(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

h(true, x, y) → h(gt(x, y), s(x), s(y))
gt(0, x) → false
gt(s(x), 0) → true
gt(s(x), s(y)) → gt(x, y)

Q is empty.

(1) DependencyPairsProof (EQUIVALENT transformation)

Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.

(2) Obligation:

Q DP problem:
The TRS P consists of the following rules:

H(true, x, y) → H(gt(x, y), s(x), s(y))
H(true, x, y) → GT(x, y)
GT(s(x), s(y)) → GT(x, y)

The TRS R consists of the following rules:

h(true, x, y) → h(gt(x, y), s(x), s(y))
gt(0, x) → false
gt(s(x), 0) → true
gt(s(x), s(y)) → gt(x, y)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(3) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 1 less node.

(4) Complex Obligation (AND)

(5) Obligation:

Q DP problem:
The TRS P consists of the following rules:

GT(s(x), s(y)) → GT(x, y)

The TRS R consists of the following rules:

h(true, x, y) → h(gt(x, y), s(x), s(y))
gt(0, x) → false
gt(s(x), 0) → true
gt(s(x), s(y)) → gt(x, y)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(6) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • GT(s(x), s(y)) → GT(x, y)
    The graph contains the following edges 1 > 1, 2 > 2

(7) YES

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

H(true, x, y) → H(gt(x, y), s(x), s(y))

The TRS R consists of the following rules:

h(true, x, y) → h(gt(x, y), s(x), s(y))
gt(0, x) → false
gt(s(x), 0) → true
gt(s(x), s(y)) → gt(x, y)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

(9) NonLoopProof (EQUIVALENT transformation)

By Theorem 8 [NONLOOP] we deduce infiniteness of the QDP.
We apply the theorem with m = 1, b = 1,
σ' = [ ], and μ' = [ ] on the rule
H(true, s(s(zr0)), s(zr1))[zr0 / s(zr0), zr1 / s(zr1)]n[zr1 / 0] → H(true, s(s(s(zr0))), s(s(zr1)))[zr0 / s(zr0), zr1 / s(zr1)]n[zr1 / 0]
This rule is correct for the QDP as the following derivation shows:

intermediate steps: Equivalent (Remove Unused) - Instantiate mu - Equivalent (Domain Renaming) - Instantiation - Equivalent (Domain Renaming) - Equivalent (Remove Unused)
H(true, s(s(zl2)), s(zl3))[zl2 / s(zl2), zl3 / s(zl3), zr2 / s(zr2), zr3 / s(zr3)]n[zl2 / y0, zl3 / 0, zr2 / y0, zr3 / 0] → H(true, s(s(s(zr2))), s(s(zr3)))[zl2 / s(zl2), zl3 / s(zl3), zr2 / s(zr2), zr3 / s(zr3)]n[zl2 / y0, zl3 / 0, zr2 / y0, zr3 / 0]
    by Narrowing at position: [0]
        intermediate steps: Equivalent (Add Unused) - Equivalent (Add Unused) - Instantiation - Equivalent (Simplify mu) - Instantiation - Equivalent (Domain Renaming) - Instantiation - Equivalent (Domain Renaming)
        H(true, s(zs2), s(zs3))[zs2 / s(zs2), zs3 / s(zs3)]n[zs2 / y1, zs3 / y0] → H(gt(y1, y0), s(s(zs2)), s(s(zs3)))[zs2 / s(zs2), zs3 / s(zs3)]n[zs2 / y1, zs3 / y0]
            by Narrowing at position: [0]
                intermediate steps: Instantiate mu - Instantiate Sigma - Instantiation - Instantiation - Instantiation
                H(true, x, y)[ ]n[ ] → H(gt(x, y), s(x), s(y))[ ]n[ ]
                    by OriginalRule from TRS P

                intermediate steps: Equivalent (Add Unused) - Equivalent (Add Unused) - Equivalent (Domain Renaming) - Instantiation - Equivalent (Domain Renaming)
                gt(s(x), s(y))[x / s(x), y / s(y)]n[ ] → gt(x, y)[ ]n[ ]
                    by PatternCreation I
                        gt(s(x), s(y))[ ]n[ ] → gt(x, y)[ ]n[ ]
                            by OriginalRule from TRS R

        intermediate steps: Equivalent (Add Unused) - Equivalent (Add Unused) - Instantiation
        gt(s(x), 0)[ ]n[ ] → true[ ]n[ ]
            by OriginalRule from TRS R

(10) NO