Termination of the given JBC could be proven:

0 JBC
↳1 JBC2FIG (⇐)
↳2 FIGraph
↳3 FIGtoITRSProof (⇐)
↳4 ITRS
↳5 ITRStoIDPProof (⇔)
↳6 IDP
↳7 UsableRulesProof (⇔)
↳8 IDP
↳9 IDPNonInfProof (⇐)
↳10 AND
    ↳11 IDP
        ↳12 IDependencyGraphProof (⇔)
        ↳13 TRUE
    ↳14 IDP
        ↳15 IDependencyGraphProof (⇔)
        ↳16 TRUE

(0) Obligation:

JBC Problem based on JBC Program:
No human-readable program information known.

Manifest-Version: 1.0 Created-By: 1.6.0_16 (Sun Microsystems Inc.) Main-Class: MinusBuiltIn

(1) JBC2FIG (SOUND transformation)

Constructed FIGraph.

(2) Obligation:

FIGraph based on JBC Program:
Graph of 165 nodes with 1 SCC.

(3) FIGtoITRSProof (SOUND transformation)

Transformed FIGraph to ITRS rules

(4) Obligation:

ITRS problem:

The following function symbols are pre-defined:
!=~Neq: (Integer, Integer) -> Boolean
*~Mul: (Integer, Integer) -> Integer
>=~Ge: (Integer, Integer) -> Boolean
-1~UnaryMinus: (Integer) -> Integer
|~Bwor: (Integer, Integer) -> Integer
/~Div: (Integer, Integer) -> Integer
=~Eq: (Integer, Integer) -> Boolean
~Bwxor: (Integer, Integer) -> Integer
||~Lor: (Boolean, Boolean) -> Boolean
!~Lnot: (Boolean) -> Boolean
<~Lt: (Integer, Integer) -> Boolean
-~Sub: (Integer, Integer) -> Integer
<=~Le: (Integer, Integer) -> Boolean
>~Gt: (Integer, Integer) -> Boolean
~~Bwnot: (Integer) -> Integer
%~Mod: (Integer, Integer) -> Integer
&~Bwand: (Integer, Integer) -> Integer
+~Add: (Integer, Integer) -> Integer
&&~Land: (Boolean, Boolean) -> Boolean

The TRS R consists of the following rules:
Load612(i12, i58, i59) → Cond_Load612(i58 >= 0 && i12 > i58, i12, i58, i59)
Cond_Load612(TRUE, i12, i58, i59) → Load612(i12, i58 + 1, i59 + 1)
The set Q consists of the following terms:
Load612(x0, x1, x2)
Cond_Load612(TRUE, x0, x1, x2)

(5) ITRStoIDPProof (EQUIVALENT transformation)

Added dependency pairs

(6) Obligation:

IDP problem:
The following function symbols are pre-defined:
!=~Neq: (Integer, Integer) -> Boolean
*~Mul: (Integer, Integer) -> Integer
>=~Ge: (Integer, Integer) -> Boolean
-1~UnaryMinus: (Integer) -> Integer
|~Bwor: (Integer, Integer) -> Integer
/~Div: (Integer, Integer) -> Integer
=~Eq: (Integer, Integer) -> Boolean
~Bwxor: (Integer, Integer) -> Integer
||~Lor: (Boolean, Boolean) -> Boolean
!~Lnot: (Boolean) -> Boolean
<~Lt: (Integer, Integer) -> Boolean
-~Sub: (Integer, Integer) -> Integer
<=~Le: (Integer, Integer) -> Boolean
>~Gt: (Integer, Integer) -> Boolean
~~Bwnot: (Integer) -> Integer
%~Mod: (Integer, Integer) -> Integer
&~Bwand: (Integer, Integer) -> Integer
+~Add: (Integer, Integer) -> Integer
&&~Land: (Boolean, Boolean) -> Boolean


The following domains are used:

Boolean, Integer


The ITRS R consists of the following rules:
Load612(i12, i58, i59) → Cond_Load612(i58 >= 0 && i12 > i58, i12, i58, i59)
Cond_Load612(TRUE, i12, i58, i59) → Load612(i12, i58 + 1, i59 + 1)

The integer pair graph contains the following rules and edges:
(0): LOAD612(i12[0], i58[0], i59[0]) → COND_LOAD612(i58[0] >= 0 && i12[0] > i58[0], i12[0], i58[0], i59[0])
(1): COND_LOAD612(TRUE, i12[1], i58[1], i59[1]) → LOAD612(i12[1], i58[1] + 1, i59[1] + 1)

