Termination w.r.t. Q of the given QTRS could be proven:

0 QTRS
↳1 Overlay + Local Confluence (⇔)
↳2 QTRS
↳3 DependencyPairsProof (⇔)
↳4 QDP
↳5 DependencyGraphProof (⇔)
↳6 AND
  ↳7 QDP
    ↳8 UsableRulesProof (⇔)
    ↳9 QDP
    ↳10 ATransformationProof (⇔)
    ↳11 QDP
    ↳12 QReductionProof (⇔)
    ↳13 QDP
    ↳14 QDPSizeChangeProof (⇔)
    ↳15 TRUE
  ↳16 QDP
    ↳17 UsableRulesProof (⇔)
    ↳18 QDP
    ↳19 ATransformationProof (⇔)
    ↳20 QDP
    ↳21 QReductionProof (⇔)
    ↳22 QDP
    ↳23 QDPSizeChangeProof (⇔)
    ↳24 TRUE
  ↳25 QDP
    ↳26 UsableRulesProof (⇔)
    ↳27 QDP
    ↳28 ATransformationProof (⇔)
    ↳29 QDP
    ↳30 QReductionProof (⇔)
    ↳31 QDP
    ↳32 QDPOrderProof (⇔)
    ↳33 QDP
    ↳34 DependencyGraphProof (⇔)
    ↳35 TRUE
  ↳36 QDP
    ↳37 UsableRulesProof (⇔)
    ↳38 QDP
    ↳39 ATransformationProof (⇔)
    ↳40 QDP
    ↳41 QReductionProof (⇔)
    ↳42 QDP
    ↳43 QDPSizeChangeProof (⇔)
    ↳44 TRUE
  ↳45 QDP
    ↳46 UsableRulesProof (⇔)
    ↳47 QDP
    ↳48 ATransformationProof (⇔)
    ↳49 QDP
    ↳50 QReductionProof (⇔)
    ↳51 QDP
    ↳52 QDPSizeChangeProof (⇔)
    ↳53 TRUE
  ↳54 QDP
    ↳55 UsableRulesProof (⇔)
    ↳56 QDP
    ↳57 ATransformationProof (⇔)
    ↳58 QDP
    ↳59 QReductionProof (⇔)
    ↳60 QDP
    ↳61 QDPOrderProof (⇔)
    ↳62 QDP
    ↳63 UsableRulesProof (⇔)
    ↳64 QDP
    ↳65 QReductionProof (⇔)
    ↳66 QDP
    ↳67 QDPSizeChangeProof (⇔)
    ↳68 TRUE
  ↳69 QDP
    ↳70 QDPSizeChangeProof (⇔)
    ↳71 TRUE

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

Q is empty.

(1) Overlay + Local Confluence (EQUIVALENT transformation)

The TRS is overlay and locally confluent. By [NOC] we can switch to innermost.

