(0) Obligation:
Clauses:
fold(X, .(Y, Ys), Z) :- ','(myop(X, Y, V), fold(V, Ys, Z)).
fold(X, [], X).
myop(a, b, c).
Query: fold(g,g,a)
(1) PrologToPiTRSViaGraphTransformerProof (SOUND transformation)
Transformed Prolog program to (Pi-)TRS.
(2) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
foldA_in_gga(a, .(b, []), c) → foldA_out_gga(a, .(b, []), c)
foldA_in_gga(T37, [], T37) → foldA_out_gga(T37, [], T37)
The argument filtering Pi contains the following mapping:
foldA_in_gga(
x1,
x2,
x3) =
foldA_in_gga(
x1,
x2)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
[] =
[]
foldA_out_gga(
x1,
x2,
x3) =
foldA_out_gga(
x1,
x2,
x3)
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
P is empty.
The TRS R consists of the following rules:
foldA_in_gga(a, .(b, []), c) → foldA_out_gga(a, .(b, []), c)
foldA_in_gga(T37, [], T37) → foldA_out_gga(T37, [], T37)
The argument filtering Pi contains the following mapping:
foldA_in_gga(
x1,
x2,
x3) =
foldA_in_gga(
x1,
x2)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
[] =
[]
foldA_out_gga(
x1,
x2,
x3) =
foldA_out_gga(
x1,
x2,
x3)
We have to consider all (P,R,Pi)-chains
(4) Obligation:
Pi DP problem:
P is empty.
The TRS R consists of the following rules:
foldA_in_gga(a, .(b, []), c) → foldA_out_gga(a, .(b, []), c)
foldA_in_gga(T37, [], T37) → foldA_out_gga(T37, [], T37)
The argument filtering Pi contains the following mapping:
foldA_in_gga(
x1,
x2,
x3) =
foldA_in_gga(
x1,
x2)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
[] =
[]
foldA_out_gga(
x1,
x2,
x3) =
foldA_out_gga(
x1,
x2,
x3)
We have to consider all (P,R,Pi)-chains
(5) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,R,Pi) chain.
(6) YES