Term Rewriting System R:
[x, y]
f(f(x)) -> f(g(f(x), x))
f(f(x)) -> f(h(f(x), f(x)))
g(x, y) -> y
h(x, x) -> g(x, 0)

Termination of R to be shown.



   R
Dependency Pair Analysis



R contains the following Dependency Pairs:

F(f(x)) -> F(g(f(x), x))
F(f(x)) -> G(f(x), x)
F(f(x)) -> F(h(f(x), f(x)))
F(f(x)) -> H(f(x), f(x))
H(x, x) -> G(x, 0)

Furthermore, R contains one SCC.


   R
DPs
       →DP Problem 1
Argument Filtering and Ordering


Dependency Pairs:

F(f(x)) -> F(h(f(x), f(x)))
F(f(x)) -> F(g(f(x), x))


Rules:


f(f(x)) -> f(g(f(x), x))
f(f(x)) -> f(h(f(x), f(x)))
g(x, y) -> y
h(x, x) -> g(x, 0)





The following dependency pair can be strictly oriented:

F(f(x)) -> F(g(f(x), x))


The following rules can be oriented:

g(x, y) -> y
f(f(x)) -> f(g(f(x), x))
f(f(x)) -> f(h(f(x), f(x)))
h(x, x) -> g(x, 0)


Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
F > 0
h > 0
f > 0
g > 0

resulting in one new DP problem.
Used Argument Filtering System:
F(x1) -> F(x1)
f(x1) -> f(x1)
g(x1, x2) -> x2
h(x1, x2) -> x1


   R
DPs
       →DP Problem 1
AFS
           →DP Problem 2
Argument Filtering and Ordering


Dependency Pair:

F(f(x)) -> F(h(f(x), f(x)))


Rules:


f(f(x)) -> f(g(f(x), x))
f(f(x)) -> f(h(f(x), f(x)))
g(x, y) -> y
h(x, x) -> g(x, 0)





The following dependency pair can be strictly oriented:

F(f(x)) -> F(h(f(x), f(x)))


The following rules can be oriented:

h(x, x) -> g(x, 0)
f(f(x)) -> f(g(f(x), x))
f(f(x)) -> f(h(f(x), f(x)))
g(x, y) -> y


Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
f > {h, 0}

resulting in one new DP problem.
Used Argument Filtering System:
F(x1) -> F(x1)
f(x1) -> f(x1)
h(x1, x2) -> h
g(x1, x2) -> x2


   R
DPs
       →DP Problem 1
AFS
           →DP Problem 2
AFS
             ...
               →DP Problem 3
Dependency Graph


Dependency Pair:


Rules:


f(f(x)) -> f(g(f(x), x))
f(f(x)) -> f(h(f(x), f(x)))
g(x, y) -> y
h(x, x) -> g(x, 0)





Using the Dependency Graph resulted in no new DP problems.

Termination of R successfully shown.
Duration:
0:00 minutes