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The given Problem was:
a ->
a -> b
b b c -> a c c c a a
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A self-embedding rewrite structure for the given SRS is:
b b c b c c --(18)-> c c c c c c a c c c b b c b c c c a (#1082343)
OC+OC at 13
OC: b b c b c --(15)-> c c c c c c a c c c b b c b b (#297214)
OC+OC at 6
OC: b b c b c --(11)-> c c c c c c a b c c b b (#32945)
OC+OC at 3
OC: b b c b c --(7)-> c c c a b c c c b b (#1206)
OC+OC at 4
OC: b b c --(2)-> c c c a a (#4)
OC+OC at 0
OC: b b c --(1)-> a c c c a a (#3)
Rule
OC: a --(1)-> (#1)
Rule
OC: a b c --(5)-> b c c c b b (#96)
OC+OC at 0
OC: a --(1)-> b (#2)
Rule
OC: b b c --(4)-> b c c c b b (#81)
OC+OC at 5
OC: b b c --(3)-> b c c c b a (#43)
OC+OC at 0
OC: b b c --(2)-> a c c c b a (#15)
OC+OC at 4
OC: b b c --(1)-> a c c c a a (#3)
Rule
OC: a --(1)-> b (#2)
Rule
OC: a --(1)-> b (#2)
Rule
OC: a --(1)-> b (#2)
Rule
OC: a b c --(4)-> c c c a b (#38)
OC+OC at 0
OC: a --(1)-> b (#2)
Rule
OC: b b c --(3)-> c c c a b (#13)
OC+OC at 4
OC: b b c --(2)-> c c c a a (#4)
OC+OC at 0
OC: b b c --(1)-> a c c c a a (#3)
Rule
OC: a --(1)-> (#1)
Rule
OC: a --(1)-> b (#2)
Rule
OC: a b c --(4)-> a c c c b b (#78)
OC+OC at 0
OC: a --(1)-> b (#2)
Rule
OC: b b c --(3)-> a c c c b b (#44)
OC+OC at 5
OC: b b c --(2)-> a c c c b a (#15)
OC+OC at 4
OC: b b c --(1)-> a c c c a a (#3)
Rule
OC: a --(1)-> b (#2)
Rule
OC: a --(1)-> b (#2)
Rule
OC: b b c --(3)-> b c c c a (#10)
OC+OC at 0
OC: b b c --(2)-> a c c c a (#5)
OC+OC at 4
OC: b b c --(1)-> a c c c a a (#3)
Rule
OC: a --(1)-> (#1)
Rule
OC: a --(1)-> b (#2)
Rule
Hence, the SRS is non-terminating.