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

(3) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(eq, app'(s, x)), app'(s, y)) → APP'(app'(eq, x), y)
APP'(app'(eq, app'(s, x)), app'(s, y)) → APP'(eq, x)
APP'(app'(le, app'(s, x)), app'(s, y)) → APP'(app'(le, x), y)
APP'(app'(le, app'(s, x)), app'(s, y)) → APP'(le, x)
APP'(app'(app, app'(app'(add, n), x)), y) → APP'(app'(add, n), app'(app'(app, x), y))
APP'(app'(app, app'(app'(add, n), x)), y) → APP'(app'(app, x), y)
APP'(app'(app, app'(app'(add, n), x)), y) → APP'(app, x)
APP'(min, app'(app'(add, n), app'(app'(add, m), x))) → APP'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
APP'(min, app'(app'(add, n), app'(app'(add, m), x))) → APP'(if_min, app'(app'(le, n), m))
APP'(min, app'(app'(add, n), app'(app'(add, m), x))) → APP'(app'(le, n), m)
APP'(min, app'(app'(add, n), app'(app'(add, m), x))) → APP'(le, n)
APP'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → APP'(min, app'(app'(add, n), x))
APP'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → APP'(app'(add, n), x)
APP'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → APP'(min, app'(app'(add, m), x))
APP'(app'(rm, n), app'(app'(add, m), x)) → APP'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
APP'(app'(rm, n), app'(app'(add, m), x)) → APP'(app'(if_rm, app'(app'(eq, n), m)), n)
APP'(app'(rm, n), app'(app'(add, m), x)) → APP'(if_rm, app'(app'(eq, n), m))
APP'(app'(rm, n), app'(app'(add, m), x)) → APP'(app'(eq, n), m)
APP'(app'(rm, n), app'(app'(add, m), x)) → APP'(eq, n)
APP'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → APP'(app'(rm, n), x)
APP'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → APP'(rm, n)
APP'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → APP'(app'(add, m), app'(app'(rm, n), x))
APP'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → APP'(app'(rm, n), x)
APP'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → APP'(rm, n)
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x))
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x))))
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(app'(eq, n), app'(min, app'(app'(add, n), x)))
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(eq, n)
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(min, app'(app'(add, n), x))
APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil)
APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(minsort, app'(app'(app, app'(app'(rm, n), x)), y))
APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(app'(app, app'(app'(rm, n), x)), y)
APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(app, app'(app'(rm, n), x))
APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(app'(rm, n), x)
APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(rm, n)
APP'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → APP'(app'(minsort, x), app'(app'(add, n), y))
APP'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → APP'(minsort, x)
APP'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → APP'(app'(add, n), y)
APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(app'(add, app'(f, x)), app'(app'(map, f), xs))
APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(add, app'(f, x))
APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(f, x)
APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(app'(map, f), xs)
APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(app'(app'(filter2, app'(f, x)), f), x)
APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(app'(filter2, app'(f, x)), f)
APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(filter2, app'(f, x))
APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(f, x)
APP'(app'(app'(app'(filter2, true), f), x), xs) → APP'(app'(add, x), app'(app'(filter, f), xs))
APP'(app'(app'(app'(filter2, true), f), x), xs) → APP'(add, x)
APP'(app'(app'(app'(filter2, true), f), x), xs) → APP'(app'(filter, f), xs)
APP'(app'(app'(app'(filter2, true), f), x), xs) → APP'(filter, f)
APP'(app'(app'(app'(filter2, false), f), x), xs) → APP'(app'(filter, f), xs)
APP'(app'(app'(app'(filter2, false), f), x), xs) → APP'(filter, f)

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(5) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 7 SCCs with 37 less nodes.

(6) Complex Obligation (AND)

(7) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(app, app'(app'(add, n), x)), y) → APP'(app'(app, x), y)

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(8) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(9) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(app, app'(app'(add, n), x)), y) → APP'(app'(app, x), y)

R is empty.
The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(10) ATransformationProof (EQUIVALENT transformation)

We have applied the A-Transformation [FROCOS05] to get from an applicative problem to a standard problem.

(11) Obligation:

Q DP problem:
The TRS P consists of the following rules:

app1(add(n, x), y) → app1(x, y)

R is empty.
The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

We have to consider all minimal (P,Q,R)-chains.

(12) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

(13) Obligation:

Q DP problem:
The TRS P consists of the following rules:

app1(add(n, x), y) → app1(x, y)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(14) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • app1(add(n, x), y) → app1(x, y)
    The graph contains the following edges 1 > 1, 2 >= 2

(15) TRUE

(16) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(le, app'(s, x)), app'(s, y)) → APP'(app'(le, x), y)

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(17) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(18) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(le, app'(s, x)), app'(s, y)) → APP'(app'(le, x), y)

R is empty.
The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(19) ATransformationProof (EQUIVALENT transformation)

We have applied the A-Transformation [FROCOS05] to get from an applicative problem to a standard problem.

