(0) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
g(tt, x) → g(h(f(x, x)), s(x))
h(f(0, y)) → tt
f(s(x), y) → f(x, s(y))
Q is empty.
(1) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
(2) Obligation:
Q DP problem:
The TRS P consists of the following rules:
G(tt, x) → G(h(f(x, x)), s(x))
G(tt, x) → H(f(x, x))
G(tt, x) → F(x, x)
F(s(x), y) → F(x, s(y))
The TRS R consists of the following rules:
g(tt, x) → g(h(f(x, x)), s(x))
h(f(0, y)) → tt
f(s(x), y) → f(x, s(y))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
(3) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 2 less nodes.
(4) Complex Obligation (AND)
(5) Obligation:
Q DP problem:
The TRS P consists of the following rules:
F(s(x), y) → F(x, s(y))
The TRS R consists of the following rules:
g(tt, x) → g(h(f(x, x)), s(x))
h(f(0, y)) → tt
f(s(x), y) → f(x, s(y))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
(6) QDPSizeChangeProof (EQUIVALENT transformation)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.
From the DPs we obtained the following set of size-change graphs:
- F(s(x), y) → F(x, s(y))
The graph contains the following edges 1 > 1
(7) YES
(8) Obligation:
Q DP problem:
The TRS P consists of the following rules:
G(tt, x) → G(h(f(x, x)), s(x))
The TRS R consists of the following rules:
g(tt, x) → g(h(f(x, x)), s(x))
h(f(0, y)) → tt
f(s(x), y) → f(x, s(y))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
(9) NonLoopProof (EQUIVALENT transformation)
By Theorem 8 [NONLOOP] we deduce infiniteness of the QDP.
We apply the theorem with m = 1, b = 1,
σ' = [ ], and μ' = [ ] on the rule
G(tt, s(zr0))[zr0 / s(zr0)]n[zr0 / 0] → G(tt, s(s(zr0)))[zr0 / s(zr0)]n[zr0 / 0]
This rule is correct for the QDP as the following derivation shows:
intermediate steps: Equivalent (Domain Renaming) - Equivalent (Domain Renaming) - Equivalent (Remove Unused)
G(tt, s(zl1))[zl1 / s(zl1), zr2 / s(zr2), zr3 / s(s(zr3))]n[zl1 / 0, zr2 / 0, zr3 / 0] → G(tt, s(s(zr2)))[zl1 / s(zl1), zr2 / s(zr2), zr3 / s(s(zr3))]n[zl1 / 0, zr2 / 0, zr3 / 0]
by Narrowing at position: [0]
intermediate steps: Equivalent (Add Unused) - Equivalent (Add Unused) - Instantiation - Equivalent (Domain Renaming) - Instantiation - Equivalent (Domain Renaming) - Equivalent (Remove Unused)
G(tt, s(zs1))[zs1 / s(zs1), zt1 / s(s(zt1))]n[zs1 / y1, zt1 / y1] → G(h(f(y1, s(s(zt1)))), s(s(zs1)))[zs1 / s(zs1), zt1 / s(s(zt1))]n[zs1 / y1, zt1 / y1]
by Narrowing at position: [0,0]
intermediate steps: Equivalent (Add Unused) - Instantiate mu - Equivalent (Add Unused) - Instantiate Sigma - Instantiation - Instantiation
G(tt, x)[ ]n[ ] → G(h(f(x, x)), s(x))[ ]n[ ]
by OriginalRule from TRS P
intermediate steps: Equivalent (Add Unused) - Equivalent (Add Unused) - Equivalent (Domain Renaming) - Equivalent (Remove Unused) - Equivalent (Simplify mu) - Instantiate mu - Instantiate Sigma - Equivalent (Simplify mu) - Equivalent (Remove Unused) - Instantiate mu - Equivalent (Simplify mu) - Instantiation - Equivalent (Domain Renaming) - Instantiation - Equivalent (Domain Renaming)
f(s(x), y)[x / s(x)]n[ ] → f(x, s(y))[y / s(y)]n[ ]
by PatternCreation I
f(s(x), y)[ ]n[ ] → f(x, s(y))[ ]n[ ]
by OriginalRule from TRS R
intermediate steps: Equivalent (Add Unused) - Instantiate mu - Equivalent (Add Unused) - Instantiate Sigma - Instantiation - Instantiation
h(f(0, y))[ ]n[ ] → tt[ ]n[ ]
by OriginalRule from TRS R
(10) NO