(0) Obligation:
Clauses:
add(X, 0, X).
add(X, Y, s(Z)) :- ','(\+(isZero(Y)), ','(p(Y, P), add(X, P, Z))).
p(0, 0).
p(s(X), X).
isZero(0).
Query: add(a,g,a)
(1) PrologToCdtProblemTransformerProof (UPPER BOUND (ID) transformation)
Built complexity over-approximating cdt problems from derivation graph.
(2) Obligation:
Complexity Dependency Tuples Problem
Rules:
f1_in(0) → f1_out1
f1_in(s(z0)) → U1(f1_in(z0), s(z0))
U1(f1_out1, s(z0)) → f1_out1
Tuples:
F1_IN(s(z0)) → c1(U1'(f1_in(z0), s(z0)), F1_IN(z0))
S tuples:
F1_IN(s(z0)) → c1(U1'(f1_in(z0), s(z0)), F1_IN(z0))
K tuples:none
Defined Rule Symbols:
f1_in, U1
Defined Pair Symbols:
F1_IN
Compound Symbols:
c1
(3) CdtGraphRemoveTrailingTuplepartsProof (BOTH BOUNDS(ID, ID) transformation)
Removed 1 trailing tuple parts
(4) Obligation:
Complexity Dependency Tuples Problem
Rules:
f1_in(0) → f1_out1
f1_in(s(z0)) → U1(f1_in(z0), s(z0))
U1(f1_out1, s(z0)) → f1_out1
Tuples:
F1_IN(s(z0)) → c1(F1_IN(z0))
S tuples:
F1_IN(s(z0)) → c1(F1_IN(z0))
K tuples:none
Defined Rule Symbols:
f1_in, U1
Defined Pair Symbols:
F1_IN
Compound Symbols:
c1
(5) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)
Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.
F1_IN(s(z0)) → c1(F1_IN(z0))
We considered the (Usable) Rules:none
And the Tuples:
F1_IN(s(z0)) → c1(F1_IN(z0))
The order we found is given by the following interpretation:
Polynomial interpretation :
POL(F1_IN(x1)) = x1
POL(c1(x1)) = x1
POL(s(x1)) = [1] + x1
(6) Obligation:
Complexity Dependency Tuples Problem
Rules:
f1_in(0) → f1_out1
f1_in(s(z0)) → U1(f1_in(z0), s(z0))
U1(f1_out1, s(z0)) → f1_out1
Tuples:
F1_IN(s(z0)) → c1(F1_IN(z0))
S tuples:none
K tuples:
F1_IN(s(z0)) → c1(F1_IN(z0))
Defined Rule Symbols:
f1_in, U1
Defined Pair Symbols:
F1_IN
Compound Symbols:
c1
(7) SIsEmptyProof (EQUIVALENT transformation)
The set S is empty
(8) BOUNDS(O(1), O(1))
(9) PrologToCdtProblemTransformerProof (UPPER BOUND (ID) transformation)
Built complexity over-approximating cdt problems from derivation graph.
(10) Obligation:
Complexity Dependency Tuples Problem
Rules:
f2_in(0) → f2_out1
f2_in(s(z0)) → U1(f2_in(z0), s(z0))
U1(f2_out1, s(z0)) → f2_out1
Tuples:
F2_IN(s(z0)) → c1(U1'(f2_in(z0), s(z0)), F2_IN(z0))
S tuples:
F2_IN(s(z0)) → c1(U1'(f2_in(z0), s(z0)), F2_IN(z0))
K tuples:none
Defined Rule Symbols:
f2_in, U1
Defined Pair Symbols:
F2_IN
Compound Symbols:
c1
(11) CdtGraphRemoveTrailingTuplepartsProof (BOTH BOUNDS(ID, ID) transformation)
Removed 1 trailing tuple parts
(12) Obligation:
Complexity Dependency Tuples Problem
Rules:
f2_in(0) → f2_out1
f2_in(s(z0)) → U1(f2_in(z0), s(z0))
U1(f2_out1, s(z0)) → f2_out1
Tuples:
F2_IN(s(z0)) → c1(F2_IN(z0))
S tuples:
F2_IN(s(z0)) → c1(F2_IN(z0))
K tuples:none
Defined Rule Symbols:
f2_in, U1
Defined Pair Symbols:
F2_IN
Compound Symbols:
c1
(13) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)
Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.
F2_IN(s(z0)) → c1(F2_IN(z0))
We considered the (Usable) Rules:none
And the Tuples:
F2_IN(s(z0)) → c1(F2_IN(z0))
The order we found is given by the following interpretation:
Polynomial interpretation :
POL(F2_IN(x1)) = x1
POL(c1(x1)) = x1
POL(s(x1)) = [1] + x1
(14) Obligation:
Complexity Dependency Tuples Problem
Rules:
f2_in(0) → f2_out1
f2_in(s(z0)) → U1(f2_in(z0), s(z0))
U1(f2_out1, s(z0)) → f2_out1
Tuples:
F2_IN(s(z0)) → c1(F2_IN(z0))
S tuples:none
K tuples:
F2_IN(s(z0)) → c1(F2_IN(z0))
Defined Rule Symbols:
f2_in, U1
Defined Pair Symbols:
F2_IN
Compound Symbols:
c1