(20) Obligation:

Q DP problem:
The TRS P consists of the following rules:

le1(s(x), s(y)) → le1(x, y)

R is empty.
The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

We have to consider all minimal (P,Q,R)-chains.

(21) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

(22) Obligation:

Q DP problem:
The TRS P consists of the following rules:

le1(s(x), s(y)) → le1(x, y)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(23) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • le1(s(x), s(y)) → le1(x, y)
    The graph contains the following edges 1 > 1, 2 > 2

(24) TRUE

(25) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(min, app'(app'(add, n), app'(app'(add, m), x))) → APP'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
APP'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → APP'(min, app'(app'(add, n), x))
APP'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → APP'(min, app'(app'(add, m), x))

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(26) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(27) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(min, app'(app'(add, n), app'(app'(add, m), x))) → APP'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
APP'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → APP'(min, app'(app'(add, n), x))
APP'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → APP'(min, app'(app'(add, m), x))

The TRS R consists of the following rules:

app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(28) ATransformationProof (EQUIVALENT transformation)

We have applied the A-Transformation [FROCOS05] to get from an applicative problem to a standard problem.

(29) Obligation:

Q DP problem:
The TRS P consists of the following rules:

min1(add(n, add(m, x))) → if_min1(le(n, m), add(n, add(m, x)))
if_min1(true, add(n, add(m, x))) → min1(add(n, x))
if_min1(false, add(n, add(m, x))) → min1(add(m, x))

The TRS R consists of the following rules:

le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

We have to consider all minimal (P,Q,R)-chains.

(30) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

(31) Obligation:

Q DP problem:
The TRS P consists of the following rules:

min1(add(n, add(m, x))) → if_min1(le(n, m), add(n, add(m, x)))
if_min1(true, add(n, add(m, x))) → min1(add(n, x))
if_min1(false, add(n, add(m, x))) → min1(add(m, x))

The TRS R consists of the following rules:

le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)

The set Q consists of the following terms:

le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))

We have to consider all minimal (P,Q,R)-chains.

(32) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


if_min1(true, add(n, add(m, x))) → min1(add(n, x))
if_min1(false, add(n, add(m, x))) → min1(add(m, x))
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO]:

POL(0) = 0   
POL(add(x1, x2)) = 1 + x2   
POL(false) = 0   
POL(if_min1(x1, x2)) = 1 + x2   
POL(le(x1, x2)) = 0   
POL(min1(x1)) = 1 + x1   
POL(s(x1)) = 0   
POL(true) = 0   

The following usable rules [FROCOS05] were oriented: none

(33) Obligation:

Q DP problem:
The TRS P consists of the following rules:

min1(add(n, add(m, x))) → if_min1(le(n, m), add(n, add(m, x)))

The TRS R consists of the following rules:

le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)

The set Q consists of the following terms:

le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))

We have to consider all minimal (P,Q,R)-chains.

(34) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node.

(35) TRUE

(36) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(eq, app'(s, x)), app'(s, y)) → APP'(app'(eq, x), y)

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(37) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(38) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(eq, app'(s, x)), app'(s, y)) → APP'(app'(eq, x), y)

R is empty.
The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(39) ATransformationProof (EQUIVALENT transformation)

We have applied the A-Transformation [FROCOS05] to get from an applicative problem to a standard problem.

(40) Obligation:

Q DP problem:
The TRS P consists of the following rules:

eq1(s(x), s(y)) → eq1(x, y)

R is empty.
The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

We have to consider all minimal (P,Q,R)-chains.

(41) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

(42) Obligation:

Q DP problem:
The TRS P consists of the following rules:

eq1(s(x), s(y)) → eq1(x, y)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(43) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • eq1(s(x), s(y)) → eq1(x, y)
    The graph contains the following edges 1 > 1, 2 > 2

(44) TRUE

(45) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(rm, n), app'(app'(add, m), x)) → APP'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
APP'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → APP'(app'(rm, n), x)
APP'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → APP'(app'(rm, n), x)

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(46) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(47) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(rm, n), app'(app'(add, m), x)) → APP'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
APP'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → APP'(app'(rm, n), x)
APP'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → APP'(app'(rm, n), x)

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(48) ATransformationProof (EQUIVALENT transformation)

We have applied the A-Transformation [FROCOS05] to get from an applicative problem to a standard problem.

