(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
f(0, y) → 0
f(s(x), y) → f(f(x, y), y)
Q is empty.
(1) Overlay + Local Confluence (EQUIVALENT transformation)
The TRS is overlay and locally confluent. By [NOC] we can switch to innermost.
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
f(0, y) → 0
f(s(x), y) → f(f(x, y), y)
The set Q consists of the following terms:
f(0, x0)
f(s(x0), x1)
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
(4) Obligation:
Q DP problem:
The TRS P consists of the following rules:
F(s(x), y) → F(f(x, y), y)
F(s(x), y) → F(x, y)
The TRS R consists of the following rules:
f(0, y) → 0
f(s(x), y) → f(f(x, y), y)
The set Q consists of the following terms:
f(0, x0)
f(s(x0), x1)
We have to consider all minimal (P,Q,R)-chains.
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node.
(6) Obligation:
Q DP problem:
The TRS P consists of the following rules:
F(s(x), y) → F(x, y)
The TRS R consists of the following rules:
f(0, y) → 0
f(s(x), y) → f(f(x, y), y)
The set Q consists of the following terms:
f(0, x0)
f(s(x0), x1)
We have to consider all minimal (P,Q,R)-chains.
(7) QDPOrderProof (EQUIVALENT transformation)
We use the reduction pair processor [LPAR04].
The following pairs can be oriented strictly and are deleted.
F(s(x), y) → F(x, y)
The remaining pairs can at least be oriented weakly.
Used ordering: Recursive path order with status [RPO].
Quasi-Precedence:
trivial
Status:
s1: [1]
F2: [1,2]
The following usable rules [FROCOS05] were oriented:
none
(8) Obligation:
Q DP problem:
P is empty.
The TRS R consists of the following rules:
f(0, y) → 0
f(s(x), y) → f(f(x, y), y)
The set Q consists of the following terms:
f(0, x0)
f(s(x0), x1)
We have to consider all minimal (P,Q,R)-chains.
(9) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
(10) TRUE