0(0(0(0(x1)))) → 0(1(0(1(x1))))
0(1(0(1(x1)))) → 0(0(1(0(x1))))
↳ QTRS
↳ DependencyPairsProof
0(0(0(0(x1)))) → 0(1(0(1(x1))))
0(1(0(1(x1)))) → 0(0(1(0(x1))))
01(1(0(1(x1)))) → 01(0(1(0(x1))))
01(0(0(0(x1)))) → 01(1(x1))
01(1(0(1(x1)))) → 01(x1)
01(1(0(1(x1)))) → 01(1(0(x1)))
01(0(0(0(x1)))) → 01(1(0(1(x1))))
0(0(0(0(x1)))) → 0(1(0(1(x1))))
0(1(0(1(x1)))) → 0(0(1(0(x1))))
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ QDPOrderProof
01(1(0(1(x1)))) → 01(0(1(0(x1))))
01(0(0(0(x1)))) → 01(1(x1))
01(1(0(1(x1)))) → 01(x1)
01(1(0(1(x1)))) → 01(1(0(x1)))
01(0(0(0(x1)))) → 01(1(0(1(x1))))
0(0(0(0(x1)))) → 0(1(0(1(x1))))
0(1(0(1(x1)))) → 0(0(1(0(x1))))
The following pairs can be oriented strictly and are deleted.
The remaining pairs can at least be oriented weakly.
01(0(0(0(x1)))) → 01(1(x1))
01(1(0(1(x1)))) → 01(x1)
01(1(0(1(x1)))) → 01(1(0(x1)))
Used ordering: Polynomial interpretation [25,35]:
01(1(0(1(x1)))) → 01(0(1(0(x1))))
01(0(0(0(x1)))) → 01(1(0(1(x1))))
The value of delta used in the strict ordering is 16.
POL(1(x1)) = 1 + (2)x_1
POL(01(x1)) = (4)x_1
POL(0(x1)) = 1 + (2)x_1
0(1(0(1(x1)))) → 0(0(1(0(x1))))
0(0(0(0(x1)))) → 0(1(0(1(x1))))
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ QDPOrderProof
↳ QDP
01(1(0(1(x1)))) → 01(0(1(0(x1))))
01(0(0(0(x1)))) → 01(1(0(1(x1))))
0(0(0(0(x1)))) → 0(1(0(1(x1))))
0(1(0(1(x1)))) → 0(0(1(0(x1))))