let R be the TRS under consideration

b(_1) -> a(_1) is in elim_R(R)
let l0 be the left-hand side of this rule
p0 = 0 is a position in l0
we have l0|p0 = _1
a(b(_2)) -> b(a(c(b(c(_2))))) is in R
let r'0 be the right-hand side of this rule
theta0 = {_1/b(a(c(b(c(_2)))))} is a mgu of l0|p0 and r'0

==> b(a(b(_1))) -> a(b(a(c(b(c(_1)))))) is in EU_R^1
let l1 be the left-hand side of this rule
p1 = 0.0 is a position in l1
we have l1|p1 = b(_1)
c(c(_2)) -> _2 is in R
let r'1 be the right-hand side of this rule
theta1 = {_2/b(_1)} is a mgu of l1|p1 and r'1

==> b(a(c(c(b(_1))))) -> a(b(a(c(b(c(_1)))))) is in EU_R^2
let l2 be the left-hand side of this rule
p2 = 0.0.0 is a position in l2
we have l2|p2 = c(b(_1))
a(_2) -> _2 is in R
let r'2 be the right-hand side of this rule
theta2 = {_2/c(b(_1))} is a mgu of l2|p2 and r'2

==> b(a(c(a(c(b(_1)))))) -> a(b(a(c(b(c(_1)))))) is in EU_R^3
let l3 be the left-hand side of this rule
p3 = 0.0.0 is a position in l3
we have l3|p3 = a(c(b(_1)))
a(_2) -> _2 is in R
let r'3 be the right-hand side of this rule
theta3 = {_2/a(c(b(_1)))} is a mgu of l3|p3 and r'3

==> b(a(c(a(a(c(b(_1))))))) -> a(b(a(c(b(c(_1)))))) is in EU_R^4
let l4 be the left-hand side of this rule
p4 = 0.0.0 is a position in l4
we have l4|p4 = a(a(c(b(_1))))
b(_2) -> a(_2) is in R
let r'4 be the right-hand side of this rule
theta4 = {_2/a(c(b(_1)))} is a mgu of l4|p4 and r'4

==> b(a(c(b(a(c(b(_1))))))) -> a(b(a(c(b(c(_1)))))) is in EU_R^5
let l5 be the left-hand side of this rule
p5 = 0.0.0 is a position in l5
we have l5|p5 = b(a(c(b(_1))))
a(b(_2)) -> b(a(c(b(c(_2))))) is in R
let r'5 be the right-hand side of this rule
theta5 = {_1/c(_2)} is a mgu of l5|p5 and r'5

==> b(a(c(a(b(_1))))) -> a(b(a(c(b(c(c(_1))))))) is in EU_R^6
let l6 be the left-hand side of this rule
p6 = 0.0.0 is a position in l6
we have l6|p6 = a(b(_1))
b(_2) -> a(_2) is in R
let r'6 be the right-hand side of this rule
theta6 = {_2/b(_1)} is a mgu of l6|p6 and r'6

==> b(a(c(b(b(_1))))) -> a(b(a(c(b(c(c(_1))))))) is in EU_R^7
let l7 be the left-hand side of this rule
p7 = 0.0.0.0 is a position in l7
we have l7|p7 = b(_1)
c(c(_2)) -> _2 is in R
let r'7 be the right-hand side of this rule
theta7 = {_2/b(_1)} is a mgu of l7|p7 and r'7

==> b(a(c(b(c(c(b(_1))))))) -> a(b(a(c(b(c(c(_1))))))) is in EU_R^8
let l8 be the left-hand side of this rule
p8 = epsilon is a position in l8
we have l8|p8 = b(a(c(b(c(c(b(_1)))))))
a(b(_2)) -> b(a(c(b(c(_2))))) is in R
let r'8 be the right-hand side of this rule
theta8 = {_2/c(b(_1))} is a mgu of l8|p8 and r'8

==> a(b(c(b(_1)))) -> a(b(a(c(b(c(c(_1))))))) is in EU_R^9
let l9 be the left-hand side of this rule
p9 = 0.0 is a position in l9
we have l9|p9 = c(b(_1))
a(_2) -> _2 is in R
let r'9 be the right-hand side of this rule
theta9 = {_2/c(b(_1))} is a mgu of l9|p9 and r'9

==> a(b(a(c(b(_1))))) -> a(b(a(c(b(c(c(_1))))))) is in EU_R^10
let l be the left-hand side and r be the right-hand side of this rule
let p = epsilon
let theta = {}
let theta' = {_1/c(c(_1))}
we have r|p = a(b(a(c(b(c(c(_1))))))) and
theta'(theta(l)) = theta(r|p)
so, theta(l) = a(b(a(c(b(_1))))) is non-terminating w.r.t. R

Termination disproved by the backward process
proof stopped at iteration i=10, depth k=7
12137 rule(s) generated