Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x1) → x1
a(b(x1)) → b(c(b(a(a(x1)))))
b(x1) → a(x1)
c(c(x1)) → x1

Q is empty.

(1) QTRS Reverse (EQUIVALENT transformation)

We applied the QTRS Reverse Processor [REVERSE].

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x) → x
b(a(x)) → a(a(b(c(b(x)))))
b(x) → a(x)
c(c(x)) → x

Q is empty.

(3) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

b a a a → b a a a c b

b a a a → b a a a c b
by OverlapClosure OC 3

b a a a → b a a b c b
by OverlapClosure OC 2

b a a → b b
by OverlapClosure OC 3

b a a → b c c b
by OverlapClosure OC 2

b a → b c b
by OverlapClosure OC 3

b a → a b c b
by OverlapClosure OC 3

b a → a a b c b
by original rule (OC 1)

a →
by original rule (OC 1)

a →
by original rule (OC 1)

b a → c b
by OverlapClosure OC 3

b a → a c b
by OverlapClosure OC 3

b a → a b c b
by OverlapClosure OC 3

b a → a a b c b
by original rule (OC 1)

a →
by original rule (OC 1)

b →
by OverlapClosure OC 2

b → a
by original rule (OC 1)

a →
by original rule (OC 1)

a →
by original rule (OC 1)

c c →
by original rule (OC 1)

b a → a a b c b
by original rule (OC 1)

b → a
by original rule (OC 1)

(4) NO