(0) Obligation:
Clauses:
fold(X, [], Z) :- ','(!, eq(X, Z)).
fold(X, Y, Z) :- ','(head(Y, H), ','(tail(Y, T), ','(myop(X, H, V), fold(V, T, Z)))).
myop(a, b, a).
head([], X1).
head(.(H, X2), H).
tail([], []).
tail(.(X3, T), T).
eq(X, X).
Query: fold(g,g,a)
(1) PrologToPrologProblemTransformerProof (SOUND transformation)
Built Prolog problem from termination graph ICLP10.
(2) Obligation:
Clauses:
foldA([], a).
foldA(.(b, T62), T47) :- foldA(T62, T47).
foldB(T11, [], T11).
foldB(a, .(b, T32), T18) :- foldA(T32, T18).
Query: foldB(g,g,a)
(3) PrologToPiTRSProof (SOUND transformation)
We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes:
foldB_in: (b,b,f)
foldA_in: (b,f)
Transforming
Prolog into the following
Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
foldB_in_gga(T11, [], T11) → foldB_out_gga(T11, [], T11)
foldB_in_gga(a, .(b, T32), T18) → U2_gga(T32, T18, foldA_in_ga(T32, T18))
foldA_in_ga([], a) → foldA_out_ga([], a)
foldA_in_ga(.(b, T62), T47) → U1_ga(T62, T47, foldA_in_ga(T62, T47))
U1_ga(T62, T47, foldA_out_ga(T62, T47)) → foldA_out_ga(.(b, T62), T47)
U2_gga(T32, T18, foldA_out_ga(T32, T18)) → foldB_out_gga(a, .(b, T32), T18)
The argument filtering Pi contains the following mapping:
foldB_in_gga(
x1,
x2,
x3) =
foldB_in_gga(
x1,
x2)
[] =
[]
foldB_out_gga(
x1,
x2,
x3) =
foldB_out_gga(
x3)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
U2_gga(
x1,
x2,
x3) =
U2_gga(
x3)
foldA_in_ga(
x1,
x2) =
foldA_in_ga(
x1)
foldA_out_ga(
x1,
x2) =
foldA_out_ga(
x2)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
(4) Obligation:
Pi-finite rewrite system:
The TRS R consists of the following rules:
foldB_in_gga(T11, [], T11) → foldB_out_gga(T11, [], T11)
foldB_in_gga(a, .(b, T32), T18) → U2_gga(T32, T18, foldA_in_ga(T32, T18))
foldA_in_ga([], a) → foldA_out_ga([], a)
foldA_in_ga(.(b, T62), T47) → U1_ga(T62, T47, foldA_in_ga(T62, T47))
U1_ga(T62, T47, foldA_out_ga(T62, T47)) → foldA_out_ga(.(b, T62), T47)
U2_gga(T32, T18, foldA_out_ga(T32, T18)) → foldB_out_gga(a, .(b, T32), T18)
The argument filtering Pi contains the following mapping:
foldB_in_gga(
x1,
x2,
x3) =
foldB_in_gga(
x1,
x2)
[] =
[]
foldB_out_gga(
x1,
x2,
x3) =
foldB_out_gga(
x3)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
U2_gga(
x1,
x2,
x3) =
U2_gga(
x3)
foldA_in_ga(
x1,
x2) =
foldA_in_ga(
x1)
foldA_out_ga(
x1,
x2) =
foldA_out_ga(
x2)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
(5) DependencyPairsProof (EQUIVALENT transformation)
Using Dependency Pairs [AG00,LOPSTR] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
FOLDB_IN_GGA(a, .(b, T32), T18) → U2_GGA(T32, T18, foldA_in_ga(T32, T18))
FOLDB_IN_GGA(a, .(b, T32), T18) → FOLDA_IN_GA(T32, T18)
FOLDA_IN_GA(.(b, T62), T47) → U1_GA(T62, T47, foldA_in_ga(T62, T47))
FOLDA_IN_GA(.(b, T62), T47) → FOLDA_IN_GA(T62, T47)
The TRS R consists of the following rules:
foldB_in_gga(T11, [], T11) → foldB_out_gga(T11, [], T11)
foldB_in_gga(a, .(b, T32), T18) → U2_gga(T32, T18, foldA_in_ga(T32, T18))
foldA_in_ga([], a) → foldA_out_ga([], a)
foldA_in_ga(.(b, T62), T47) → U1_ga(T62, T47, foldA_in_ga(T62, T47))
U1_ga(T62, T47, foldA_out_ga(T62, T47)) → foldA_out_ga(.(b, T62), T47)
U2_gga(T32, T18, foldA_out_ga(T32, T18)) → foldB_out_gga(a, .(b, T32), T18)
The argument filtering Pi contains the following mapping:
foldB_in_gga(
x1,
x2,
x3) =
foldB_in_gga(
x1,
x2)
[] =
[]
foldB_out_gga(
x1,
x2,
x3) =
foldB_out_gga(
x3)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
U2_gga(
x1,
x2,
x3) =
U2_gga(
x3)
foldA_in_ga(
x1,
x2) =
foldA_in_ga(
x1)
foldA_out_ga(
x1,
x2) =
foldA_out_ga(
x2)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