(0) -> (1), if ((i12[0] →* i12[1])∧(i59[0] →* i59[1])∧(i58[0] →* i58[1])∧(i58[0] >= 0 && i12[0] > i58[0] →* TRUE))


(1) -> (0), if ((i59[1] + 1 →* i59[0])∧(i12[1] →* i12[0])∧(i58[1] + 1 →* i58[0]))



The set Q consists of the following terms:
Load612(x0, x1, x2)
Cond_Load612(TRUE, x0, x1, x2)

(7) UsableRulesProof (EQUIVALENT transformation)

As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.

(8) Obligation:

IDP problem:
The following function symbols are pre-defined:
!=~Neq: (Integer, Integer) -> Boolean
*~Mul: (Integer, Integer) -> Integer
>=~Ge: (Integer, Integer) -> Boolean
-1~UnaryMinus: (Integer) -> Integer
|~Bwor: (Integer, Integer) -> Integer
/~Div: (Integer, Integer) -> Integer
=~Eq: (Integer, Integer) -> Boolean
~Bwxor: (Integer, Integer) -> Integer
||~Lor: (Boolean, Boolean) -> Boolean
!~Lnot: (Boolean) -> Boolean
<~Lt: (Integer, Integer) -> Boolean
-~Sub: (Integer, Integer) -> Integer
<=~Le: (Integer, Integer) -> Boolean
>~Gt: (Integer, Integer) -> Boolean
~~Bwnot: (Integer) -> Integer
%~Mod: (Integer, Integer) -> Integer
&~Bwand: (Integer, Integer) -> Integer
+~Add: (Integer, Integer) -> Integer
&&~Land: (Boolean, Boolean) -> Boolean


The following domains are used:

Boolean, Integer


R is empty.

The integer pair graph contains the following rules and edges:
(0): LOAD612(i12[0], i58[0], i59[0]) → COND_LOAD612(i58[0] >= 0 && i12[0] > i58[0], i12[0], i58[0], i59[0])
(1): COND_LOAD612(TRUE, i12[1], i58[1], i59[1]) → LOAD612(i12[1], i58[1] + 1, i59[1] + 1)

(0) -> (1), if ((i12[0] →* i12[1])∧(i59[0] →* i59[1])∧(i58[0] →* i58[1])∧(i58[0] >= 0 && i12[0] > i58[0] →* TRUE))


(1) -> (0), if ((i59[1] + 1 →* i59[0])∧(i12[1] →* i12[0])∧(i58[1] + 1 →* i58[0]))



The set Q consists of the following terms:
Load612(x0, x1, x2)
Cond_Load612(TRUE, x0, x1, x2)

(9) IDPNonInfProof (SOUND transformation)

The constraints were generated the following way:
The DP Problem is simplified using the Induction Calculus [NONINF] with the following steps:
Note that final constraints are written in bold face.


For Pair LOAD612(i12, i58, i59) → COND_LOAD612(&&(>=(i58, 0), >(i12, i58)), i12, i58, i59) the following chains were created:
  • We consider the chain LOAD612(i12[0], i58[0], i59[0]) → COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0]), COND_LOAD612(TRUE, i12[1], i58[1], i59[1]) → LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1)) which results in the following constraint:

    (1)    (i12[0]=i12[1]∧i59[0]=i59[1]∧i58[0]=i58[1]∧&&(>=(i58[0], 0), >(i12[0], i58[0]))=TRUE ⇒ LOAD612(i12[0], i58[0], i59[0])≥NonInfC∧LOAD612(i12[0], i58[0], i59[0])≥COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])∧(UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥))



    We simplified constraint (1) using rules (IV), (IDP_BOOLEAN) which results in the following new constraint:

    (2)    (>=(i58[0], 0)=TRUE∧>(i12[0], i58[0])=TRUE ⇒ LOAD612(i12[0], i58[0], i59[0])≥NonInfC∧LOAD612(i12[0], i58[0], i59[0])≥COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])∧(UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥))



    We simplified constraint (2) using rule (POLY_CONSTRAINTS) which results in the following new constraint:

