(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
a(b(x1)) → x1
a(b(x1)) → b(c(x1))
a(c(x1)) → b(a(a(a(x1))))
Q is empty.
(1) QTRS Reverse (EQUIVALENT transformation)
We applied the QTRS Reverse Processor [REVERSE].
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
b(a(x)) → x
b(a(x)) → c(b(x))
c(a(x)) → a(a(a(b(x))))
Q is empty.
(3) NonTerminationProof (EQUIVALENT transformation)
We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.
Found the self-embedding DerivationStructure:
b a a a a a a a a → a a a b a a a a a a a a b b b
b a a a a a a a a →
a a a b a a a a a a a a b b bby OverlapClosure OC 3
b a a a a a a a a → c a a a a a a a a a b b b
by OverlapClosure OC 3b a a a a a a a a → c a a a a a a c a b b
by OverlapClosure OC 2b a → c b
by original rule (OC 1)
b a a a a a a a → a a a a a a c a b b
by OverlapClosure OC 3b a a a a a a a → a a a a a a c b a a b b
by OverlapClosure OC 3b a a a a a a a → a a a a a a b a a a b b
by OverlapClosure OC 3b a a a a a a a → a a a c a a a a b b
by OverlapClosure OC 3b a a a a a a a → a a a c a a a b a a b b
by OverlapClosure OC 3b a a a a a a a → a a a c c a a a b b
by OverlapClosure OC 3b a a a a a a a → a a a c c c a b
by OverlapClosure OC 3b a a a a a a a → a a a c c c b a a b
by OverlapClosure OC 3b a a a a a a a → a a a c c b a a a b
by OverlapClosure OC 2b a a a a a a → a a a c c b c
by OverlapClosure OC 2b a a a a → a a a c c b b
by OverlapClosure OC 3b a a a a → a a a c b a b
by OverlapClosure OC 3b a a a a → a a a b a a b
by OverlapClosure OC 3b a a a a → c a a a b
by OverlapClosure OC 2b a a a → c c
by OverlapClosure OC 2b a → c b
by original rule (OC 1)
b a a → c
by OverlapClosure OC 2b a → c b
by original rule (OC 1)
b a →
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
b a → c b
by original rule (OC 1)
b a → c b
by original rule (OC 1)
b a a → c
by OverlapClosure OC 2b a → c b
by original rule (OC 1)
b a →
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
b a → c b
by original rule (OC 1)
b a →
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
b a →
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
b a → c b
by original rule (OC 1)
b a →
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
c a → a a a b
by original rule (OC 1)
(4) NO