(0) Obligation:
Clauses:
flatten(atom(X), .(X, [])).
flatten(cons(atom(X), U), .(X, Y)) :- flatten(U, Y).
flatten(cons(cons(U, V), W), X) :- flatten(cons(U, cons(V, W)), X).
Query: flatten(g,a)
(1) PrologToPiTRSViaGraphTransformerProof (SOUND transformation)
Transformed Prolog program to (Pi-)TRS.
(2) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
flattenA_in_ga(atom(T4), .(T4, [])) → flattenA_out_ga(atom(T4), .(T4, []))
flattenA_in_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, []))) → flattenA_out_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, [])))
flattenA_in_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → U1_ga(T8, T29, T30, T32, flattenA_in_ga(T30, T32))
flattenA_in_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → U2_ga(T8, T51, T52, T53, T55, flattenA_in_ga(cons(T51, cons(T52, T53)), T55))
flattenA_in_ga(cons(cons(atom(T81), T82), T83), .(T81, T85)) → U3_ga(T81, T82, T83, T85, flattenA_in_ga(cons(T82, T83), T85))
flattenA_in_ga(cons(cons(cons(T96, T97), T98), T99), T101) → U4_ga(T96, T97, T98, T99, T101, flattenA_in_ga(cons(T96, cons(T97, cons(T98, T99))), T101))
U4_ga(T96, T97, T98, T99, T101, flattenA_out_ga(cons(T96, cons(T97, cons(T98, T99))), T101)) → flattenA_out_ga(cons(cons(cons(T96, T97), T98), T99), T101)
U3_ga(T81, T82, T83, T85, flattenA_out_ga(cons(T82, T83), T85)) → flattenA_out_ga(cons(cons(atom(T81), T82), T83), .(T81, T85))
U2_ga(T8, T51, T52, T53, T55, flattenA_out_ga(cons(T51, cons(T52, T53)), T55)) → flattenA_out_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55))
U1_ga(T8, T29, T30, T32, flattenA_out_ga(T30, T32)) → flattenA_out_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32)))
The argument filtering Pi contains the following mapping:
flattenA_in_ga(
x1,
x2) =
flattenA_in_ga(
x1)
atom(
x1) =
atom(
x1)
flattenA_out_ga(
x1,
x2) =
flattenA_out_ga(
x1,
x2)
cons(
x1,
x2) =
cons(
x1,
x2)
U1_ga(
x1,
x2,
x3,
x4,
x5) =
U1_ga(
x1,
x2,
x3,
x5)
U2_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U2_ga(
x1,
x2,
x3,
x4,
x6)
U3_ga(
x1,
x2,
x3,
x4,
x5) =
U3_ga(
x1,
x2,
x3,
x5)
U4_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U4_ga(
x1,
x2,
x3,
x4,
x6)
.(
x1,
x2) =
.(
x1,
x2)
(3) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → U1_GA(T8, T29, T30, T32, flattenA_in_ga(T30, T32))
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → FLATTENA_IN_GA(T30, T32)
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → U2_GA(T8, T51, T52, T53, T55, flattenA_in_ga(cons(T51, cons(T52, T53)), T55))
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → FLATTENA_IN_GA(cons(T51, cons(T52, T53)), T55)
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83), .(T81, T85)) → U3_GA(T81, T82, T83, T85, flattenA_in_ga(cons(T82, T83), T85))
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83), .(T81, T85)) → FLATTENA_IN_GA(cons(T82, T83), T85)
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99), T101) → U4_GA(T96, T97, T98, T99, T101, flattenA_in_ga(cons(T96, cons(T97, cons(T98, T99))), T101))
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99), T101) → FLATTENA_IN_GA(cons(T96, cons(T97, cons(T98, T99))), T101)
The TRS R consists of the following rules:
flattenA_in_ga(atom(T4), .(T4, [])) → flattenA_out_ga(atom(T4), .(T4, []))
flattenA_in_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, []))) → flattenA_out_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, [])))
flattenA_in_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → U1_ga(T8, T29, T30, T32, flattenA_in_ga(T30, T32))
