(0) Obligation:
Clauses:
tree_member(X, tree(X, X1, X2)).
tree_member(X, tree(X3, Left, X4)) :- tree_member(X, Left).
tree_member(X, tree(X5, X6, Right)) :- tree_member(X, Right).
Query: tree_member(a,g)
(1) PrologToTRSTransformerProof (SOUND transformation)
Transformed Prolog program to TRS.
(2) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
f1_in(tree(T15, T16, T17)) → f1_out1(T15)
f1_in(tree(T35, T36, T37)) → U1(f1_in(T36), tree(T35, T36, T37))
U1(f1_out1(T38), tree(T35, T36, T37)) → f1_out1(T38)
f1_in(tree(T54, T55, T56)) → U2(f1_in(T56), tree(T54, T55, T56))
U2(f1_out1(T57), tree(T54, T55, T56)) → f1_out1(T57)
Q is empty.
(3) QTRSRRRProof (EQUIVALENT transformation)
Used ordering:
Polynomial interpretation [POLO]:
POL(U1(x1, x2)) = 2 + x1 + x2
POL(U2(x1, x2)) = 1 + x1 + x2
POL(f1_in(x1)) = 2·x1
POL(f1_out1(x1)) = 2·x1
POL(tree(x1, x2, x3)) = 2 + 2·x1 + 2·x2 + 2·x3
With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly:
f1_in(tree(T15, T16, T17)) → f1_out1(T15)
U1(f1_out1(T38), tree(T35, T36, T37)) → f1_out1(T38)
f1_in(tree(T54, T55, T56)) → U2(f1_in(T56), tree(T54, T55, T56))
U2(f1_out1(T57), tree(T54, T55, T56)) → f1_out1(T57)
(4) Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:
f1_in(tree(T35, T36, T37)) → U1(f1_in(T36), tree(T35, T36, T37))
Q is empty.
(5) QTRSRRRProof (EQUIVALENT transformation)
Used ordering:
Polynomial interpretation [POLO]:
POL(U1(x1, x2)) = 1 + x1 + x2
POL(f1_in(x1)) = 2·x1
POL(tree(x1, x2, x3)) = 2 + x1 + 2·x2 + x3
With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly:
f1_in(tree(T35, T36, T37)) → U1(f1_in(T36), tree(T35, T36, T37))
(6) Obligation:
Q restricted rewrite system:
R is empty.
Q is empty.
(7) RisEmptyProof (EQUIVALENT transformation)
The TRS R is empty. Hence, termination is trivially proven.
(8) YES