let R be the TRS under consideration

f(0,s(0),_1) -> f(_1,double(_1),_1) is in elim_R(R)
let r0 be the right-hand side of this rule
p0 = 0 is a position in r0
we have r0|p0 = _1
g(_2,_3) -> _2 is in R
let l'0 be the left-hand side of this rule
theta0 = {_1/g(_2,_3)} is a mgu of r0|p0 and l'0

==> f(0,s(0),g(_1,_2)) -> f(_1,double(g(_1,_2)),g(_1,_2)) is in EU_R^1
let r1 be the right-hand side of this rule
p1 = 1 is a position in r1
we have r1|p1 = double(g(_1,_2))
double(_3) -> +(_3,_3) is in R
let l'1 be the left-hand side of this rule
theta1 = {_3/g(_1,_2)} is a mgu of r1|p1 and l'1

==> f(0,s(0),g(_1,_2)) -> f(_1,+(g(_1,_2),g(_1,_2)),g(_1,_2)) is in EU_R^2
let r2 be the right-hand side of this rule
p2 = 1.0 is a position in r2
we have r2|p2 = g(_1,_2)
g(_3,_4) -> _4 is in R
let l'2 be the left-hand side of this rule
theta2 = {_1/_3, _2/_4} is a mgu of r2|p2 and l'2

==> f(0,s(0),g(_1,_2)) -> f(_1,+(_2,g(_1,_2)),g(_1,_2)) is in EU_R^3
let r3 be the right-hand side of this rule
p3 = 1.1 is a position in r3
we have r3|p3 = g(_1,_2)
g(_3,_4) -> _3 is in R
let l'3 be the left-hand side of this rule
theta3 = {_1/_3, _2/_4} is a mgu of r3|p3 and l'3

==> f(0,s(0),g(_1,_2)) -> f(_1,+(_2,_1),g(_1,_2)) is in EU_R^4
let r4 be the right-hand side of this rule
p4 = 1 is a position in r4
we have r4|p4 = +(_2,_1)
+(_3,0) -> _3 is in R
let l'4 be the left-hand side of this rule
theta4 = {_1/0, _2/_3} is a mgu of r4|p4 and l'4

==> f(0,s(0),g(0,_1)) -> f(0,_1,g(0,_1)) is in EU_R^5
let l be the left-hand side and r be the right-hand side of this rule
let p = epsilon
let theta = {_1/s(0)}
let theta' = {}
we have r|p = f(0,_1,g(0,_1)) and
theta'(theta(l)) = theta(r|p)
so, theta(l) = f(0,s(0),g(0,s(0))) is non-terminating w.r.t. R

Termination disproved by the forward process
proof stopped at iteration i=5, depth k=3
8150 rule(s) generated