'1(x1)) =
/0\
\1/
 +
/00\
\00/
·x1

POL(intersect'ii'in(x1, x2)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/00\
\00/
·x2

POL(intersect'ii'out) =
/1\
\1/

POL(u'1'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'3'1(x1)) =
/1\
\1/
 +
/01\
\00/
·x1

POL(u'2'1(x1)) =
/0\
\1/
 +
/00\
\10/
·x1

POL(u'5'1(x1)) =
/0\
\0/
 +
/01\
\00/
·x1

POL(u'4'1(x1)) =
/0\
\0/
 +
/01\
\01/
·x1

POL(u'7'1(x1)) =
/1\
\0/
 +
/01\
\00/
·x1

POL(u'6'2(x1)) =
/0\
\1/
 +
/00\
\00/
·x1

POL(u'6'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/11\
\11/
·x2 +
/11\
\11/
·x3 +
/11\
\11/
·x4 +
/00\
\10/
·x5

POL(u'8'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

The following usable rules [FROCOS05] were oriented: none

(16) Obligation:

Q DP problem:
The TRS P consists of the following rules:

REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → U'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(17) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node.

(18) Obligation:

Q DP problem:
The TRS P consists of the following rules:

U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(19) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


REDUCE'II'IN(sequent(cons(iff(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF)
The remaining pairs can at least be oriented weakly.
Used ordering: Matrix interpretation [MATRO]:

POL(U'6'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/11\
\00/
·x2 +
/10\
\00/
·x3 +
/10\
\00/
·x4 +
/00\
\00/
·x5

POL(reduce'ii'out) =
/1\
\1/

POL(REDUCE'II'IN(x1, x2)) =
/0\
\0/
 +
/01\
\00/
·x1 +
/00\
\00/
·x2

POL(sequent(x1, x2)) =
/0\
\0/
 +
/00\
\10/
·x1 +
/10\
\10/
·x2

POL(cons(x1, x2)) =
/0\
\0/
 +
/11\
\00/
·x1 +
/10\
\00/
·x2

POL(if(x1, x2)) =
/0\
\0/
 +
/10\
\01/
·x1 +
/10\
\01/
·x2

POL(x'2b(x1, x2)) =
/0\
\0/
 +
/01\
\10/
·x1 +
/11\
\00/
·x2

POL(x'2d(x1)) =
/0\
\0/
 +
/11\
\00/
·x1

POL(reduce'ii'in(x1, x2)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/01\
\10/
·x2

POL(iff(x1, x2)) =
/0\
\1/
 +
/11\
\11/
·x1 +
/11\
\11/
·x2

POL(x'2a(x1, x2)) =
/0\
\0/
 +
/10\
\01/
·x1 +
/10\
\01/
·x2

POL(u'9'1(x1)) =
/0\
\1/
 +
/00\
\00/
·x1

POL(p(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'10'1(x1)) =
/0\
\0/
 +
/11\
\00/
·x1

POL(u'11'1(x1)) =
/1\
\0/
 +
/11\
\10/
·x1

POL(u'12'1(x1, x2, x3, x4, x5)) =
/0\
\0/
 +
/11\
\11/
·x1 +
/10\
\00/
·x2 +
/00\
\00/
·x3 +
/11\
\01/
·x4 +
/00\
\10/
·x5

POL(u'12'2(x1)) =
/1\
\1/
 +
/11\
\10/
·x1

POL(u'13'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(nil) =
/0\
\0/

POL(u'14'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'15'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(intersect'ii'in(x1, x2)) =
/0\
\0/
 +
/00\
\00/
·x1 +
/00\
\10/
·x2

POL(intersect'ii'out) =
/1\
\1/

POL(u'1'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'3'1(x1)) =
/1\
\1/
 +
/00\
\00/
·x1

POL(u'2'1(x1)) =
/0\
\0/
 +
/11\
\00/
·x1

POL(u'5'1(x1)) =
/1\
\1/
 +
/00\
\00/
·x1

POL(u'4'1(x1)) =
/1\
\1/
 +
/00\
\00/
·x1

POL(u'7'1(x1)) =
/0\
\0/
 +
/00\
\00/
·x1

POL(u'6'2(x1)) =
/0\
\0/
 +
/01\
\00/
·x1

POL(u'6'1(x1, x2, x3, x4, x5)) =
/0\
\1/
 +
/11\
\00/
·x1 +
/10\
\11/
·x2 +
/11\
\10/
·x3 +
/10\
\11/
·x4 +
/00\
\00/
·x5