flattenA_in_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → U2_ga(T8, T51, T52, T53, T55, flattenA_in_ga(cons(T51, cons(T52, T53)), T55))
flattenA_in_ga(cons(cons(atom(T81), T82), T83), .(T81, T85)) → U3_ga(T81, T82, T83, T85, flattenA_in_ga(cons(T82, T83), T85))
flattenA_in_ga(cons(cons(cons(T96, T97), T98), T99), T101) → U4_ga(T96, T97, T98, T99, T101, flattenA_in_ga(cons(T96, cons(T97, cons(T98, T99))), T101))
U4_ga(T96, T97, T98, T99, T101, flattenA_out_ga(cons(T96, cons(T97, cons(T98, T99))), T101)) → flattenA_out_ga(cons(cons(cons(T96, T97), T98), T99), T101)
U3_ga(T81, T82, T83, T85, flattenA_out_ga(cons(T82, T83), T85)) → flattenA_out_ga(cons(cons(atom(T81), T82), T83), .(T81, T85))
U2_ga(T8, T51, T52, T53, T55, flattenA_out_ga(cons(T51, cons(T52, T53)), T55)) → flattenA_out_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55))
U1_ga(T8, T29, T30, T32, flattenA_out_ga(T30, T32)) → flattenA_out_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32)))
The argument filtering Pi contains the following mapping:
flattenA_in_ga(
x1,
x2) =
flattenA_in_ga(
x1)
atom(
x1) =
atom(
x1)
flattenA_out_ga(
x1,
x2) =
flattenA_out_ga(
x1,
x2)
cons(
x1,
x2) =
cons(
x1,
x2)
U1_ga(
x1,
x2,
x3,
x4,
x5) =
U1_ga(
x1,
x2,
x3,
x5)
U2_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U2_ga(
x1,
x2,
x3,
x4,
x6)
U3_ga(
x1,
x2,
x3,
x4,
x5) =
U3_ga(
x1,
x2,
x3,
x5)
U4_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U4_ga(
x1,
x2,
x3,
x4,
x6)
.(
x1,
x2) =
.(
x1,
x2)
FLATTENA_IN_GA(
x1,
x2) =
FLATTENA_IN_GA(
x1)
U1_GA(
x1,
x2,
x3,
x4,
x5) =
U1_GA(
x1,
x2,
x3,
x5)
U2_GA(
x1,
x2,
x3,
x4,
x5,
x6) =
U2_GA(
x1,
x2,
x3,
x4,
x6)
U3_GA(
x1,
x2,
x3,
x4,
x5) =
U3_GA(
x1,
x2,
x3,
x5)
U4_GA(
x1,
x2,
x3,
x4,
x5,
x6) =
U4_GA(
x1,
x2,
x3,
x4,
x6)
We have to consider all (P,R,Pi)-chains
(4) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → U1_GA(T8, T29, T30, T32, flattenA_in_ga(T30, T32))
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → FLATTENA_IN_GA(T30, T32)
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → U2_GA(T8, T51, T52, T53, T55, flattenA_in_ga(cons(T51, cons(T52, T53)), T55))
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → FLATTENA_IN_GA(cons(T51, cons(T52, T53)), T55)
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83), .(T81, T85)) → U3_GA(T81, T82, T83, T85, flattenA_in_ga(cons(T82, T83), T85))
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83), .(T81, T85)) → FLATTENA_IN_GA(cons(T82, T83), T85)
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99), T101) → U4_GA(T96, T97, T98, T99, T101, flattenA_in_ga(cons(T96, cons(T97, cons(T98, T99))), T101))
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99), T101) → FLATTENA_IN_GA(cons(T96, cons(T97, cons(T98, T99))), T101)
The TRS R consists of the following rules:
flattenA_in_ga(atom(T4), .(T4, [])) → flattenA_out_ga(atom(T4), .(T4, []))
flattenA_in_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, []))) → flattenA_out_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, [])))
flattenA_in_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → U1_ga(T8, T29, T30, T32, flattenA_in_ga(T30, T32))
flattenA_in_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → U2_ga(T8, T51, T52, T53, T55, flattenA_in_ga(cons(T51, cons(T52, T53)), T55))
flattenA_in_ga(cons(cons(atom(T81), T82), T83), .(T81, T85)) → U3_ga(T81, T82, T83, T85, flattenA_in_ga(cons(T82, T83), T85))
flattenA_in_ga(cons(cons(cons(T96, T97), T98), T99), T101) → U4_ga(T96, T97, T98, T99, T101, flattenA_in_ga(cons(T96, cons(T97, cons(T98, T99))), T101))
