(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x1) → x1
a(b(x1)) → b(c(a(a(x1))))
c(c(c(x1))) → a(b(x1))

Q is empty.

(1) QTRS Reverse (EQUIVALENT transformation)

We applied the QTRS Reverse Processor [REVERSE].

(2) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x) → x
b(a(x)) → a(a(c(b(x))))
c(c(c(x))) → b(a(x))

Q is empty.

(3) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:
b a a a a a a a → b a a a a a a a c b b c b

b a a a a a a a → b a a a a a a a c b b c b
by OverlapClosure OC 3
b a a a a a a a → b a a a a a b a b c b
by OverlapClosure OC 2
b a a a → b a b
by OverlapClosure OC 3
b a a a → c c c b
by OverlapClosure OC 2
b a → c b
by OverlapClosure OC 3
b a → a c b
by OverlapClosure OC 3
b a → a a c b
by original rule (OC 1)
a →
by original rule (OC 1)
a →
by original rule (OC 1)
b a a → c c b
by OverlapClosure OC 2
b a → c b
by OverlapClosure OC 3
b a → a c b
by OverlapClosure OC 3
b a → a a c b
by original rule (OC 1)
a →
by original rule (OC 1)
a →
by original rule (OC 1)
b a → c b
by OverlapClosure OC 3
b a → a c b
by OverlapClosure OC 3
b a → a a c b
by original rule (OC 1)
a →
by original rule (OC 1)
a →
by original rule (OC 1)
c c c → b a
by original rule (OC 1)
b a a a a → a a a a b a b c b
by OverlapClosure OC 3
b a a a a → a a a a c c c b c b
by OverlapClosure OC 3
b a a a a → a a a a c c b a c b
by OverlapClosure OC 3
b a a a a → a a a a c b a a c b
by OverlapClosure OC 3
b a a a a → a a b a a a c b
by OverlapClosure OC 2
b a a a → a a b a b
by OverlapClosure OC 3
b a a a → a a c c c b
by OverlapClosure OC 2
b a → a a c b
by original rule (OC 1)
b a a → c c b
by OverlapClosure OC 2
b a → c b
by OverlapClosure OC 3
b a → a c b
by OverlapClosure OC 3
b a → a a c b
by original rule (OC 1)
a →
by original rule (OC 1)
a →
by original rule (OC 1)
b a → c b
by OverlapClosure OC 3
b a → a c b
by OverlapClosure OC 3
b a → a a c b
by original rule (OC 1)
a →
by original rule (OC 1)
a →
by original rule (OC 1)
c c c → b a
by original rule (OC 1)
b a → a a c b
by original rule (OC 1)
b a → a a c b
by original rule (OC 1)
b a → c b
by OverlapClosure OC 3
b a → a c b
by OverlapClosure OC 3
b a → a a c b
by original rule (OC 1)
a →
by original rule (OC 1)
a →
by original rule (OC 1)
b a → c b
by OverlapClosure OC 3
b a → a c b
by OverlapClosure OC 3
b a → a a c b
by original rule (OC 1)
a →
by original rule (OC 1)
a →
by original rule (OC 1)
c c c → b a
by original rule (OC 1)
b a → a a c b
by original rule (OC 1)

(4) NO