Termination w.r.t. Q proof of /tmp/tmpcZ6vgO/maude2.trs

Termination w.r.t. Q of the given QTRS could not be shown:

0 QTRS

↳1 DependencyPairsProof (⇔)

↳2 QDP

↳3 DependencyGraphProof (⇔)

↳4 AND

  ↳5 QDP

    ↳6 QDPOrderProof (⇔)

    ↳7 QDP

    ↳8 PisEmptyProof (⇔)

    ↳9 TRUE

  ↳10 QDP

    ↳11 QDPOrderProof (⇔)

    ↳12 QDP

    ↳13 PisEmptyProof (⇔)

    ↳14 TRUE

  ↳15 QDP

  ↳16 QDP

  ↳17 QDP

    ↳18 QDPOrderProof (⇔)

    ↳19 QDP

    ↳20 PisEmptyProof (⇔)

    ↳21 TRUE

  ↳22 QDP

    ↳23 QDPOrderProof (⇔)

    ↳24 QDP

    ↳25 PisEmptyProof (⇔)

    ↳26 TRUE

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

+¹(s(N), s(M)) → +¹(N, M)
*¹(s(N), s(M)) → +¹(N, +(M, *(N, M)))
*¹(s(N), s(M)) → +¹(M, *(N, M))
*¹(s(N), s(M)) → *¹(N, M)
GT(NzN, 0) → U_4(is_NzNat(NzN))
GT(NzN, 0) → IS_NZNAT(NzN)
GT(s(N), s(M)) → GT(N, M)
LT(N, M) → GT(M, N)
D(s(N), s(M)) → D(N, M)
QUOT(N, NzM) → U_11(is_NzNat(NzM), N, NzM)
QUOT(N, NzM) → IS_NZNAT(NzM)
U_11(True, N, NzM) → U_1(gt(N, NzM), N, NzM)
U_11(True, N, NzM) → GT(N, NzM)
U_1(True, N, NzM) → QUOT(d(N, NzM), NzM)
U_1(True, N, NzM) → D(N, NzM)
QUOT(NzM, NzM) → U_01(is_NzNat(NzM))
QUOT(NzM, NzM) → IS_NZNAT(NzM)
QUOT(N, NzM) → U_21(is_NzNat(NzM), NzM, N)
U_21(True, NzM, N) → U_2(gt(NzM, N))
U_21(True, NzM, N) → GT(NzM, N)
GCD(NzM, NzM) → U_02(is_NzNat(NzM), NzM)
GCD(NzM, NzM) → IS_NZNAT(NzM)
GCD(NzN, NzM) → U_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
GCD(NzN, NzM) → IS_NZNAT(NzN)
GCD(NzN, NzM) → IS_NZNAT(NzM)
U_31(True, True, NzN, NzM) → U_3(gt(NzN, NzM), NzN, NzM)
U_31(True, True, NzN, NzM) → GT(NzN, NzM)
U_3(True, NzN, NzM) → GCD(d(NzN, NzM), NzM)
U_3(True, NzN, NzM) → D(NzN, NzM)

The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 6 SCCs with 19 less nodes.

(4) Complex Obligation (AND)

(5) Obligation:

Q DP problem:
The TRS P consists of the following rules:

D(s(N), s(M)) → D(N, M)

The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(6) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

D(s(N), s(M)) → D(N, M)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
D(x1, x2) = D(x2)
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

trivial

Status:

D₁: [1]
s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(7) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(8) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(9) TRUE

(10) Obligation:

Q DP problem:
The TRS P consists of the following rules:

GT(s(N), s(M)) → GT(N, M)

The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(11) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

GT(s(N), s(M)) → GT(N, M)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
GT(x1, x2) = GT(x2)
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

trivial

Status:

GT₁: [1]
s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(12) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(13) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(14) TRUE

(15) Obligation:

Q DP problem:
The TRS P consists of the following rules:

U_31(True, True, NzN, NzM) → U_3(gt(NzN, NzM), NzN, NzM)
U_3(True, NzN, NzM) → GCD(d(NzN, NzM), NzM)
GCD(NzN, NzM) → U_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)