FOLDB_IN_GGA(
x1,
x2,
x3) =
FOLDB_IN_GGA(
x1,
x2)
U2_GGA(
x1,
x2,
x3) =
U2_GGA(
x3)
FOLDA_IN_GA(
x1,
x2) =
FOLDA_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x3)
We have to consider all (P,R,Pi)-chains
(6) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
FOLDB_IN_GGA(a, .(b, T32), T18) → U2_GGA(T32, T18, foldA_in_ga(T32, T18))
FOLDB_IN_GGA(a, .(b, T32), T18) → FOLDA_IN_GA(T32, T18)
FOLDA_IN_GA(.(b, T62), T47) → U1_GA(T62, T47, foldA_in_ga(T62, T47))
FOLDA_IN_GA(.(b, T62), T47) → FOLDA_IN_GA(T62, T47)
The TRS R consists of the following rules:
foldB_in_gga(T11, [], T11) → foldB_out_gga(T11, [], T11)
foldB_in_gga(a, .(b, T32), T18) → U2_gga(T32, T18, foldA_in_ga(T32, T18))
foldA_in_ga([], a) → foldA_out_ga([], a)
foldA_in_ga(.(b, T62), T47) → U1_ga(T62, T47, foldA_in_ga(T62, T47))
U1_ga(T62, T47, foldA_out_ga(T62, T47)) → foldA_out_ga(.(b, T62), T47)
U2_gga(T32, T18, foldA_out_ga(T32, T18)) → foldB_out_gga(a, .(b, T32), T18)
The argument filtering Pi contains the following mapping:
foldB_in_gga(
x1,
x2,
x3) =
foldB_in_gga(
x1,
x2)
[] =
[]
foldB_out_gga(
x1,
x2,
x3) =
foldB_out_gga(
x3)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
U2_gga(
x1,
x2,
x3) =
U2_gga(
x3)
foldA_in_ga(
x1,
x2) =
foldA_in_ga(
x1)
foldA_out_ga(
x1,
x2) =
foldA_out_ga(
x2)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
FOLDB_IN_GGA(
x1,
x2,
x3) =
FOLDB_IN_GGA(
x1,
x2)
U2_GGA(
x1,
x2,
x3) =
U2_GGA(
x3)
FOLDA_IN_GA(
x1,
x2) =
FOLDA_IN_GA(
x1)
U1_GA(
x1,
x2,
x3) =
U1_GA(
x3)
We have to consider all (P,R,Pi)-chains
(7) DependencyGraphProof (EQUIVALENT transformation)
The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 3 less nodes.
(8) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
FOLDA_IN_GA(.(b, T62), T47) → FOLDA_IN_GA(T62, T47)
The TRS R consists of the following rules:
foldB_in_gga(T11, [], T11) → foldB_out_gga(T11, [], T11)
foldB_in_gga(a, .(b, T32), T18) → U2_gga(T32, T18, foldA_in_ga(T32, T18))
foldA_in_ga([], a) → foldA_out_ga([], a)
foldA_in_ga(.(b, T62), T47) → U1_ga(T62, T47, foldA_in_ga(T62, T47))
U1_ga(T62, T47, foldA_out_ga(T62, T47)) → foldA_out_ga(.(b, T62), T47)
U2_gga(T32, T18, foldA_out_ga(T32, T18)) → foldB_out_gga(a, .(b, T32), T18)
The argument filtering Pi contains the following mapping:
foldB_in_gga(
x1,
x2,
x3) =
foldB_in_gga(
x1,
x2)
[] =
[]
foldB_out_gga(
x1,
x2,
x3) =
foldB_out_gga(
x3)
a =
a
.(
x1,
x2) =
.(
x1,
x2)
b =
b
U2_gga(
x1,
x2,
x3) =
U2_gga(
x3)
foldA_in_ga(
x1,
x2) =
foldA_in_ga(
x1)
foldA_out_ga(
x1,
x2) =
foldA_out_ga(
x2)
U1_ga(
x1,
x2,
x3) =
U1_ga(
x3)
FOLDA_IN_GA(
x1,
x2) =
FOLDA_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(9) UsableRulesProof (EQUIVALENT transformation)
For (infinitary) constructor rewriting [LOPSTR] we can delete all non-usable rules from R.
(10) Obligation:
Pi DP problem:
The TRS P consists of the following rules:
FOLDA_IN_GA(.(b, T62), T47) → FOLDA_IN_GA(T62, T47)
R is empty.
The argument filtering Pi contains the following mapping:
.(
x1,
x2) =
.(
x1,
x2)
b =
b
FOLDA_IN_GA(
x1,
x2) =
FOLDA_IN_GA(
x1)
We have to consider all (P,R,Pi)-chains
(11) PiDPToQDPProof (SOUND transformation)
Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.
(12) Obligation:
Q DP problem:
The TRS P consists of the following rules:
FOLDA_IN_GA(.(b, T62)) → FOLDA_IN_GA(T62)
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
(13) QDPSizeChangeProof (EQUIVALENT transformation)
By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.
From the DPs we obtained the following set of size-change graphs:
- FOLDA_IN_GA(.(b, T62)) → FOLDA_IN_GA(T62)
The graph contains the following edges 1 > 1
(14) YES