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The given Problem was:
a a a -> b
b c -> c c a a a a
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A self-embedding rewrite structure for the given SRS is:
b c a a c c a c c --(17)-> c c c c a c c a a c c a b c a a c c a c c b a (#160684)
OC+OC at 19
OC: b c a a c c a c --(15)-> c c c c a c c a a c c a b c a a c c a b (#36622)
OC+OC at 16
OC: b c a a c c a --(13)-> c c c c a c c a a c c a b c a a b (#13320)
OC+OC at 9
OC: b c a a c c a --(11)-> c c c c a c c a a b c c a a b (#2825)
OC+OC at 10
OC: b c a a c --(9)-> c c c c a c c a a b b (#981)
OC+OC at 5
OC: b c a a c --(7)-> c c c c a b c a b (#187)
OC+OC at 2
OC: b c a a c --(5)-> c c b c c a b (#24)
OC+OC at 3
OC: b c --(2)-> c c b a (#4)
OC+OC at 2
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
OC: a a a c --(3)-> c c a b (#14)
OC+OC at 3
OC: a a a c --(2)-> c c a a a a (#3)
OC+OC at 0
OC: a a a --(1)-> b (#1)
Rule
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
OC: b c --(2)-> c c a b (#5)
OC+OC at 3
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
OC: b c a --(2)-> c c a a b (#6)
OC+OC at 4
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
OC: b c a --(2)-> c c a a b (#6)
OC+OC at 4
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
OC: b c --(2)-> c c a b (#5)
OC+OC at 3
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
OC: b c --(2)-> c c a b (#5)
OC+OC at 3
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
OC: b c --(2)-> c c b a (#4)
OC+OC at 2
OC: b c --(1)-> c c a a a a (#2)
Rule
OC: a a a --(1)-> b (#1)
Rule
Hence, the SRS is non-terminating.