Problem: terms(N) -> cons(recip(sqr(N)),terms(s(N))) sqr(0()) -> 0() sqr(s(X)) -> s(add(sqr(X),dbl(X))) dbl(0()) -> 0() dbl(s(X)) -> s(s(dbl(X))) add(0(),X) -> X add(s(X),Y) -> s(add(X,Y)) first(0(),X) -> nil() first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z)) half(0()) -> 0() half(s(0())) -> 0() half(s(s(X))) -> s(half(X)) half(dbl(X)) -> X Proof: Containment Processor: loop length: 1 terms: terms(N) context: cons(recip(sqr(N)),[]) substitution: N -> s(N) Qed