(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
f(t, x, y) → f(g(x, y), x, s(y))
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
Q is empty.
(1) AAECC Innermost (EQUIVALENT transformation)
We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
The TRS R 2 is
f(t, x, y) → f(g(x, y), x, s(y))
The signature Sigma is {
f}
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
f(t, x, y) → f(g(x, y), x, s(y))
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
The set Q consists of the following terms:
f(t, x0, x1)
g(s(x0), 0)
g(s(x0), s(x1))
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
(4) Obligation:
Q DP problem:
The TRS P consists of the following rules:
F(t, x, y) → F(g(x, y), x, s(y))
F(t, x, y) → G(x, y)
G(s(x), s(y)) → G(x, y)
The TRS R consists of the following rules:
f(t, x, y) → f(g(x, y), x, s(y))
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
The set Q consists of the following terms:
f(t, x0, x1)
g(s(x0), 0)
g(s(x0), s(x1))
We have to consider all minimal (P,Q,R)-chains.
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 1 less node.
(6) Complex Obligation (AND)
(7) Obligation:
Q DP problem:
The TRS P consists of the following rules:
G(s(x), s(y)) → G(x, y)
The TRS R consists of the following rules:
f(t, x, y) → f(g(x, y), x, s(y))
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
The set Q consists of the following terms:
f(t, x0, x1)
g(s(x0), 0)
g(s(x0), s(x1))
We have to consider all minimal (P,Q,R)-chains.
(8) QDPOrderProof (EQUIVALENT transformation)
We use the reduction pair processor [LPAR04].
The following pairs can be oriented strictly and are deleted.
G(s(x), s(y)) → G(x, y)
The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
G(
x1,
x2) =
x1
s(
x1) =
s(
x1)
f(
x1,
x2,
x3) =
x2
t =
t
g(
x1,
x2) =
g(
x1,
x2)
0 =
0
Lexicographic Path Order [LPO].
Precedence:
s1 > [t, g2]
0 > [t, g2]
The following usable rules [FROCOS05] were oriented:
f(t, x, y) → f(g(x, y), x, s(y))
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
(9) Obligation:
Q DP problem:
P is empty.
The TRS R consists of the following rules:
f(t, x, y) → f(g(x, y), x, s(y))
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
The set Q consists of the following terms:
f(t, x0, x1)
g(s(x0), 0)
g(s(x0), s(x1))
We have to consider all minimal (P,Q,R)-chains.
(10) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
(11) TRUE
(12) Obligation:
Q DP problem:
The TRS P consists of the following rules:
F(t, x, y) → F(g(x, y), x, s(y))
The TRS R consists of the following rules:
f(t, x, y) → f(g(x, y), x, s(y))
g(s(x), 0) → t
g(s(x), s(y)) → g(x, y)
The set Q consists of the following terms:
f(t, x0, x1)
g(s(x0), 0)
g(s(x0), s(x1))
We have to consider all minimal (P,Q,R)-chains.