(49) Obligation:

Q DP problem:
The TRS P consists of the following rules:

rm1(n, add(m, x)) → if_rm1(eq(n, m), n, add(m, x))
if_rm1(true, n, add(m, x)) → rm1(n, x)
if_rm1(false, n, add(m, x)) → rm1(n, x)

The TRS R consists of the following rules:

eq(0, 0) → true
eq(0, s(x)) → false
eq(s(x), 0) → false
eq(s(x), s(y)) → eq(x, y)

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

We have to consider all minimal (P,Q,R)-chains.

(50) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

(51) Obligation:

Q DP problem:
The TRS P consists of the following rules:

rm1(n, add(m, x)) → if_rm1(eq(n, m), n, add(m, x))
if_rm1(true, n, add(m, x)) → rm1(n, x)
if_rm1(false, n, add(m, x)) → rm1(n, x)

The TRS R consists of the following rules:

eq(0, 0) → true
eq(0, s(x)) → false
eq(s(x), 0) → false
eq(s(x), s(y)) → eq(x, y)

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))

We have to consider all minimal (P,Q,R)-chains.

(52) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • rm1(n, add(m, x)) → if_rm1(eq(n, m), n, add(m, x))
    The graph contains the following edges 1 >= 2, 2 >= 3

  • if_rm1(true, n, add(m, x)) → rm1(n, x)
    The graph contains the following edges 2 >= 1, 3 > 2

  • if_rm1(false, n, add(m, x)) → rm1(n, x)
    The graph contains the following edges 2 >= 1, 3 > 2

(53) TRUE

(54) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil)
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
APP'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → APP'(app'(minsort, x), app'(app'(add, n), y))

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(55) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(56) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → APP'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil)
APP'(app'(minsort, app'(app'(add, n), x)), y) → APP'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
APP'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → APP'(app'(minsort, x), app'(app'(add, n), y))

The TRS R consists of the following rules:

app'(min, app'(app'(add, n), nil)) → n
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(57) ATransformationProof (EQUIVALENT transformation)

We have applied the A-Transformation [FROCOS05] to get from an applicative problem to a standard problem.

(58) Obligation:

Q DP problem:
The TRS P consists of the following rules:

if_minsort1(true, add(n, x), y) → minsort1(app(rm(n, x), y), nil)
minsort1(add(n, x), y) → if_minsort1(eq(n, min(add(n, x))), add(n, x), y)
if_minsort1(false, add(n, x), y) → minsort1(x, add(n, y))

The TRS R consists of the following rules:

min(add(n, nil)) → n
if_min(true, add(n, add(m, x))) → min(add(n, x))
min(add(n, add(m, x))) → if_min(le(n, m), add(n, add(m, x)))
if_min(false, add(n, add(m, x))) → min(add(m, x))
eq(0, 0) → true
eq(0, s(x)) → false
eq(s(x), 0) → false
eq(s(x), s(y)) → eq(x, y)
le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)
rm(n, nil) → nil
rm(n, add(m, x)) → if_rm(eq(n, m), n, add(m, x))
if_rm(true, n, add(m, x)) → rm(n, x)
app(nil, y) → y
app(add(n, x), y) → add(n, app(x, y))
if_rm(false, n, add(m, x)) → add(m, rm(n, x))

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))
minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

We have to consider all minimal (P,Q,R)-chains.