The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(16) Obligation:

Q DP problem:
The TRS P consists of the following rules:

U_11(True, N, NzM) → U_1(gt(N, NzM), N, NzM)
U_1(True, N, NzM) → QUOT(d(N, NzM), NzM)
QUOT(N, NzM) → U_11(is_NzNat(NzM), N, NzM)

The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(17) Obligation:

Q DP problem:
The TRS P consists of the following rules:

+¹(s(N), s(M)) → +¹(N, M)

The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(18) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

+¹(s(N), s(M)) → +¹(N, M)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
+¹(x1, x2) = +¹(x2)
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

trivial

Status:

+^1₁: [1]
s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(19) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(20) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(21) TRUE

(22) Obligation:

Q DP problem:
The TRS P consists of the following rules:

*¹(s(N), s(M)) → *¹(N, M)

The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(23) QDPOrderProof (EQUIVALENT transformation)

We use the reduction pair processor [LPAR04].

The following pairs can be oriented strictly and are deleted.

*¹(s(N), s(M)) → *¹(N, M)

The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
*¹(x1, x2) = *¹(x2)
s(x1) = s(x1)

Lexicographic path order with status [LPO].
Quasi-Precedence:

trivial

Status:

*^1₁: [1]
s₁: [1]

The following usable rules [FROCOS05] were oriented: none

(24) Obligation:

Q DP problem:
P is empty.
The TRS R consists of the following rules:

p(s(N)) → N
+(N, 0) → N
+(s(N), s(M)) → s(s(+(N, M)))
*(N, 0) → 0
*(s(N), s(M)) → s(+(N, +(M, *(N, M))))
gt(0, M) → False
gt(NzN, 0) → u_4(is_NzNat(NzN))
u_4(True) → True
is_NzNat(0) → False
is_NzNat(s(N)) → True
gt(s(N), s(M)) → gt(N, M)
lt(N, M) → gt(M, N)
d(0, N) → N
d(s(N), s(M)) → d(N, M)
quot(N, NzM) → u_11(is_NzNat(NzM), N, NzM)
u_11(True, N, NzM) → u_1(gt(N, NzM), N, NzM)
u_1(True, N, NzM) → s(quot(d(N, NzM), NzM))
quot(NzM, NzM) → u_01(is_NzNat(NzM))
u_01(True) → s(0)
quot(N, NzM) → u_21(is_NzNat(NzM), NzM, N)
u_21(True, NzM, N) → u_2(gt(NzM, N))
u_2(True) → 0
gcd(0, N) → 0
gcd(NzM, NzM) → u_02(is_NzNat(NzM), NzM)
u_02(True, NzM) → NzM
gcd(NzN, NzM) → u_31(is_NzNat(NzN), is_NzNat(NzM), NzN, NzM)
u_31(True, True, NzN, NzM) → u_3(gt(NzN, NzM), NzN, NzM)
u_3(True, NzN, NzM) → gcd(d(NzN, NzM), NzM)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(25) PisEmptyProof (EQUIVALENT transformation)

The TRS P is empty. Hence, there is no (P,Q,R) chain.

(0) Obligation:

(1) DependencyPairsProof (EQUIVALENT transformation)

(2) Obligation:

(3) DependencyGraphProof (EQUIVALENT transformation)

(4) Complex Obligation (AND)

(5) Obligation:

(6) QDPOrderProof (EQUIVALENT transformation)

(7) Obligation:

(8) PisEmptyProof (EQUIVALENT transformation)

(9) TRUE

(10) Obligation:

(11) QDPOrderProof (EQUIVALENT transformation)

(12) Obligation:

(13) PisEmptyProof (EQUIVALENT transformation)

(14) TRUE

(15) Obligation:

(16) Obligation:

(17) Obligation:

(18) QDPOrderProof (EQUIVALENT transformation)

(19) Obligation:

(20) PisEmptyProof (EQUIVALENT transformation)

(21) TRUE

(22) Obligation:

(23) QDPOrderProof (EQUIVALENT transformation)

(24) Obligation:

(25) PisEmptyProof (EQUIVALENT transformation)

(26) TRUE