Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(b(x1)) → x1
a(c(x1)) → c(c(b(b(x1))))
b(c(x1)) → a(a(x1))

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

b c c c c → c c b c c c c b b c b b b b b b b

b c c c c → c c b c c c c b b c b b b b b b b
by OverlapClosure OC 3

b c c c c → c c b c c a c c b b b b b b b
by OverlapClosure OC 3

b c c c c → c c b c c b c c b b b b b
by OverlapClosure OC 3

b c c c c → c c b c c b b c b c b b b
by OverlapClosure OC 3

b c c c c → c c b c c b b c b b c b b c b b b
by OverlapClosure OC 3

b c c c c → c c b a c c b b c b b c b b b
by OverlapClosure OC 3

b c c c c → c c b a a c c b b c b b b
by OverlapClosure OC 3

b c c c c → c c b a a a c c b b b
by OverlapClosure OC 3

b c c c c → c c b a a a a c b
by OverlapClosure OC 3

b c c c c → c c b a a b c c b
by OverlapClosure OC 2

b c c → c c b a a b b
by OverlapClosure OC 3

b c c → c c b b c b b
by OverlapClosure OC 3

b c c → a c c b b
by OverlapClosure OC 2

b c → a a
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

b c → a a
by original rule (OC 1)

b c c → c c b
by OverlapClosure OC 2

b c c → c c b b c b b
by OverlapClosure OC 3

b c c → a c c b b
by OverlapClosure OC 2

b c → a a
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

b c b b →
by OverlapClosure OC 2

b c b → a
by OverlapClosure OC 2

b c → a a
by original rule (OC 1)

a b →
by original rule (OC 1)

a b →
by original rule (OC 1)

b c → a a
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

b c b b →
by OverlapClosure OC 2

b c b → a
by OverlapClosure OC 2

b c → a a
by original rule (OC 1)

a b →
by original rule (OC 1)

a b →
by original rule (OC 1)

b c b c → c c b b
by OverlapClosure OC 2

b c b → a
by OverlapClosure OC 2

b c → a a
by original rule (OC 1)

a b →
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

b c c → a c c b b
by OverlapClosure OC 2

b c → a a
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

a c → c c b b
by original rule (OC 1)

(2) NO