POL(u'8'1(x1)) =
/1\
\0/
 +
/00\
\00/
·x1

The following usable rules [FROCOS05] were oriented: none

(20) Obligation:

Q DP problem:
The TRS P consists of the following rules:

U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(21) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


REDUCE'II'IN(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, cons(F2, Fs)), Gs), NF)
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO]:

POL(REDUCE'II'IN(x1, x2)) = x1   
POL(U'6'1(x1, x2, x3, x4, x5)) = x2 + x3 + x4   
POL(cons(x1, x2)) = x1 + x2   
POL(if(x1, x2)) = x1 + x2   
POL(iff(x1, x2)) = 0   
POL(intersect'ii'in(x1, x2)) = 0   
POL(intersect'ii'out) = 0   
POL(nil) = 0   
POL(p(x1)) = 0   
POL(reduce'ii'in(x1, x2)) = 0   
POL(reduce'ii'out) = 0   
POL(sequent(x1, x2)) = x1 + x2   
POL(u'1'1(x1)) = 0   
POL(u'10'1(x1)) = 0   
POL(u'11'1(x1)) = 0   
POL(u'12'1(x1, x2, x3, x4, x5)) = 0   
POL(u'12'2(x1)) = 0   
POL(u'13'1(x1)) = 0   
POL(u'14'1(x1)) = 0   
POL(u'15'1(x1)) = 0   
POL(u'2'1(x1)) = 0   
POL(u'3'1(x1)) = 0   
POL(u'4'1(x1)) = 0   
POL(u'5'1(x1)) = 0   
POL(u'6'1(x1, x2, x3, x4, x5)) = 0   
POL(u'6'2(x1)) = 0   
POL(u'7'1(x1)) = 0   
POL(u'8'1(x1)) = 0   
POL(u'9'1(x1)) = 0   
POL(x'2a(x1, x2)) = 1 + x1 + x2   
POL(x'2b(x1, x2)) = x1 + x2   
POL(x'2d(x1)) = x1   

The following usable rules [FROCOS05] were oriented: none

(22) Obligation:

Q DP problem:
The TRS P consists of the following rules:

U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(23) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


REDUCE'II'IN(sequent(cons(x'2d(F1), Fs), Gs), NF) → REDUCE'II'IN(sequent(Fs, cons(F1, Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2d(G1), Gs)), NF) → REDUCE'II'IN(sequent(cons(G1, Fs), Gs), NF)
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO]:

POL(REDUCE'II'IN(x1, x2)) = x1   
POL(U'6'1(x1, x2, x3, x4, x5)) = x2 + x3 + x4   
POL(cons(x1, x2)) = x1 + x2   
POL(if(x1, x2)) = 1 + x1 + x2   
POL(iff(x1, x2)) = 0   
POL(intersect'ii'in(x1, x2)) = 0   
POL(intersect'ii'out) = 0   
POL(nil) = 0   
POL(p(x1)) = 0   
POL(reduce'ii'in(x1, x2)) = 0   
POL(reduce'ii'out) = 0   
POL(sequent(x1, x2)) = x1 + x2   
POL(u'1'1(x1)) = 0   
POL(u'10'1(x1)) = 0   
POL(u'11'1(x1)) = 0   
POL(u'12'1(x1, x2, x3, x4, x5)) = 0   
POL(u'12'2(x1)) = 0   
POL(u'13'1(x1)) = 0   
POL(u'14'1(x1)) = 0   
POL(u'15'1(x1)) = 0   
POL(u'2'1(x1)) = 0   
POL(u'3'1(x1)) = 0   
POL(u'4'1(x1)) = 0   
POL(u'5'1(x1)) = 0   
POL(u'6'1(x1, x2, x3, x4, x5)) = 0   
POL(u'6'2(x1)) = 0   
POL(u'7'1(x1)) = 0   
POL(u'8'1(x1)) = 0   
POL(u'9'1(x1)) = 0   
POL(x'2a(x1, x2)) = 0   
POL(x'2b(x1, x2)) = x1 + x2   
POL(x'2d(x1)) = 1 + x1   