(59) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

minsort(nil, nil)
minsort(add(x0, x1), x2)
if_minsort(true, add(x0, x1), x2)
if_minsort(false, add(x0, x1), x2)
map(x0, nil)
map(x0, add(x1, x2))
filter(x0, nil)
filter(x0, add(x1, x2))
filter2(true, x0, x1, x2)
filter2(false, x0, x1, x2)

(60) Obligation:

Q DP problem:
The TRS P consists of the following rules:

if_minsort1(true, add(n, x), y) → minsort1(app(rm(n, x), y), nil)
minsort1(add(n, x), y) → if_minsort1(eq(n, min(add(n, x))), add(n, x), y)
if_minsort1(false, add(n, x), y) → minsort1(x, add(n, y))

The TRS R consists of the following rules:

min(add(n, nil)) → n
if_min(true, add(n, add(m, x))) → min(add(n, x))
min(add(n, add(m, x))) → if_min(le(n, m), add(n, add(m, x)))
if_min(false, add(n, add(m, x))) → min(add(m, x))
eq(0, 0) → true
eq(0, s(x)) → false
eq(s(x), 0) → false
eq(s(x), s(y)) → eq(x, y)
le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)
rm(n, nil) → nil
rm(n, add(m, x)) → if_rm(eq(n, m), n, add(m, x))
if_rm(true, n, add(m, x)) → rm(n, x)
app(nil, y) → y
app(add(n, x), y) → add(n, app(x, y))
if_rm(false, n, add(m, x)) → add(m, rm(n, x))

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))

We have to consider all minimal (P,Q,R)-chains.

(61) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].


The following pairs can be oriented strictly and are deleted.


if_minsort1(true, add(n, x), y) → minsort1(app(rm(n, x), y), nil)
The remaining pairs can at least be oriented weakly.
Used ordering: Polynomial interpretation [POLO]:

POL(0) = 1   
POL(add(x1, x2)) = 1 + x2   
POL(app(x1, x2)) = x1 + x2   
POL(eq(x1, x2)) = x1   
POL(false) = 0   
POL(if_min(x1, x2)) = 0   
POL(if_minsort1(x1, x2, x3)) = 1 + x2 + x3   
POL(if_rm(x1, x2, x3)) = x3   
POL(le(x1, x2)) = 0   
POL(min(x1)) = 0   
POL(minsort1(x1, x2)) = 1 + x1 + x2   
POL(nil) = 0   
POL(rm(x1, x2)) = x2   
POL(s(x1)) = x1   
POL(true) = 0   

The following usable rules [FROCOS05] were oriented:

app(nil, y) → y
app(add(n, x), y) → add(n, app(x, y))
if_rm(false, n, add(m, x)) → add(m, rm(n, x))
rm(n, nil) → nil
if_rm(true, n, add(m, x)) → rm(n, x)
rm(n, add(m, x)) → if_rm(eq(n, m), n, add(m, x))

(62) Obligation:

Q DP problem:
The TRS P consists of the following rules:

minsort1(add(n, x), y) → if_minsort1(eq(n, min(add(n, x))), add(n, x), y)
if_minsort1(false, add(n, x), y) → minsort1(x, add(n, y))

The TRS R consists of the following rules:

min(add(n, nil)) → n
if_min(true, add(n, add(m, x))) → min(add(n, x))
min(add(n, add(m, x))) → if_min(le(n, m), add(n, add(m, x)))
if_min(false, add(n, add(m, x))) → min(add(m, x))
eq(0, 0) → true
eq(0, s(x)) → false
eq(s(x), 0) → false
eq(s(x), s(y)) → eq(x, y)
le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)
rm(n, nil) → nil
rm(n, add(m, x)) → if_rm(eq(n, m), n, add(m, x))
if_rm(true, n, add(m, x)) → rm(n, x)
app(nil, y) → y
app(add(n, x), y) → add(n, app(x, y))
if_rm(false, n, add(m, x)) → add(m, rm(n, x))

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))

We have to consider all minimal (P,Q,R)-chains.

