========================================================
The given Problem was:
a ->
a b -> b a c a
c b ->
c c -> b
========================================================
A self-embedding rewrite structure for the given SRS is:
a b b c b b c --(17)-> b b a b b c b b c a (#381431)
OC+OC at 8
OC: a b b c b b c --(16)-> b b a b b c b b a c a (#296222)
OC+OC at 4
OC: a b b c --(10)-> b b a b a (#1281)
OC+OC at 3
OC: a b b c --(9)-> b b a c c a (#1239)
OC+OC at 1
OC: a b b c --(7)-> b a b c a (#397)
OC+OC at 2
OC: a b b c --(5)-> b a a b (#90)
OC+OC at 2
OC: a b b c --(4)-> b a c b a b (#55)
OC+OC at 3
OC: a b --(1)-> b a c a (#2)
Rule
OC: a b c --(3)-> b a b (#9)
OC+OC at 2
OC: a b --(2)-> b a c (#6)
OC+OC at 3
OC: a b --(1)-> b a c a (#2)
Rule
OC: a --(1)-> (#1)
Rule
OC: c c --(1)-> b (#4)
Rule
OC: c b --(1)-> (#3)
Rule
OC: a b --(2)-> b c a (#5)
OC+OC at 1
OC: a b --(1)-> b a c a (#2)
Rule
OC: a --(1)-> (#1)
Rule
OC: a b --(2)-> b a c (#6)
OC+OC at 3
OC: a b --(1)-> b a c a (#2)
Rule
OC: a --(1)-> (#1)
Rule
OC: c c --(1)-> b (#4)
Rule
OC: a b b c --(6)-> b c b b a c a (#167)
OC+OC at 2
OC: a b --(2)-> b c a (#5)
OC+OC at 1
OC: a b --(1)-> b a c a (#2)
Rule
OC: a --(1)-> (#1)
Rule
OC: a b c --(4)-> b b a c a (#61)
OC+OC at 1
OC: a b c --(3)-> b a b (#9)
OC+OC at 2
OC: a b --(2)-> b a c (#6)
OC+OC at 3
OC: a b --(1)-> b a c a (#2)
Rule
OC: a --(1)-> (#1)
Rule
OC: c c --(1)-> b (#4)
Rule
OC: a b --(1)-> b a c a (#2)
Rule
OC: a --(1)-> (#1)
Rule
Hence, the SRS is non-terminating.