let R be the TRS under consideration

f(0,1,_1) -> h(_1,_1) is in elim_R(R)
let r0 be the right-hand side of this rule
p0 = 0 is a position in r0
we have r0|p0 = _1
g(_2,_3) -> _2 is in R
let l'0 be the left-hand side of this rule
theta0 = {_1/g(_2,_3)} is a mgu of r0|p0 and l'0

==> f(0,1,g(_1,_2)) -> h(_1,g(_1,_2)) is in EU_R^1
let r1 be the right-hand side of this rule
p1 = epsilon is a position in r1
we have r1|p1 = h(_1,g(_1,_2))
h(0,_3) -> f(0,_3,_3) is in R
let l'1 be the left-hand side of this rule
theta1 = {_1/0, _3/g(0,_2)} is a mgu of r1|p1 and l'1

==> f(0,1,g(0,_1)) -> f(0,g(0,_1),g(0,_1)) is in EU_R^2
let r2 be the right-hand side of this rule
p2 = 1 is a position in r2
we have r2|p2 = g(0,_1)
g(_2,_3) -> _3 is in R
let l'2 be the left-hand side of this rule
theta2 = {_1/_3, _2/0} is a mgu of r2|p2 and l'2

==> f(0,1,g(0,_1)) -> f(0,_1,g(0,_1)) is in EU_R^3
let l be the left-hand side and r be the right-hand side of this rule
let p = epsilon
let theta = {_1/1}
let theta' = {}
we have r|p = f(0,_1,g(0,_1)) and
theta'(theta(l)) = theta(r|p)
so, theta(l) = f(0,1,g(0,1)) is non-terminating w.r.t. R

Termination disproved by the forward process
proof stopped at iteration i=3, depth k=2
50 rule(s) generated