Termination w.r.t. Q of the following Term Rewriting System could be proven:
Q restricted rewrite system:
The TRS R consists of the following rules:
0(0(*(*(x1)))) → *(*(1(1(x1))))
1(1(*(*(x1)))) → 0(0(#(#(x1))))
#(#(0(0(x1)))) → 0(0(#(#(x1))))
#(#(1(1(x1)))) → 1(1(#(#(x1))))
#(#($($(x1)))) → *(*($($(x1))))
#(#(#(#(x1)))) → #(#(x1))
#(#(*(*(x1)))) → *(*(x1))
Q is empty.
↳ QTRS
↳ DirectTerminationProof
Q restricted rewrite system:
The TRS R consists of the following rules:
0(0(*(*(x1)))) → *(*(1(1(x1))))
1(1(*(*(x1)))) → 0(0(#(#(x1))))
#(#(0(0(x1)))) → 0(0(#(#(x1))))
#(#(1(1(x1)))) → 1(1(#(#(x1))))
#(#($($(x1)))) → *(*($($(x1))))
#(#(#(#(x1)))) → #(#(x1))
#(#(*(*(x1)))) → *(*(x1))
Q is empty.
We use [27] with the following order to prove termination.
Knuth-Bendix order [24] with precedence:
#1 > 11 > 01 > *1
and weight map:
*_1=2
1_1=2
0_1=2
#_1=2
dummyConstant=1
$_1=1