(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f(x, a(b(y))) → f(a(b(x)), y)
f(a(x), y) → f(x, a(y))
f(b(x), y) → f(x, b(y))

Q is empty.

(1) AAECC Innermost (EQUIVALENT transformation)

We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is none

The TRS R 2 is

f(x, a(b(y))) → f(a(b(x)), y)
f(a(x), y) → f(x, a(y))
f(b(x), y) → f(x, b(y))

The signature Sigma is {f}

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

f(x, a(b(y))) → f(a(b(x)), y)
f(a(x), y) → f(x, a(y))
f(b(x), y) → f(x, b(y))

The set Q consists of the following terms:

f(x0, a(b(x1)))
f(a(x0), x1)
f(b(x0), x1)

(3) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(4) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(x, a(b(y))) → F(a(b(x)), y)
F(a(x), y) → F(x, a(y))
F(b(x), y) → F(x, b(y))

The TRS R consists of the following rules:

f(x, a(b(y))) → f(a(b(x)), y)
f(a(x), y) → f(x, a(y))
f(b(x), y) → f(x, b(y))

The set Q consists of the following terms:

f(x0, a(b(x1)))
f(a(x0), x1)
f(b(x0), x1)

We have to consider all minimal (P,Q,R)-chains.

(5) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(6) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(x, a(b(y))) → F(a(b(x)), y)
F(a(x), y) → F(x, a(y))
F(b(x), y) → F(x, b(y))

R is empty.
The set Q consists of the following terms:

f(x0, a(b(x1)))
f(a(x0), x1)
f(b(x0), x1)

We have to consider all minimal (P,Q,R)-chains.

(7) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

f(x0, a(b(x1)))
f(a(x0), x1)
f(b(x0), x1)

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

F(x, a(b(y))) → F(a(b(x)), y)
F(a(x), y) → F(x, a(y))
F(b(x), y) → F(x, b(y))

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) QDPToSRSProof (SOUND transformation)

The finiteness of this DP problem is implied by strong termination of a SRS due to [UNKNOWN].

(10) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(b(x)) → b(a(x))

Q is empty.

(11) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(12) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(x)) → A(x)

The TRS R consists of the following rules:

a(b(x)) → b(a(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(13) MNOCProof (EQUIVALENT transformation)

We use the modular non-overlap check [LPAR04] to enlarge Q to all left-hand sides of R.

(14) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(x)) → A(x)

The TRS R consists of the following rules:

a(b(x)) → b(a(x))

The set Q consists of the following terms:

a(b(x0))

We have to consider all minimal (P,Q,R)-chains.

(15) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(16) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(x)) → A(x)

R is empty.
The set Q consists of the following terms:

a(b(x0))

We have to consider all minimal (P,Q,R)-chains.

(17) QReductionProof (EQUIVALENT transformation)

We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN].

a(b(x0))

(18) Obligation:

Q DP problem:
The TRS P consists of the following rules:

A(b(x)) → A(x)

R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(19) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • A(b(x)) → A(x)
    The graph contains the following edges 1 > 1

(20) TRUE