    (3)    (i58[0] ≥ 0∧i12[0] + [-1] + [-1]i58[0] ≥ 0 ⇒ (UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥)∧[(-1)bni_11 + (-1)Bound*bni_11] + [(-1)bni_11]i58[0] + [bni_11]i12[0] ≥ 0∧[(-1)bso_12] ≥ 0)



    We simplified constraint (3) using rule (IDP_POLY_SIMPLIFY) which results in the following new constraint:

    (4)    (i58[0] ≥ 0∧i12[0] + [-1] + [-1]i58[0] ≥ 0 ⇒ (UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥)∧[(-1)bni_11 + (-1)Bound*bni_11] + [(-1)bni_11]i58[0] + [bni_11]i12[0] ≥ 0∧[(-1)bso_12] ≥ 0)



    We simplified constraint (4) using rule (POLY_REMOVE_MIN_MAX) which results in the following new constraint:

    (5)    (i58[0] ≥ 0∧i12[0] + [-1] + [-1]i58[0] ≥ 0 ⇒ (UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥)∧[(-1)bni_11 + (-1)Bound*bni_11] + [(-1)bni_11]i58[0] + [bni_11]i12[0] ≥ 0∧[(-1)bso_12] ≥ 0)



    We simplified constraint (5) using rule (IDP_UNRESTRICTED_VARS) which results in the following new constraint:

    (6)    (i58[0] ≥ 0∧i12[0] + [-1] + [-1]i58[0] ≥ 0 ⇒ (UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥)∧0 = 0∧[(-1)bni_11 + (-1)Bound*bni_11] + [(-1)bni_11]i58[0] + [bni_11]i12[0] ≥ 0∧0 = 0∧[(-1)bso_12] ≥ 0)



    We simplified constraint (6) using rule (IDP_SMT_SPLIT) which results in the following new constraint:

    (7)    (i58[0] ≥ 0∧i12[0] ≥ 0 ⇒ (UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥)∧0 = 0∧[(-1)Bound*bni_11] + [bni_11]i12[0] ≥ 0∧0 = 0∧[(-1)bso_12] ≥ 0)







For Pair COND_LOAD612(TRUE, i12, i58, i59) → LOAD612(i12, +(i58, 1), +(i59, 1)) the following chains were created:
  • We consider the chain COND_LOAD612(TRUE, i12[1], i58[1], i59[1]) → LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1)) which results in the following constraint:

    (8)    (COND_LOAD612(TRUE, i12[1], i58[1], i59[1])≥NonInfC∧COND_LOAD612(TRUE, i12[1], i58[1], i59[1])≥LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))∧(UIncreasing(LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))), ≥))



    We simplified constraint (8) using rule (POLY_CONSTRAINTS) which results in the following new constraint:

    (9)    ((UIncreasing(LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))), ≥)∧[1 + (-1)bso_14] ≥ 0)



    We simplified constraint (9) using rule (IDP_POLY_SIMPLIFY) which results in the following new constraint:

    (10)    ((UIncreasing(LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))), ≥)∧[1 + (-1)bso_14] ≥ 0)



    We simplified constraint (10) using rule (POLY_REMOVE_MIN_MAX) which results in the following new constraint:

    (11)    ((UIncreasing(LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))), ≥)∧[1 + (-1)bso_14] ≥ 0)



    We simplified constraint (11) using rule (IDP_UNRESTRICTED_VARS) which results in the following new constraint:

    (12)    ((UIncreasing(LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))), ≥)∧0 = 0∧0 = 0∧0 = 0∧[1 + (-1)bso_14] ≥ 0)







To summarize, we get the following constraints P≥ for the following pairs.
  • LOAD612(i12, i58, i59) → COND_LOAD612(&&(>=(i58, 0), >(i12, i58)), i12, i58, i59)
    • (i58[0] ≥ 0∧i12[0] ≥ 0 ⇒ (UIncreasing(COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])), ≥)∧0 = 0∧[(-1)Bound*bni_11] + [bni_11]i12[0] ≥ 0∧0 = 0∧[(-1)bso_12] ≥ 0)

  • COND_LOAD612(TRUE, i12, i58, i59) → LOAD612(i12, +(i58, 1), +(i59, 1))
    • ((UIncreasing(LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))), ≥)∧0 = 0∧0 = 0∧0 = 0∧[1 + (-1)bso_14] ≥ 0)




