let R be the TRS under consideration

0(0(0(0(_1)))) -> 0(0(1(1(_1)))) is in elim_R(R)
let r0 be the right-hand side of this rule
p0 = 0.0.0 is a position in r0
we have r0|p0 = 1(_1)
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'0 be the left-hand side of this rule
theta0 = {_1/0(0(1(_2)))} is a mgu of r0|p0 and l'0

==> 0(0(0(0(0(0(1(_1))))))) -> 0(0(1(0(0(1(0(_1))))))) is in EU_R^1
let r1 be the right-hand side of this rule
p1 = 0.0.0.0.0 is a position in r1
we have r1|p1 = 1(0(_1))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'1 be the left-hand side of this rule
theta1 = {_1/0(1(_2))} is a mgu of r1|p1 and l'1

==> 0(0(0(0(0(0(1(0(1(_1))))))))) -> 0(0(1(0(0(0(0(1(0(_1))))))))) is in EU_R^2
let r2 be the right-hand side of this rule
p2 = 0.0.0 is a position in r2
we have r2|p2 = 0(0(0(0(1(0(_1))))))
0(0(0(0(_2)))) -> 0(0(1(1(_2)))) is in R
let l'2 be the left-hand side of this rule
theta2 = {_2/1(0(_1))} is a mgu of r2|p2 and l'2

==> 0(0(0(0(0(0(1(0(1(_1))))))))) -> 0(0(1(0(0(1(1(1(0(_1))))))))) is in EU_R^3
let r3 be the right-hand side of this rule
p3 = 0.0.0.0.0.0.0 is a position in r3
we have r3|p3 = 1(0(_1))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'3 be the left-hand side of this rule
theta3 = {_1/0(1(_2))} is a mgu of r3|p3 and l'3

==> 0(0(0(0(0(0(1(0(1(0(1(_1))))))))))) -> 0(0(1(0(0(1(1(0(0(1(0(_1))))))))))) is in EU_R^4
let r4 be the right-hand side of this rule
p4 = 0.0.0.0.0.0 is a position in r4
we have r4|p4 = 1(0(0(1(0(_1)))))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'4 be the left-hand side of this rule
theta4 = {_2/0(_1)} is a mgu of r4|p4 and l'4

==> 0(0(0(0(0(0(1(0(1(0(1(_1))))))))))) -> 0(0(1(0(0(1(0(0(1(0(0(_1))))))))))) is in EU_R^5
let r5 be the right-hand side of this rule
p5 = 0.0.0.0.0 is a position in r5
we have r5|p5 = 1(0(0(1(0(0(_1))))))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'5 be the left-hand side of this rule
theta5 = {_2/0(0(_1))} is a mgu of r5|p5 and l'5

==> 0(0(0(0(0(0(1(0(1(0(1(_1))))))))))) -> 0(0(1(0(0(0(0(1(0(0(0(_1))))))))))) is in EU_R^6
let r6 be the right-hand side of this rule
p6 = 0.0.0 is a position in r6
we have r6|p6 = 0(0(0(0(1(0(0(0(_1))))))))
0(0(0(0(_2)))) -> 0(0(1(1(_2)))) is in R
let l'6 be the left-hand side of this rule
theta6 = {_2/1(0(0(0(_1))))} is a mgu of r6|p6 and l'6

==> 0(0(0(0(0(0(1(0(1(0(1(_1))))))))))) -> 0(0(1(0(0(1(1(1(0(0(0(_1))))))))))) is in EU_R^7
let r7 be the right-hand side of this rule
p7 = 0.0 is a position in r7
we have r7|p7 = 1(0(0(1(1(1(0(0(0(_1)))))))))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'7 be the left-hand side of this rule
theta7 = {_2/1(1(0(0(0(_1)))))} is a mgu of r7|p7 and l'7

==> 0(0(0(0(0(0(1(0(1(0(1(_1))))))))))) -> 0(0(0(0(1(0(1(1(0(0(0(_1))))))))))) is in EU_R^8
let r8 be the right-hand side of this rule
p8 = 0.0.0.0.0.0.0.0 is a position in r8
we have r8|p8 = 0(0(0(_1)))
0(0(0(0(_2)))) -> 0(0(1(1(_2)))) is in R
let l'8 be the left-hand side of this rule
theta8 = {_1/0(_2)} is a mgu of r8|p8 and l'8

==> 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) -> 0(0(0(0(1(0(1(1(0(0(1(1(_1)))))))))))) is in EU_R^9
let r9 be the right-hand side of this rule
p9 = 0.0.0.0.0.0.0 is a position in r9
we have r9|p9 = 1(0(0(1(1(_1)))))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'9 be the left-hand side of this rule
theta9 = {_2/1(_1)} is a mgu of r9|p9 and l'9

==> 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) -> 0(0(0(0(1(0(1(0(0(1(0(1(_1)))))))))))) is in EU_R^10
let r10 be the right-hand side of this rule
p10 = 0.0.0.0.0.0 is a position in r10
we have r10|p10 = 1(0(0(1(0(1(_1))))))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'10 be the left-hand side of this rule
theta10 = {_2/0(1(_1))} is a mgu of r10|p10 and l'10

==> 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) -> 0(0(0(0(1(0(0(0(1(0(0(1(_1)))))))))))) is in EU_R^11
let r11 be the right-hand side of this rule
p11 = 0.0.0.0.0.0.0.0 is a position in r11
we have r11|p11 = 1(0(0(1(_1))))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'11 be the left-hand side of this rule
theta11 = {_1/_2} is a mgu of r11|p11 and l'11

==> 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) -> 0(0(0(0(1(0(0(0(0(0(1(0(_1)))))))))))) is in EU_R^12
let r12 be the right-hand side of this rule
p12 = 0.0.0.0.0 is a position in r12
we have r12|p12 = 0(0(0(0(0(1(0(_1)))))))
0(0(0(0(_2)))) -> 0(0(1(1(_2)))) is in R
let l'12 be the left-hand side of this rule
theta12 = {_2/0(1(0(_1)))} is a mgu of r12|p12 and l'12

==> 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) -> 0(0(0(0(1(0(0(1(1(0(1(0(_1)))))))))))) is in EU_R^13
let r13 be the right-hand side of this rule
p13 = 0.0.0.0 is a position in r13
we have r13|p13 = 1(0(0(1(1(0(1(0(_1))))))))
1(0(0(1(_2)))) -> 0(0(1(0(_2)))) is in R
let l'13 be the left-hand side of this rule
theta13 = {_2/1(0(1(0(_1))))} is a mgu of r13|p13 and l'13

==> 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) -> 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) is in EU_R^14
let l be the left-hand side and r be the right-hand side of this rule
let p = epsilon
let theta = {}
let theta' = {}
we have r|p = 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) and
theta'(theta(l)) = theta(r|p)
so, theta(l) = 0(0(0(0(0(0(1(0(1(0(1(0(_1)))))))))))) is non-terminating w.r.t. R

Termination disproved by the forward process
proof stopped at iteration i=14, depth k=12
2220 rule(s) generated