Termination w.r.t. Q of the following Term Rewriting System could be proven:
Q restricted rewrite system:
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
Q is empty.
↳ QTRS
↳ Overlay + Local Confluence
Q restricted rewrite system:
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
Q is empty.
The TRS is overlay and locally confluent. By [19] we can switch to innermost.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
The set Q consists of the following terms:
h(f(x0, x1))
Using Dependency Pairs [1,15] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
H(f(x, y)) → H(h(x))
H(f(x, y)) → H(x)
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
The set Q consists of the following terms:
h(f(x0, x1))
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ Narrowing
Q DP problem:
The TRS P consists of the following rules:
H(f(x, y)) → H(h(x))
H(f(x, y)) → H(x)
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
The set Q consists of the following terms:
h(f(x0, x1))
We have to consider all minimal (P,Q,R)-chains.
By narrowing [15] the rule H(f(x, y)) → H(h(x)) at position [0] we obtained the following new rules:
H(f(f(x0, x1), y1)) → H(f(x1, f(h(h(x0)), a)))
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ Narrowing
↳ QDP
↳ ForwardInstantiation
Q DP problem:
The TRS P consists of the following rules:
H(f(f(x0, x1), y1)) → H(f(x1, f(h(h(x0)), a)))
H(f(x, y)) → H(x)
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
The set Q consists of the following terms:
h(f(x0, x1))
We have to consider all minimal (P,Q,R)-chains.
By forward instantiating [14] the rule H(f(x, y)) → H(x) we obtained the following new rules:
H(f(f(f(y_0, y_1), y_2), x1)) → H(f(f(y_0, y_1), y_2))
H(f(f(y_0, y_1), x1)) → H(f(y_0, y_1))
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ Narrowing
↳ QDP
↳ ForwardInstantiation
↳ QDP
↳ MNOCProof
↳ QDPOrderProof
Q DP problem:
The TRS P consists of the following rules:
H(f(f(x0, x1), y1)) → H(f(x1, f(h(h(x0)), a)))
H(f(f(f(y_0, y_1), y_2), x1)) → H(f(f(y_0, y_1), y_2))
H(f(f(y_0, y_1), x1)) → H(f(y_0, y_1))
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
The set Q consists of the following terms:
h(f(x0, x1))
We have to consider all minimal (P,Q,R)-chains.
We use the modular non-overlap check [17] to decrease Q to the empty set.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ Narrowing
↳ QDP
↳ ForwardInstantiation
↳ QDP
↳ MNOCProof
↳ QDP
↳ QDPOrderProof
Q DP problem:
The TRS P consists of the following rules:
H(f(f(x0, x1), y1)) → H(f(x1, f(h(h(x0)), a)))
H(f(f(f(y_0, y_1), y_2), x1)) → H(f(f(y_0, y_1), y_2))
H(f(f(y_0, y_1), x1)) → H(f(y_0, y_1))
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
Q is empty.
We have to consider all (P,Q,R)-chains.
We use the reduction pair processor [15].
The following pairs can be oriented strictly and are deleted.
H(f(f(x0, x1), y1)) → H(f(x1, f(h(h(x0)), a)))
H(f(f(f(y_0, y_1), y_2), x1)) → H(f(f(y_0, y_1), y_2))
H(f(f(y_0, y_1), x1)) → H(f(y_0, y_1))
The remaining pairs can at least be oriented weakly.
none
Used ordering: Matrix interpretation [3]:
Non-tuple symbols:
M( f(x1, x2) ) = | | + | | · | x1 | + | | · | x2 |
Tuple symbols:
Matrix type:
We used a basic matrix type which is not further parametrizeable.
As matrix orders are CE-compatible, we used usable rules w.r.t. argument filtering in the order.
The following usable rules [17] were oriented:
h(f(x, y)) → f(y, f(h(h(x)), a))
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ Narrowing
↳ QDP
↳ ForwardInstantiation
↳ QDP
↳ MNOCProof
↳ QDPOrderProof
↳ QDP
↳ PisEmptyProof
Q DP problem:
P is empty.
The TRS R consists of the following rules:
h(f(x, y)) → f(y, f(h(h(x)), a))
The set Q consists of the following terms:
h(f(x0, x1))
We have to consider all minimal (P,Q,R)-chains.
The TRS P is empty. Hence, there is no (P,Q,R) chain.