Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x1) → x1
a(b(x1)) → c(x1)
c(c(x1)) → b(c(b(a(a(x1)))))

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

c c b c b c b c → b c b b c b b c b c c b c b c b c

c c b c b c b c → b c b b c b b c b c c b c b c b c
by OverlapClosure OC 2

c c b c b c b c → b c b b c b b c b c c b c b c b a b
by OverlapClosure OC 3

c c b c b c b c → b c b b c b b c b c c b c c c b
by OverlapClosure OC 3

c c b c b c b c → b c b b c b b c b c c b c a b c b
by OverlapClosure OC 2

c c b c b c → b c b b c b b c b c c b c a a
by OverlapClosure OC 3

c c b c b c → b c b b c b c c b c b a a
by OverlapClosure OC 3

c c b c b c → b c b c c b c c b a a
by OverlapClosure OC 3

c c b c b c → b c b a b c b c c b a a
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a b c b c → b c b c c b a a
by OverlapClosure OC 3

a b c b c → b c b a b c b a a
by OverlapClosure OC 2

a b → c
by original rule (OC 1)

c c b c → b c b a b c b a a
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a b c → b c b a a
by OverlapClosure OC 2

a b → c
by original rule (OC 1)

c c → b c b a a
by original rule (OC 1)

a b → c
by original rule (OC 1)

a b → c
by original rule (OC 1)

c c b c → b c b c c b
by OverlapClosure OC 3

c c b c → b c b a b c b
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a b c → b c b
by OverlapClosure OC 2

a b c → b c b a
by OverlapClosure OC 2

a b → c
by original rule (OC 1)

c c → b c b a
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a →
by original rule (OC 1)

a →
by original rule (OC 1)

a b → c
by original rule (OC 1)

c c b c b → b c b c c b c
by OverlapClosure OC 3

c c b c b → b c b a b c b c
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a b c b → b c b c
by OverlapClosure OC 2

a b → c
by original rule (OC 1)

c c b → b c b c
by OverlapClosure OC 2

c c → b c b a
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a →
by original rule (OC 1)

a b → c
by original rule (OC 1)

a b → c
by original rule (OC 1)

a b c → b c b
by OverlapClosure OC 2

a b c → b c b a
by OverlapClosure OC 2

a b → c
by original rule (OC 1)

c c → b c b a
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a →
by original rule (OC 1)

a →
by original rule (OC 1)

a b → c
by original rule (OC 1)

c c → b c b a
by OverlapClosure OC 2

c c → b c b a a
by original rule (OC 1)

a →
by original rule (OC 1)

a b → c
by original rule (OC 1)

(2) NO