Problem:
 terms(N) -> cons(recip(sqr(N)),terms(s(N)))
 sqr(0()) -> 0()
 sqr(s(X)) -> s(add(sqr(X),dbl(X)))
 dbl(0()) -> 0()
 dbl(s(X)) -> s(s(dbl(X)))
 add(0(),X) -> X
 add(s(X),Y) -> s(add(X,Y))
 first(0(),X) -> nil()
 first(s(X),cons(Y,Z)) -> cons(Y,first(X,Z))

Proof:
 Containment Processor:
  loop length: 1
  terms:
   terms(N)
  context: cons(recip(sqr(N)),[])
  substitution:
   N -> s(N)
  Qed