(63) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(64) Obligation:

Q DP problem:
The TRS P consists of the following rules:

minsort1(add(n, x), y) → if_minsort1(eq(n, min(add(n, x))), add(n, x), y)
if_minsort1(false, add(n, x), y) → minsort1(x, add(n, y))

The TRS R consists of the following rules:

min(add(n, nil)) → n
min(add(n, add(m, x))) → if_min(le(n, m), add(n, add(m, x)))
if_min(false, add(n, add(m, x))) → min(add(m, x))
if_min(true, add(n, add(m, x))) → min(add(n, x))
eq(0, 0) → true
eq(0, s(x)) → false
eq(s(x), 0) → false
eq(s(x), s(y)) → eq(x, y)
le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
app(nil, x0)
app(add(x0, x1), x2)
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))

We have to consider all minimal (P,Q,R)-chains.

(65) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

app(nil, x0)
app(add(x0, x1), x2)
rm(x0, nil)
rm(x0, add(x1, x2))
if_rm(true, x0, add(x1, x2))
if_rm(false, x0, add(x1, x2))

(66) Obligation:

Q DP problem:
The TRS P consists of the following rules:

minsort1(add(n, x), y) → if_minsort1(eq(n, min(add(n, x))), add(n, x), y)
if_minsort1(false, add(n, x), y) → minsort1(x, add(n, y))

The TRS R consists of the following rules:

min(add(n, nil)) → n
min(add(n, add(m, x))) → if_min(le(n, m), add(n, add(m, x)))
if_min(false, add(n, add(m, x))) → min(add(m, x))
if_min(true, add(n, add(m, x))) → min(add(n, x))
eq(0, 0) → true
eq(0, s(x)) → false
eq(s(x), 0) → false
eq(s(x), s(y)) → eq(x, y)
le(0, y) → true
le(s(x), 0) → false
le(s(x), s(y)) → le(x, y)

The set Q consists of the following terms:

eq(0, 0)
eq(0, s(x0))
eq(s(x0), 0)
eq(s(x0), s(x1))
le(0, x0)
le(s(x0), 0)
le(s(x0), s(x1))
min(add(x0, nil))
min(add(x0, add(x1, x2)))
if_min(true, add(x0, add(x1, x2)))
if_min(false, add(x0, add(x1, x2)))

We have to consider all minimal (P,Q,R)-chains.

(67) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • if_minsort1(false, add(n, x), y) → minsort1(x, add(n, y))
    The graph contains the following edges 2 > 1

  • minsort1(add(n, x), y) → if_minsort1(eq(n, min(add(n, x))), add(n, x), y)
    The graph contains the following edges 1 >= 2, 2 >= 3

(68) TRUE

(69) Obligation:

Q DP problem:
The TRS P consists of the following rules:

APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(app'(map, f), xs)
APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(f, x)
APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
APP'(app'(app'(app'(filter2, true), f), x), xs) → APP'(app'(filter, f), xs)
APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(f, x)
APP'(app'(app'(app'(filter2, false), f), x), xs) → APP'(app'(filter, f), xs)

The TRS R consists of the following rules:

