Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x1) → x1
a(b(x1)) → x1
b(b(x1)) → c(x1)
c(a(x1)) → a(a(b(c(x1))))

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

c a a a a a → c a a a a a b c b c

c a a a a a → c a a a a a b c b c
by OverlapClosure OC 3

c a a a a a → c a a a c a b c
by OverlapClosure OC 2

c a a → c c
by OverlapClosure OC 3

c a a → b b c
by OverlapClosure OC 2

c a → b c
by OverlapClosure OC 3

c a → a b c
by OverlapClosure OC 3

c a → a a b c
by original rule (OC 1)

a →
by original rule (OC 1)

a →
by original rule (OC 1)

c a → b c
by OverlapClosure OC 3

c a → a b c
by OverlapClosure OC 3

c a → a a b c
by original rule (OC 1)

a →
by original rule (OC 1)

a →
by original rule (OC 1)

b b → c
by original rule (OC 1)

c a a a → a a a c a b c
by OverlapClosure OC 3

c a a a → a a a a b c a b c
by OverlapClosure OC 3

c a a a → a a c a a b c
by OverlapClosure OC 2

c a a → a a c c
by OverlapClosure OC 3

c a a → a a b b c
by OverlapClosure OC 2

c a → a a b c
by original rule (OC 1)

c a → b c
by OverlapClosure OC 3

c a → a b c
by OverlapClosure OC 3

c a → a a b c
by original rule (OC 1)

a →
by original rule (OC 1)

a →
by original rule (OC 1)

b b → c
by original rule (OC 1)

c a → a a b c
by original rule (OC 1)

c a → a a b c
by original rule (OC 1)

a b →
by original rule (OC 1)

c a → a a b c
by original rule (OC 1)

(2) NO