U4_ga(T96, T97, T98, T99, T101, flattenA_out_ga(cons(T96, cons(T97, cons(T98, T99))), T101)) → flattenA_out_ga(cons(cons(cons(T96, T97), T98), T99), T101)
U3_ga(T81, T82, T83, T85, flattenA_out_ga(cons(T82, T83), T85)) → flattenA_out_ga(cons(cons(atom(T81), T82), T83), .(T81, T85))
U2_ga(T8, T51, T52, T53, T55, flattenA_out_ga(cons(T51, cons(T52, T53)), T55)) → flattenA_out_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55))
U1_ga(T8, T29, T30, T32, flattenA_out_ga(T30, T32)) → flattenA_out_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32)))
The argument filtering Pi contains the following mapping:
flattenA_in_ga(
x1,
x2) =
flattenA_in_ga(
x1)
atom(
x1) =
atom(
x1)
flattenA_out_ga(
x1,
x2) =
flattenA_out_ga(
x1,
x2)
cons(
x1,
x2) =
cons(
x1,
x2)
U1_ga(
x1,
x2,
x3,
x4,
x5) =
U1_ga(
x1,
x2,
x3,
x5)
U2_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U2_ga(
x1,
x2,
x3,
x4,
x6)
U3_ga(
x1,
x2,
x3,
x4,
x5) =
U3_ga(
x1,
x2,
x3,
x5)
U4_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U4_ga(
x1,
x2,
x3,
x4,
x6)
.(
x1,
x2) =
.(
x1,
x2)
FLATTENA_IN_GA(
x1,
x2) =
FLATTENA_IN_GA(
x1)
U1_GA(
x1,
x2,
x3,
x4,
x5) =
U1_GA(
x1,
x2,
x3,
x5)
U2_GA(
x1,
x2,
x3,
x4,
x5,
x6) =
U2_GA(
x1,
x2,
x3,
x4,
x6)
U3_GA(
x1,
x2,
x3,
x4,
x5) =
U3_GA(
x1,
x2,
x3,
x5)
U4_GA(
x1,
x2,
x3,
x4,
x5,
x6) =
U4_GA(
x1,
x2,
x3,
x4,
x6)
We have to consider all (P,R,Pi)-chains
(5) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 4 less nodes.
(6) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → FLATTENA_IN_GA(cons(T51, cons(T52, T53)), T55)
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → FLATTENA_IN_GA(T30, T32)
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83), .(T81, T85)) → FLATTENA_IN_GA(cons(T82, T83), T85)
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99), T101) → FLATTENA_IN_GA(cons(T96, cons(T97, cons(T98, T99))), T101)
The TRS R consists of the following rules:
flattenA_in_ga(atom(T4), .(T4, [])) → flattenA_out_ga(atom(T4), .(T4, []))
flattenA_in_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, []))) → flattenA_out_ga(cons(atom(T8), atom(T16)), .(T8, .(T16, [])))
flattenA_in_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → U1_ga(T8, T29, T30, T32, flattenA_in_ga(T30, T32))
flattenA_in_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → U2_ga(T8, T51, T52, T53, T55, flattenA_in_ga(cons(T51, cons(T52, T53)), T55))
flattenA_in_ga(cons(cons(atom(T81), T82), T83), .(T81, T85)) → U3_ga(T81, T82, T83, T85, flattenA_in_ga(cons(T82, T83), T85))
flattenA_in_ga(cons(cons(cons(T96, T97), T98), T99), T101) → U4_ga(T96, T97, T98, T99, T101, flattenA_in_ga(cons(T96, cons(T97, cons(T98, T99))), T101))
U4_ga(T96, T97, T98, T99, T101, flattenA_out_ga(cons(T96, cons(T97, cons(T98, T99))), T101)) → flattenA_out_ga(cons(cons(cons(T96, T97), T98), T99), T101)
U3_ga(T81, T82, T83, T85, flattenA_out_ga(cons(T82, T83), T85)) → flattenA_out_ga(cons(cons(atom(T81), T82), T83), .(T81, T85))
U2_ga(T8, T51, T52, T53, T55, flattenA_out_ga(cons(T51, cons(T52, T53)), T55)) → flattenA_out_ga(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55))
U1_ga(T8, T29, T30, T32, flattenA_out_ga(T30, T32)) → flattenA_out_ga(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32)))
The argument filtering Pi contains the following mapping:
flattenA_in_ga(
x1,
x2) =
flattenA_in_ga(
x1)
atom(
x1) =
atom(
x1)
flattenA_out_ga(
x1,
x2) =
flattenA_out_ga(
x1,
x2)
cons(
x1,
x2) =
cons(
x1,
x2)
U1_ga(
x1,
x2,
x3,
x4,
x5) =
U1_ga(
x1,