The following usable rules [FROCOS05] were oriented: none

(24) Obligation:

Q DP problem:
The TRS P consists of the following rules:

U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(25) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → U'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
REDUCE'II'IN(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(F1, Fs), Gs), NF)
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO]:

POL(REDUCE'II'IN(x1, x2)) = x1   
POL(U'6'1(x1, x2, x3, x4, x5)) = 1 + x2   
POL(cons(x1, x2)) = x1   
POL(if(x1, x2)) = 1 + x1   
POL(iff(x1, x2)) = 0   
POL(intersect'ii'in(x1, x2)) = x1 + x2   
POL(intersect'ii'out) = 0   
POL(nil) = 0   
POL(p(x1)) = 0   
POL(reduce'ii'in(x1, x2)) = 0   
POL(reduce'ii'out) = 0   
POL(sequent(x1, x2)) = 1 + x1   
POL(u'1'1(x1)) = 0   
POL(u'10'1(x1)) = 0   
POL(u'11'1(x1)) = 0   
POL(u'12'1(x1, x2, x3, x4, x5)) = 0   
POL(u'12'2(x1)) = 0   
POL(u'13'1(x1)) = 0   
POL(u'14'1(x1)) = 0   
POL(u'15'1(x1)) = 0   
POL(u'2'1(x1)) = 0   
POL(u'3'1(x1)) = 0   
POL(u'4'1(x1)) = 0   
POL(u'5'1(x1)) = 0   
POL(u'6'1(x1, x2, x3, x4, x5)) = 0   
POL(u'6'2(x1)) = 0   
POL(u'7'1(x1)) = 0   
POL(u'8'1(x1)) = 0   
POL(u'9'1(x1)) = 0   
POL(x'2a(x1, x2)) = 0   
POL(x'2b(x1, x2)) = 1 + x1 + x2   
POL(x'2d(x1)) = 0   

The following usable rules [FROCOS05] were oriented: none

(26) Obligation:

Q DP problem:
The TRS P consists of the following rules:

U'6'1(reduce'ii'out, F2, Fs, Gs, NF) → REDUCE'II'IN(sequent(cons(F2, Fs), Gs), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(27) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node.

(28) Obligation:

Q DP problem:
The TRS P consists of the following rules:

REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)

The TRS R consists of the following rules:

intersect'ii'in(cons(X, X0), cons(X, X1)) → intersect'ii'out
intersect'ii'in(Xs, cons(X0, Ys)) → u'1'1(intersect'ii'in(Xs, Ys))
u'1'1(intersect'ii'out) → intersect'ii'out
intersect'ii'in(cons(X0, Xs), Ys) → u'2'1(intersect'ii'in(Xs, Ys))
u'2'1(intersect'ii'out) → intersect'ii'out
reduce'ii'in(sequent(cons(if(A, B), Fs), Gs), NF) → u'3'1(reduce'ii'in(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF))
u'3'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(iff(A, B), Fs), Gs), NF) → u'4'1(reduce'ii'in(sequent(cons(x'2a(if(A, B), if(B, A)), Fs), Gs), NF))
u'4'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2a(F1, F2), Fs), Gs), NF) → u'5'1(reduce'ii'in(sequent(cons(F1, cons(F2, Fs)), Gs), NF))
u'5'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2b(F1, F2), Fs), Gs), NF) → u'6'1(reduce'ii'in(sequent(cons(F1, Fs), Gs), NF), F2, Fs, Gs, NF)
u'6'1(reduce'ii'out, F2, Fs, Gs, NF) → u'6'2(reduce'ii'in(sequent(cons(F2, Fs), Gs), NF))
u'6'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(x'2d(F1), Fs), Gs), NF) → u'7'1(reduce'ii'in(sequent(Fs, cons(F1, Gs)), NF))
u'7'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(if(A, B), Gs)), NF) → u'8'1(reduce'ii'in(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF))
u'8'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(iff(A, B), Gs)), NF) → u'9'1(reduce'ii'in(sequent(Fs, cons(x'2a(if(A, B), if(B, A)), Gs)), NF))
u'9'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(cons(p(V), Fs), Gs), sequent(Left, Right)) → u'10'1(reduce'ii'in(sequent(Fs, Gs), sequent(cons(p(V), Left), Right)))
u'10'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → u'11'1(reduce'ii'in(sequent(Fs, cons(G1, cons(G2, Gs))), NF))
u'11'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2a(G1, G2), Gs)), NF) → u'12'1(reduce'ii'in(sequent(Fs, cons(G1, Gs)), NF), Fs, G2, Gs, NF)
u'12'1(reduce'ii'out, Fs, G2, Gs, NF) → u'12'2(reduce'ii'in(sequent(Fs, cons(G2, Gs)), NF))
u'12'2(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(Fs, cons(x'2d(G1), Gs)), NF) → u'13'1(reduce'ii'in(sequent(cons(G1, Fs), Gs), NF))
u'13'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, cons(p(V), Gs)), sequent(Left, Right)) → u'14'1(reduce'ii'in(sequent(nil, Gs), sequent(Left, cons(p(V), Right))))
u'14'1(reduce'ii'out) → reduce'ii'out
reduce'ii'in(sequent(nil, nil), sequent(F1, F2)) → u'15'1(intersect'ii'in(F1, F2))
u'15'1(intersect'ii'out) → reduce'ii'out
tautology'i'in(F) → u'16'1(reduce'ii'in(sequent(nil, cons(F, nil)), sequent(nil, nil)))
u'16'1(reduce'ii'out) → tautology'i'out

