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The given Problem was:
a ->
a -> b
b b c -> a c c c a b
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A self-embedding rewrite structure for the given SRS is:
a b c b c c --(13)-> a c c c c c c c c c a b c b c c c a b (#239785)
OC+OC at 13
OC: a b c b c --(11)-> a c c c c c c c c c a b c b b (#50876)
OC+OC at 7
OC: a b c b c --(8)-> a c c c c c c a b c c b b (#11314)
OC+OC at 4
OC: a b c b c --(5)-> a c c c a b c c c b b (#459)
OC+OC at 0
OC: a --(1)-> b (#2)
Rule
OC: b b c b c --(4)-> a c c c a b c c c b b (#243)
OC+OC at 5
OC: b b c --(1)-> a c c c a b (#3)
Rule
OC: b b c --(3)-> b c c c b b (#27)
OC+OC at 4
OC: b b c --(2)-> b c c c a b (#11)
OC+OC at 0
OC: b b c --(1)-> a c c c a b (#3)
Rule
OC: a --(1)-> b (#2)
Rule
OC: a --(1)-> b (#2)
Rule
OC: a b c --(3)-> c c c a b (#7)
OC+OC at 0
OC: a --(1)-> b (#2)
Rule
OC: b b c --(2)-> c c c a b (#4)
OC+OC at 0
OC: b b c --(1)-> a c c c a b (#3)
Rule
OC: a --(1)-> (#1)
Rule
OC: a b c --(3)-> c c c a b (#7)
OC+OC at 0
OC: a --(1)-> b (#2)
Rule
OC: b b c --(2)-> c c c a b (#4)
OC+OC at 0
OC: b b c --(1)-> a c c c a b (#3)
Rule
OC: a --(1)-> (#1)
Rule
OC: b b c --(2)-> b c c c a b (#11)
OC+OC at 0
OC: b b c --(1)-> a c c c a b (#3)
Rule
OC: a --(1)-> b (#2)
Rule
Hence, the SRS is non-terminating.