Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x1) → x1
a(b(x1)) → b(b(c(a(x1))))
b(x1) → x1
b(c(c(x1))) → a(x1)

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

a b b b c b b → a b b b c b b c a

a b b b c b b → a b b b c b b c a
by OverlapClosure OC 2

a b b b c b → a b b b c a
by OverlapClosure OC 2

a b b b c → a b a
by OverlapClosure OC 2

a b b b → a b b c
by OverlapClosure OC 2

a b b → a a
by OverlapClosure OC 3

a b b → b c c a
by OverlapClosure OC 2

a b → b c a
by OverlapClosure OC 3

a b → b b c a
by original rule (OC 1)

b →
by original rule (OC 1)

a b → c a
by OverlapClosure OC 3

a b → b c a
by OverlapClosure OC 3

a b → b b c a
by original rule (OC 1)

b →
by original rule (OC 1)

b →
by original rule (OC 1)

b c c → a
by original rule (OC 1)

a b → b b c
by OverlapClosure OC 2

a b → b b c a
by original rule (OC 1)

a →
by original rule (OC 1)

b c c → a
by original rule (OC 1)

a b → b b c a
by original rule (OC 1)

a b → b b c a
by original rule (OC 1)

(2) NO