x2,
x3,
x5)
U2_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U2_ga(
x1,
x2,
x3,
x4,
x6)
U3_ga(
x1,
x2,
x3,
x4,
x5) =
U3_ga(
x1,
x2,
x3,
x5)
U4_ga(
x1,
x2,
x3,
x4,
x5,
x6) =
U4_ga(
x1,
x2,
x3,
x4,
x6)
.(
x1,
x2) =
.(
x1,
x2)
FLATTENA_IN_GA(
x1,
x2) =
FLATTENA_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(7) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(8) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53)), .(T8, T55)) → FLATTENA_IN_GA(cons(T51, cons(T52, T53)), T55)
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30)), .(T8, .(T29, T32))) → FLATTENA_IN_GA(T30, T32)
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83), .(T81, T85)) → FLATTENA_IN_GA(cons(T82, T83), T85)
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99), T101) → FLATTENA_IN_GA(cons(T96, cons(T97, cons(T98, T99))), T101)
R is empty.
The argument filtering Pi contains the following mapping:
atom(
x1) =
atom(
x1)
cons(
x1,
x2) =
cons(
x1,
x2)
.(
x1,
x2) =
.(
x1,
x2)
FLATTENA_IN_GA(
x1,
x2) =
FLATTENA_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(9) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(10) Obligation:
Q DP problem:
The TRS P consists of the following rules:
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53))) → FLATTENA_IN_GA(cons(T51, cons(T52, T53)))
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30))) → FLATTENA_IN_GA(T30)
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83)) → FLATTENA_IN_GA(cons(T82, T83))
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99)) → FLATTENA_IN_GA(cons(T96, cons(T97, cons(T98, T99))))
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(11) UsableRulesReductionPairsProof (EQUIVALENT transformation)
By using the usable rules with reduction pair processor [LPAR04] with a polynomial ordering [POLO], all dependency pairs and the corresponding usable rules [FROCOS05] can be oriented non-strictly. All non-usable rules are removed, and those dependency pairs and usable rules that have been oriented strictly or contain non-usable symbols in their left-hand side are removed as well.
The following dependency pairs can be deleted:
FLATTENA_IN_GA(cons(atom(T8), cons(cons(T51, T52), T53))) → FLATTENA_IN_GA(cons(T51, cons(T52, T53)))
FLATTENA_IN_GA(cons(atom(T8), cons(atom(T29), T30))) → FLATTENA_IN_GA(T30)
FLATTENA_IN_GA(cons(cons(atom(T81), T82), T83)) → FLATTENA_IN_GA(cons(T82, T83))
No rules are removed from R.
Used ordering: POLO with Polynomial interpretation [POLO]:
POL(FLATTENA_IN_GA(x1)) = 2·x1
POL(atom(x1)) = x1
POL(cons(x1, x2)) = x1 + x2
(12) Obligation:
Q DP problem:
The TRS P consists of the following rules:
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99)) → FLATTENA_IN_GA(cons(T96, cons(T97, cons(T98, T99))))
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(13) MRRProof (EQUIVALENT transformation)
By using the rule removal processor [LPAR04] with the following ordering, at least one Dependency Pair or term rewrite system rule of this QDP problem can be strictly oriented.
Strictly oriented dependency pairs:
FLATTENA_IN_GA(cons(cons(cons(T96, T97), T98), T99)) → FLATTENA_IN_GA(cons(T96, cons(T97, cons(T98, T99))))
Used ordering: Knuth-Bendix order [KBO] with precedence:
cons2 > FLATTENAINGA1
and weight map:
FLATTENA_IN_GA_1=1
cons_2=0
The variable weight is 1
(14) Obligation:
Q DP problem:
P is empty.
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(15) PisEmptyProof (EQUIVALENT transformation)
The TRS P is empty. Hence, there is no (P,Q,R) chain.
(16) YES