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The given Problem was:
0 0 0 0 -> 0 1 1 0
1 0 0 1 -> 0 0 1 0
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A self-embedding rewrite structure for the given SRS is:
0 0 0 0 0 1 0 1 0 1 0 0 --(15)-> 0 0 0 0 0 1 0 1 0 1 0 0 (#28065)
OC+OC at 3
OC: 0 0 0 0 0 1 0 1 0 1 0 0 --(14)-> 0 0 0 1 0 0 1 1 0 1 0 0 (#19389)
OC+OC at 1
OC: 0 0 0 0 0 1 0 1 0 1 0 0 --(13)-> 0 1 0 0 1 0 1 1 0 1 0 0 (#3219)
OC+OC at 2
OC: 0 0 0 0 --(1)-> 0 1 1 0 (#1)
Rule
OC: 1 0 0 1 0 1 0 1 0 0 --(12)-> 0 0 1 0 1 1 0 1 0 0 (#2993)
OC+OC at 3
OC: 1 0 0 1 0 1 0 1 0 0 --(11)-> 0 0 1 0 0 0 0 1 0 0 (#2000)
OC+OC at 5
OC: 1 0 0 1 0 1 0 1 0 0 --(10)-> 0 0 1 0 0 1 0 0 1 0 (#1494)
OC+OC at 3
OC: 1 0 0 1 0 1 0 1 0 0 --(9)-> 0 0 1 1 0 0 1 0 1 0 (#1096)
OC+OC at 1
OC: 1 0 0 1 0 1 0 1 0 0 --(8)-> 0 0 0 0 0 0 1 0 1 0 (#816)
OC+OC at 4
OC: 1 0 0 1 0 1 0 1 0 0 --(7)-> 0 0 0 0 1 0 0 1 1 0 (#171)
OC+OC at 6
OC: 1 0 0 1 0 1 0 1 --(6)-> 0 0 0 0 1 0 0 0 (#131)
OC+OC at 2
OC: 1 0 0 1 0 1 0 1 --(5)-> 0 0 1 0 0 1 0 0 (#101)
OC+OC at 3
OC: 1 0 0 1 0 1 0 1 --(4)-> 0 0 1 1 0 0 1 0 (#54)
OC+OC at 1
OC: 1 0 0 1 0 1 0 1 --(3)-> 0 0 0 0 0 0 1 0 (#9)
OC+OC at 2
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 1 0 0 1 0 1 --(2)-> 0 0 0 0 1 0 (#6)
OC+OC at 2
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 0 0 0 0 --(1)-> 0 1 1 0 (#1)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 0 0 0 0 --(1)-> 0 1 1 0 (#1)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 0 0 0 0 --(1)-> 0 1 1 0 (#1)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 0 0 0 0 --(1)-> 0 1 1 0 (#1)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
OC: 1 0 0 1 --(1)-> 0 0 1 0 (#2)
Rule
Hence, the SRS is non-terminating.