app'(app'(eq, 0), 0) → true
app'(app'(eq, 0), app'(s, x)) → false
app'(app'(eq, app'(s, x)), 0) → false
app'(app'(eq, app'(s, x)), app'(s, y)) → app'(app'(eq, x), y)
app'(app'(le, 0), y) → true
app'(app'(le, app'(s, x)), 0) → false
app'(app'(le, app'(s, x)), app'(s, y)) → app'(app'(le, x), y)
app'(app'(app, nil), y) → y
app'(app'(app, app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(app, x), y))
app'(min, app'(app'(add, n), nil)) → n
app'(min, app'(app'(add, n), app'(app'(add, m), x))) → app'(app'(if_min, app'(app'(le, n), m)), app'(app'(add, n), app'(app'(add, m), x)))
app'(app'(if_min, true), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, n), x))
app'(app'(if_min, false), app'(app'(add, n), app'(app'(add, m), x))) → app'(min, app'(app'(add, m), x))
app'(app'(rm, n), nil) → nil
app'(app'(rm, n), app'(app'(add, m), x)) → app'(app'(app'(if_rm, app'(app'(eq, n), m)), n), app'(app'(add, m), x))
app'(app'(app'(if_rm, true), n), app'(app'(add, m), x)) → app'(app'(rm, n), x)
app'(app'(app'(if_rm, false), n), app'(app'(add, m), x)) → app'(app'(add, m), app'(app'(rm, n), x))
app'(app'(minsort, nil), nil) → nil
app'(app'(minsort, app'(app'(add, n), x)), y) → app'(app'(app'(if_minsort, app'(app'(eq, n), app'(min, app'(app'(add, n), x)))), app'(app'(add, n), x)), y)
app'(app'(app'(if_minsort, true), app'(app'(add, n), x)), y) → app'(app'(add, n), app'(app'(minsort, app'(app'(app, app'(app'(rm, n), x)), y)), nil))
app'(app'(app'(if_minsort, false), app'(app'(add, n), x)), y) → app'(app'(minsort, x), app'(app'(add, n), y))
app'(app'(map, f), nil) → nil
app'(app'(map, f), app'(app'(add, x), xs)) → app'(app'(add, app'(f, x)), app'(app'(map, f), xs))
app'(app'(filter, f), nil) → nil
app'(app'(filter, f), app'(app'(add, x), xs)) → app'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
app'(app'(app'(app'(filter2, true), f), x), xs) → app'(app'(add, x), app'(app'(filter, f), xs))
app'(app'(app'(app'(filter2, false), f), x), xs) → app'(app'(filter, f), xs)

The set Q consists of the following terms:

app'(app'(eq, 0), 0)
app'(app'(eq, 0), app'(s, x0))
app'(app'(eq, app'(s, x0)), 0)
app'(app'(eq, app'(s, x0)), app'(s, x1))
app'(app'(le, 0), x0)
app'(app'(le, app'(s, x0)), 0)
app'(app'(le, app'(s, x0)), app'(s, x1))
app'(app'(app, nil), x0)
app'(app'(app, app'(app'(add, x0), x1)), x2)
app'(min, app'(app'(add, x0), nil))
app'(min, app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, true), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(if_min, false), app'(app'(add, x0), app'(app'(add, x1), x2)))
app'(app'(rm, x0), nil)
app'(app'(rm, x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, true), x0), app'(app'(add, x1), x2))
app'(app'(app'(if_rm, false), x0), app'(app'(add, x1), x2))
app'(app'(minsort, nil), nil)
app'(app'(minsort, app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, true), app'(app'(add, x0), x1)), x2)
app'(app'(app'(if_minsort, false), app'(app'(add, x0), x1)), x2)
app'(app'(map, x0), nil)
app'(app'(map, x0), app'(app'(add, x1), x2))
app'(app'(filter, x0), nil)
app'(app'(filter, x0), app'(app'(add, x1), x2))
app'(app'(app'(app'(filter2, true), x0), x1), x2)
app'(app'(app'(app'(filter2, false), x0), x1), x2)

We have to consider all minimal (P,Q,R)-chains.

(70) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(f, x)
    The graph contains the following edges 1 > 1, 2 > 2

  • APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(f, x)
    The graph contains the following edges 1 > 1, 2 > 2

  • APP'(app'(map, f), app'(app'(add, x), xs)) → APP'(app'(map, f), xs)
    The graph contains the following edges 1 >= 1, 2 > 2

  • APP'(app'(filter, f), app'(app'(add, x), xs)) → APP'(app'(app'(app'(filter2, app'(f, x)), f), x), xs)
    The graph contains the following edges 2 > 2

  • APP'(app'(app'(app'(filter2, true), f), x), xs) → APP'(app'(filter, f), xs)
    The graph contains the following edges 2 >= 2

  • APP'(app'(app'(app'(filter2, false), f), x), xs) → APP'(app'(filter, f), xs)
    The graph contains the following edges 2 >= 2

(71) TRUE