(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
app(app(iterate, f), x) → app(app(cons, x), app(app(iterate, f), app(f, x)))
Q is empty.
(1) Overlay + Local Confluence (EQUIVALENT transformation)
The TRS is overlay and locally confluent. By [NOC] we can switch to innermost.
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
app(app(iterate, f), x) → app(app(cons, x), app(app(iterate, f), app(f, x)))
The set Q consists of the following terms:
app(app(iterate, x0), x1)
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
(4) Obligation:
Q DP problem:
The TRS P consists of the following rules:
APP(app(iterate, f), x) → APP(app(cons, x), app(app(iterate, f), app(f, x)))
APP(app(iterate, f), x) → APP(cons, x)
APP(app(iterate, f), x) → APP(app(iterate, f), app(f, x))
APP(app(iterate, f), x) → APP(f, x)
The TRS R consists of the following rules:
app(app(iterate, f), x) → app(app(cons, x), app(app(iterate, f), app(f, x)))
The set Q consists of the following terms:
app(app(iterate, x0), x1)
We have to consider all minimal (P,Q,R)-chains.
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes.
(6) Obligation:
Q DP problem:
The TRS P consists of the following rules:
APP(app(iterate, f), x) → APP(f, x)
APP(app(iterate, f), x) → APP(app(iterate, f), app(f, x))
The TRS R consists of the following rules:
app(app(iterate, f), x) → app(app(cons, x), app(app(iterate, f), app(f, x)))
The set Q consists of the following terms:
app(app(iterate, x0), x1)
We have to consider all minimal (P,Q,R)-chains.
(7) QDPOrderProof (EQUIVALENT transformation)
We use the reduction pair processor [LPAR04].
The following pairs can be oriented strictly and are deleted.
APP(app(iterate, f), x) → APP(f, x)
The remaining pairs can at least be oriented weakly.
Used ordering: Combined order from the following AFS and order.
APP(
x1,
x2) =
x1
app(
x1,
x2) =
app(
x2)
iterate =
iterate
Knuth-Bendix order [KBO] with precedence:
trivial
and weight map:
dummyConstant=1
app_1=1
The following usable rules [FROCOS05] were oriented:
none
(8) Obligation:
Q DP problem:
The TRS P consists of the following rules:
APP(app(iterate, f), x) → APP(app(iterate, f), app(f, x))
The TRS R consists of the following rules:
app(app(iterate, f), x) → app(app(cons, x), app(app(iterate, f), app(f, x)))
The set Q consists of the following terms:
app(app(iterate, x0), x1)
We have to consider all minimal (P,Q,R)-chains.
(9) MNOCProof (EQUIVALENT transformation)
We use the modular non-overlap check [FROCOS05] to decrease Q to the empty set.
(10) Obligation:
Q DP problem:
The TRS P consists of the following rules:
APP(app(iterate, f), x) → APP(app(iterate, f), app(f, x))
The TRS R consists of the following rules:
app(app(iterate, f), x) → app(app(cons, x), app(app(iterate, f), app(f, x)))
Q is empty.
We have to consider all (P,Q,R)-chains.
(11) NonTerminationProof (EQUIVALENT transformation)
We used the non-termination processor [FROCOS05] to show that the DP problem is infinite.
Found a loop by semiunifying a rule from P directly.
s =
APP(
app(
iterate,
f),
x) evaluates to t =
APP(
app(
iterate,
f),
app(
f,
x))
Thus s starts an infinite chain as s semiunifies with t with the following substitutions:
- Matcher: [x / app(f, x)]
- Semiunifier: [ ]
Rewriting sequenceThe DP semiunifies directly so there is only one rewrite step from APP(app(iterate, f), x) to APP(app(iterate, f), app(f, x)).
(12) NO