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(29) UsableRulesProof (EQUIVALENT transformation)

We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R.

(30) Obligation:

Q DP problem:
The TRS P consists of the following rules:

REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(31) UsableRulesReductionPairsProof (EQUIVALENT transformation)

By using the usable rules with reduction pair processor [LPAR04] with a polynomial ordering [POLO], all dependency pairs and the corresponding usable rules [FROCOS05] can be oriented non-strictly. All non-usable rules are removed, and those dependency pairs and usable rules that have been oriented strictly or contain non-usable symbols in their left-hand side are removed as well.

The following dependency pairs can be deleted:

REDUCE'II'IN(sequent(Fs, cons(if(A, B), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(x'2b(x'2d(B), A), Gs)), NF)
REDUCE'II'IN(sequent(cons(if(A, B), Fs), Gs), NF) → REDUCE'II'IN(sequent(cons(x'2b(x'2d(B), A), Fs), Gs), NF)
No rules are removed from R.

Used ordering: POLO with Polynomial interpretation [POLO]:

POL(REDUCE'II'IN(x1, x2)) = x1 + x2   
POL(cons(x1, x2)) = 1 + x1 + x2   
POL(if(x1, x2)) = 2 + 2·x1 + 2·x2   
POL(sequent(x1, x2)) = x1 + x2   
POL(x'2b(x1, x2)) = 1 + 2·x1 + x2   
POL(x'2d(x1)) = x1   

(32) Obligation:

Q DP problem:
The TRS P consists of the following rules:

REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(33) UsableRulesReductionPairsProof (EQUIVALENT transformation)

By using the usable rules with reduction pair processor [LPAR04] with a polynomial ordering [POLO], all dependency pairs and the corresponding usable rules [FROCOS05] can be oriented non-strictly. All non-usable rules are removed, and those dependency pairs and usable rules that have been oriented strictly or contain non-usable symbols in their left-hand side are removed as well.

The following dependency pairs can be deleted:

REDUCE'II'IN(sequent(Fs, cons(x'2b(G1, G2), Gs)), NF) → REDUCE'II'IN(sequent(Fs, cons(G1, cons(G2, Gs))), NF)
No rules are removed from R.

Used ordering: POLO with Polynomial interpretation [POLO]:

POL(REDUCE'II'IN(x1, x2)) = x1 + x2   
POL(cons(x1, x2)) = x1 + x2   
POL(sequent(x1, x2)) = x1 + x2   
POL(x'2b(x1, x2)) = 1 + 2·x1 + x2   

(34) Obligation:

Q DP problem:
P is empty.
R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(35) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(36) TRUE