The constraints for P> respective Pbound are constructed from P≥ where we just replace every occurence of "t ≥ s" in P≥ by "t > s" respective "t ≥ c". Here c stands for the fresh constant used for Pbound.
Using the following integer polynomial ordering the resulting constraints can be solved
Polynomial interpretation over integers[POLO]:

POL(TRUE) = 0   
POL(FALSE) = 0   
POL(LOAD612(x1, x2, x3)) = [-1] + [-1]x2 + x1   
POL(COND_LOAD612(x1, x2, x3, x4)) = [-1] + [-1]x3 + x2   
POL(&&(x1, x2)) = [-1]   
POL(>=(x1, x2)) = [-1]   
POL(0) = 0   
POL(>(x1, x2)) = [-1]   
POL(+(x1, x2)) = x1 + x2   
POL(1) = [1]   

The following pairs are in P>:

COND_LOAD612(TRUE, i12[1], i58[1], i59[1]) → LOAD612(i12[1], +(i58[1], 1), +(i59[1], 1))

The following pairs are in Pbound:

LOAD612(i12[0], i58[0], i59[0]) → COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])

The following pairs are in P≥:

LOAD612(i12[0], i58[0], i59[0]) → COND_LOAD612(&&(>=(i58[0], 0), >(i12[0], i58[0])), i12[0], i58[0], i59[0])

There are no usable rules.

(10) Complex Obligation (AND)

(11) Obligation:

IDP problem:
The following function symbols are pre-defined:
!=~Neq: (Integer, Integer) -> Boolean
*~Mul: (Integer, Integer) -> Integer
>=~Ge: (Integer, Integer) -> Boolean
-1~UnaryMinus: (Integer) -> Integer
|~Bwor: (Integer, Integer) -> Integer
/~Div: (Integer, Integer) -> Integer
=~Eq: (Integer, Integer) -> Boolean
~Bwxor: (Integer, Integer) -> Integer
||~Lor: (Boolean, Boolean) -> Boolean
!~Lnot: (Boolean) -> Boolean
<~Lt: (Integer, Integer) -> Boolean
-~Sub: (Integer, Integer) -> Integer
<=~Le: (Integer, Integer) -> Boolean
>~Gt: (Integer, Integer) -> Boolean
~~Bwnot: (Integer) -> Integer
%~Mod: (Integer, Integer) -> Integer
&~Bwand: (Integer, Integer) -> Integer
+~Add: (Integer, Integer) -> Integer
&&~Land: (Boolean, Boolean) -> Boolean


The following domains are used:

Boolean, Integer


R is empty.

The integer pair graph contains the following rules and edges:
(0): LOAD612(i12[0], i58[0], i59[0]) → COND_LOAD612(i58[0] >= 0 && i12[0] > i58[0], i12[0], i58[0], i59[0])


The set Q consists of the following terms:
Load612(x0, x1, x2)
Cond_Load612(TRUE, x0, x1, x2)

(12) IDependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node.

(13) TRUE

(14) Obligation:

IDP problem:
The following function symbols are pre-defined:
!=~Neq: (Integer, Integer) -> Boolean
*~Mul: (Integer, Integer) -> Integer
>=~Ge: (Integer, Integer) -> Boolean
-1~UnaryMinus: (Integer) -> Integer
|~Bwor: (Integer, Integer) -> Integer
/~Div: (Integer, Integer) -> Integer
=~Eq: (Integer, Integer) -> Boolean
~Bwxor: (Integer, Integer) -> Integer
||~Lor: (Boolean, Boolean) -> Boolean
!~Lnot: (Boolean) -> Boolean
<~Lt: (Integer, Integer) -> Boolean
-~Sub: (Integer, Integer) -> Integer
<=~Le: (Integer, Integer) -> Boolean
>~Gt: (Integer, Integer) -> Boolean
~~Bwnot: (Integer) -> Integer
%~Mod: (Integer, Integer) -> Integer
&~Bwand: (Integer, Integer) -> Integer
+~Add: (Integer, Integer) -> Integer
&&~Land: (Boolean, Boolean) -> Boolean


The following domains are used:

Integer


R is empty.

The integer pair graph contains the following rules and edges:
(1): COND_LOAD612(TRUE, i12[1], i58[1], i59[1]) → LOAD612(i12[1], i58[1] + 1, i59[1] + 1)


The set Q consists of the following terms:
Load612(x0, x1, x2)
Cond_Load612(TRUE, x0, x1, x2)

(15) IDependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node.

(16) TRUE