(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
Q is empty.
(1) Overlay + Local Confluence (EQUIVALENT transformation)
The TRS is overlay and locally confluent. By [NOC] we can switch to innermost.
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
The set Q consists of the following terms:
half(0)
half(s(s(x0)))
log(s(0))
log(s(s(x0)))
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
(4) Obligation:
Q DP problem:
The TRS P consists of the following rules:
HALF(s(s(x))) → HALF(x)
LOG(s(s(x))) → LOG(s(half(x)))
LOG(s(s(x))) → HALF(x)
The TRS R consists of the following rules:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
The set Q consists of the following terms:
half(0)
half(s(s(x0)))
log(s(0))
log(s(s(x0)))
We have to consider all minimal (P,Q,R)-chains.
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 1 less node.
(6) Complex Obligation (AND)
(7) Obligation:
Q DP problem:
The TRS P consists of the following rules:
HALF(s(s(x))) → HALF(x)
The TRS R consists of the following rules:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
The set Q consists of the following terms:
half(0)
half(s(s(x0)))
log(s(0))
log(s(s(x0)))
We have to consider all minimal (P,Q,R)-chains.
(8) QDPOrderProof (EQUIVALENT transformation)
We use the reduction pair processor [LPAR04].
The following pairs can be oriented strictly and are deleted.
HALF(s(s(x))) → HALF(x)
The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
HALF(
x1) =
x1
s(
x1) =
s(
x1)
half(
x1) =
half(
x1)
0 =
0
log(
x1) =
log(
x1)
Lexicographic Path Order [LPO].
Precedence:
log1 > [s1, 0] > half1
The following usable rules [FROCOS05] were oriented:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
(9) Obligation:
Q DP problem:
P is empty.
The TRS R consists of the following rules:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
The set Q consists of the following terms:
half(0)
half(s(s(x0)))
log(s(0))
log(s(s(x0)))
We have to consider all minimal (P,Q,R)-chains.
(10) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
(11) TRUE
(12) Obligation:
Q DP problem:
The TRS P consists of the following rules:
LOG(s(s(x))) → LOG(s(half(x)))
The TRS R consists of the following rules:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
The set Q consists of the following terms:
half(0)
half(s(s(x0)))
log(s(0))
log(s(s(x0)))
We have to consider all minimal (P,Q,R)-chains.
(13) QDPOrderProof (EQUIVALENT transformation)
We use the reduction pair processor [LPAR04].
The following pairs can be oriented strictly and are deleted.
LOG(s(s(x))) → LOG(s(half(x)))
The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
LOG(
x1) =
x1
s(
x1) =
s(
x1)
half(
x1) =
x1
0 =
0
log(
x1) =
log(
x1)
Lexicographic Path Order [LPO].
Precedence:
[s1, log1] > 0
The following usable rules [FROCOS05] were oriented:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
(14) Obligation:
Q DP problem:
P is empty.
The TRS R consists of the following rules:
half(0) → 0
half(s(s(x))) → s(half(x))
log(s(0)) → 0
log(s(s(x))) → s(log(s(half(x))))
The set Q consists of the following terms:
half(0)
half(s(s(x0)))
log(s(0))
log(s(s(x0)))
We have to consider all minimal (P,Q,R)-chains.
(15) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
(16) TRUE